rotational equilibrium simulation assignment answer key

• For educators
• English (US)
• English (India)
• English (UK)
• Greek Alphabet

This problem has been solved!

You'll get a detailed solution from a subject matter expert that helps you learn core concepts.

Question: Lab 13: Torque and Rotational Equilibrium Objectives Determine the mass of the meter stick by the application of known torques to the meter stick ► Compare the total clockwise and the total anticlockwise torques when the system is in equilibrium → Determine the mass of an unknown object by using it along with known masses to produce rotational equilibrium. ►

5 The data given are the following:

m 1 = 0.15 k g : m 2 = 0.25 k g

d 0 = 0.09 m , d 1 = 0.3 m    and    d 2 = 0.115 m

Not the question you’re looking for?

Post any question and get expert help quickly.

• High School
• You don't have any recent items yet.
• You don't have any courses yet.
• You don't have any books yet.
• You don't have any Studylists yet.
• Information

Phet contribution 4212 7610

Unit 3: circular motion and gravitation, ap physics 1: algebra-based, birdville h s - north richland hills-tx.

Recommended for you

Students also viewed.

• Free fall motion - Kaka
• Ballistic Pendulum Lab Report
• Essay self reflection - ikd
• Bigler rot energy
• Classwork Angles+10-17
• Algebra 1 answer key ( leah)

Related documents

• Module 5 FRQ practice
• Systems of Inequalities
• Unit 5 Review - Math practice for people
• Kami Export - Systems of Inequalities
• Unit 2 Vectors SE Gizmo - make sure you do good!
• A2a2879e 7eac 439d 81f5 7827c3586c19

Preview text

Cp physics – mrs. carpinelli date_______, rotational equilibrium simulation assignment, directions: for this activity, you will be using the phet website, phet.colorado/sims/html/balancing-act/latest/balancing-act_en.html (linked on my, website). when you open it, select the “balance lab” tab and select “mass labels”, “rulers”,, “forces from objects” and “level” under the “show” box. your screen should look like this one:, notice the yellow arrow above the word “bricks” in the second box. click this arrow. you will, see other objects (like people and mystery packages) that you will use for various parts of this, activity. for now, we will use the bricks. also notice the “remove supports” button. we will, use this button frequently. click this button now. does anything happen, part a. rotational equilibrium conditions., select the 5 kg brick and place it 0 m from the center of rotation (called the fulcrum). place, another 5 kg brick at the opposite 0 m position. remove the supports. does the seesaw, move why/why not, put the supports back. now move one of the 5 kg bricks to the 0 m position. remove the, supports again. does the seesaw move why/why not, move the same 5 kg brick to the 1 m position. how does the position of the seesaw compare, to its position when the brick was at the 0 m position why is this the case, put the supports back in place and remove one of the 5 kg bricks. place the other at the 0 m, mark and then add a 10 kg brick to the 0 m mark on the other side. remove the supports., does the seesaw move why/why not, replace the 10 kg brick with a 20 kg brick. how is the motion of the seesaw affected why, does this happen, what does it mean to be in a state of rotational equilibrium, part b. simple rotational equilibrium., in this part of the activity, you will be placing objects at various positions to balance the seesaw., you will be told a starting mass (brick or person) and position and then will determine where a, second mass should be placed in order to balance it out. to do this, you will be required to do a, torque summation. the first one has been done as an example. check your answer by placing, the objects on the seesaw and removing the supports., τright = τleft, 20 1 m left 30 0 m left, (20)(9)(1) + (30), (9)(0) = (60)(9)x, 20 1 m left 60 2 m left 80, 80 1 m left 30 0 m right 60, 60 1 m left 80, part d. mystery packages., for this part, you will determine the masses of the mystery packages based on known objects, and distances., position (m), (60)(9)(0) = (x)(9)(1), if you are trying to balance a seesaw and you have a higher mass on the left, should the mass, on the right be placed at a greater distance or lower distance to balance it why.

• Multiple Choice

Topic : Unit 3: Circular Motion and Gravitation

Subject : ap physics 1: algebra-based.

• More from: Unit 3: Circular Motion and Gravitation 244   Documents Go to topic
• More from: AP Physics 1: Algebra-Based AP (Advanced Placement) 999+   Documents Go to course