*The balance after the third payment was $69,918.68. 10% of this amount is $6,991.87. **The balance after the fifth payment was $29,032.76. 10% of this amount is $2,903.28.
Step 2: Adjust for the “missing pennies” (noted in bold italics ) and total the interest.
0 | $0.00 | $118,000.00 | ||
1 | $18,000.00 | $2,278.41 | $15,721.59 | $102,278.41 |
2 | $18,000.00 | $86,253.25 | ||
3 | $24,991.87 | $62,926.81 | ||
4 | $18,000.00 | $1,215.02 | $16,784.98 | $46,141.83 |
5 | $20,903.28 | $890.93 | $20,012.35 | $26,129.48 |
6 | $18,000.00 | $8,634.01 | ||
7 | $8,800.72 | $166.71 | $8,634.01 | $0.00 |
Total |
From Question 18a, amount of interest paid was $9,391.27. Interest Saved = $9,391.27 − $8,695.87 = $695.40.
Step 1 : Find the initial payment.
[latex]N = (\text{Number of Years}) \times (\text{Payments Per Year})[/latex] [latex]N = 30 \times 12 = 360 \;\text{payments}[/latex] [latex]I/Y = 6.49[/latex] [latex]P/Y = 12[/latex] [latex]C/Y = 2[/latex] [latex]FV = 0[/latex] [latex]PV = 628,\!200 − 100,\!000 = 528,\!200[/latex] [latex]CPT\; PMT =-\$3,\!305.288742[/latex]
Make sure to reinput PMT = -3,305.29 (Input as a negative value rounded to 2 decimal places).
Step 2: Use the AMORT function to find the BAL on the after the first term (payment 1-36).
2nd AMORT P1 = 1 P2 = 36 ↓ BAL = $508,947.54
2nd AMORT P1 = 1 P2 = 36 ↓ ↓ PRN = $19,252.46 INT = $99,737.98
[latex]N = (\text{Number of Years}) \times (\text{Payments Per Year})[/latex] [latex]N = 27 \times 12 = 324 \;\text{payments}[/latex] [latex]I/Y = 6.19[/latex] [latex]P/Y = 12[/latex] [latex]C/Y = 2[/latex] [latex]FV = 0[/latex] [latex]PV = 508,\!947.54[/latex] [latex]CPT\; PMT =-\$3,\!211.32429[/latex]
Make sure to reinput PMT = -3,211.32 (Input as a negative value rounded to 2 decimal places).
Use the AMORT function to find the BAL on the after the second term (payment 1-48).
2nd AMORT P1 = 1 P2 = 48 ↓ BAL = $475,372.69
[latex]N = (\text{Number of Years}) \times (\text{Payments Per Year})[/latex] [latex]N = 20 \times 12 = 240 \;\text{payments}[/latex] [latex]I/Y = 4.84[/latex] [latex]P/Y = 12[/latex] [latex]C/Y = 2[/latex] [latex]FV = 0[/latex] [latex]PV = 323,\!000[/latex] [latex]CPT\; PMT =-\$2,\!094.701842[/latex]
Make sure to reinput PMT = -2,094.70 (Input as a negative value rounded to 2 decimal places).
Step 2: Use the AMORT function to find the BAL on the after the first 18 months.
2nd AMORT P1 = 1 P2 = 18 ↓ BAL = $308,009.80
Step 3: Find New Balance after $20,000 top-up payment.
New Balance = $308,009.80 − $20,000 = $288,009.80. Reinput PV = $288,009.80.
Step 4: Use the AMORT function to find the BAL on the after the last 18 months of the first term.
2nd AMORT P1 = 1 P2 = 18 ↓ BAL = $270,417.34
Step 1: Find Original BAL paid without top-up payment (payments 1-36).
Reinput PV = $323,000
2nd AMORT P1 = 1 P2 = 36 ↓ BAL = $291,904.76
Step 2: Find Interest Difference.
[latex]\begin{align} \text{Interest Difference}&=\$291,\!904.76 − \$270,\!417.34 − \$20,\!000\\ &= \$1,\!487.42 \end{align}[/latex]
Step 1 : Find the initial payment for 10-year term.
[latex]N = (\text{Number of Years}) \times (\text{Payments Per Year})[/latex] [latex]N = 30 \times 12 = 360 \;\text{payments}[/latex] [latex]I/Y = 7.7[/latex] [latex]P/Y = 12[/latex] [latex]C/Y = 2[/latex] [latex]FV = 0[/latex] [latex]PV = 408,\!650[/latex] [latex]CPT\; PMT =-\$2,\!879.565159[/latex]
Make sure to reinput PMT = -2,879.57 (Input as a negative value rounded to 2 decimal places).
Step 2: Use the AMORT function to find the BAL on the after the 10-year term (payments 1-120).
2nd AMORT P1 = 1 P2 = 120 ↓ BAL = $355,303.81
Step 3 : Find the payment for 5-year term.
[latex]N = (\text{Number of Years}) \times (\text{Payments Per Year})[/latex] [latex]N = 20 \times 12 = 240 \;\text{payments}[/latex] [latex]I/Y = 5.69[/latex] [latex]P/Y = 12[/latex] [latex]C/Y = 2[/latex] [latex]FV = 0[/latex] [latex]PV = 355,\!303.81[/latex] [latex]CPT\; PMT =-\$2,\!468.979621[/latex]
Make sure to reinput PMT = -2,468.98 (Input as a negative value rounded to 2 decimal places).
Step 4: Use the AMORT function to find the BAL on the after the 5-year term (payments 1-120).
2nd AMORT P1 = 1 P2 = 60 ↓ BAL = $299,756.24
Step 5 : Find the payment for 3-year term with amortization period shortened by 5 years. Number of years remaining = 15 – 5 = 10.
[latex]N = (\text{Number of Years}) \times (\text{Payments Per Year})[/latex] [latex]N = 10 \times 12 = 120 \;\text{payments}[/latex] [latex]I/Y = 3.45[/latex] [latex]P/Y = 12[/latex] [latex]C/Y = 2[/latex] [latex]FV = 0[/latex] [latex]PV =299,\!756.24[/latex] [latex]CPT\; PMT =-\$2,\!953.710318[/latex]
Make sure to reinput PMT = -2,953.71 (Input as a negative value rounded to 2 decimal places).
Step 6: Use the AMORT function to find the BAL on the after the 3-year term (payments 1-36).
2nd AMORT P1 = 1 P2 = 36 ↓ BAL = $220,328.74
Start of 3rd term principal = $299,756.24. Remaining balance at end of 3rd term = $220,328.74.
[latex]\begin{align} \text{Total principal across all}\;18\;\text{years}&=\$408,\!650 - \$220,\!328.74\\ &= \$188,\!321.26 \end{align}[/latex]
[latex]\text{Total interest across all}\;18\;\text{years}[/latex] [latex]=(120 \times 2,\!879.57) + (60 \times 2,\!468.98) + (36 \times 2,\!953.71) - 188,\!321.26[/latex] [latex]= \$411,\!499.50[/latex]
Figure 13.1.2: Timeline: Deferral period from age 54 until age 65 at 6.25% compounded annually. Starting at age 55, 20 years end of month payments of PMT at 3.85% compounded annually. $75,000 at age 54 brought to age 65 as FV. At age 65 the FV becomes the PV for the stream of PMT’s brought back to age 65. [ Back to Figure 13.1.2 ]
Business Math: A Step-by-Step Handbook Abridged Copyright © 2022 by Sanja Krajisnik; Carol Leppinen; and Jelena Loncar-Vines is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International License , except where otherwise noted.
To succeed in life, you have to be good at maths as well as finance. Mathematical finance (a mix of both), also known as quantitative finance, is a field of applied maths, concerned with the mathematical modeling of financial markets. It is one of the rarest yet important skills to have. Take this test to test your knowledge about Financial Math and try to get better at it.
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Mr zwane invested an amount of r13.900 divided in two different schemes a and b at the simple interest rate of 14% p.a and 11% p.a respectively. if the total amount of simple interest earned in 2 years be r3508,what was the amount invested in scheme b , how much time will it take for an amount of rs. 900 to yield rs. 81 as interest at 4.5% per annum of simple interest, mr. thomas invested an amount of rs. 13,900 divided in two different schemes a and b at the simple interest rate of 14% p.a. and 11% p.a. respectively. if the total amount of simple interest earned in 2 years be rs. 3508, what was the amount invested in scheme b, arun took a loan of rs. 1400 with simple interest for as many years as the rate of interest. if he paid rs.686 as interest at the end of the loan period, what was the rate of interest, which of these is not a deduction from your pay each month.
Direct Debit
National Insurance
£190.25
£315.12
£255.45
£1584
£1122
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