case study questions on fractions and decimals class 7

Assertion and Reason Questions Class 7 Maths Chapter 2 Fractions and Decimals

19)  Assertion: A unit fraction is the reciprocal of positive integer.

d.) both assertion and reason are false.

b.) Both Assertion and Reason are correct and Reason is not the correct explanation for Assertion.

Ans: a.) Both Assertion and Reason are correct and Reason is the correct explanation for Assertion

a.) Both Assertion and Reason are correct and Reason is the correct explanation for Assertion

Reason: 21/27 + 5/27 = 26/27.

c.) assertion is true but the reason is false.

33) Assertion: 2/5 & 3/7 are the like fractions.

Ans: b) both assertion and reason are correct   but the reason is not correct explanation for Assertion

43)  Assertion: To multiply a decimal number by 10, we move the decimal point in the number to the right by as many places as many zeros are at the right of one.

56)  Assertion: Expanded form of 78.059 is 70 + 8+ 0 + 5/100 + 9/1000.

Reason (R): In order to compare two decimal numbers we first convert them to like decimals.

(83) Assertion (A): 7.3 × 0.3 = 2.19.

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Chapter 2 Class 7 Fractions and Decimals

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Updated from 2023-24 NCERT Book.

Get solutions of all questions of Chapter 2 Class 7 Fractions & Decimals free at teachoo. All NCERT exercise questions and examples have been solved with detailed explanation of each solution. Concepts have also been explained in the concept wise.

In this chapter, we will study

• What is a fraction
• What is proper , improper and mixed fraction
• What are equivalent fractions
• Comparing fractions
• Adding and Subtracting Fractions
• Then, we will learn how to Multiply Fractions and Mixed Fractions
• And how to divide Fractions
• And do some statement questions on multiplication and division of fractions
• What are Decimal Numbers
• Place value of Decimals
• Comparing Decimal Numbers
• Converting g → kg, mm → cm, mm → m, mm → km, cm → m, cm → km
• Addition and Subtraction of Decimal Numbers
• We will learn how to Multiply Decimal Numbers
• and How to divide Decimals
• And do some statement questions

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NCERT Solutions for Class 6, 7, 8, 9, 10, 11 and 12

Fractions and Decimals Class 7 Extra Questions Maths Chapter 2

June 11, 2019 by Sastry CBSE

Extra Questions for Class 7 Maths Chapter 2 Fractions and Decimals

Fractions and Decimals Class 7 Extra Questions Very Short Answer Type

Fractions and Decimals Class 7 Extra Questions Short Answer Type

Question 16. A picture hall has seats for 820 persons. At a recent film show, one usher guessed it was \(\frac { 3 }{ 4 }\) full, another that it was \(\frac { 2 }{ 3 }\) full. The ticket office reported 648 sales. Which usher (first or second) made the better guess? [NCERT Exemplar] Solution: Total number of seats = 820 Number of ticket sold = 648 For first usher = \(\frac { 3 }{ 4 }\) × 648 = 3 × 162 = 486 For second usher = \(\frac { 2 }{ 3 }\) × 648 = 2 × 216 = 432 Since 432 < 486 Hence, the first usher guessed better.

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NCERT Solutions Class 7 Maths Chapter 2 Fractions and Decimals

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• Chapter 2 Fractions And Decimals

NCERT Class 7 Chapter 2 Maths Fractions and Decimals - FREE PDF Download

Here are the NCERT solutions for fractions and decimals Class 7. In order to improve their exam scores, students can practice answering various kinds of questions linked to this chapter either online or by downloading these files. In previous lessons, students have learned how to add and subtract decimals as well as fractions. In this lesson, students will learn how to multiply and divide decimals, as well as fractions. These Class 7 Maths Chapter 2 Solutions, which include fractions and decimals, have been created by experts in the field to help students prepare for their exams.

Glance on Maths Chapter 2 Class 7 - Fractions and Decimals

Basic calculations like adding, subtracting, comparing, and ranking fractions are covered in this chapter.

We work on word problems, such as applying concepts like fractions to real-life scenarios.

We cover higher-order thinking questions that test your ability to evaluate and resolve issues with decimals and fractions.

Focus on concepts like adding, subtracting, multiplying, and dividing fractions, and confidently convert between fractions and decimals.

This article contains chapter notes, important questions, and exercise links for Chapter 2 Fractions and Decimals, which you can download  as PDFs.

There are five exercises (31 fully solved questions) in class 7th maths chapter 2 Fractions and Decimal.

Access Exercise Wise NCERT Solutions for Chapter 2 Maths Class 7

Exercises Under NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals

Exercise 2.1: multiplication of fractions.

Multiplying Fractions by Whole Numbers : Understanding how to multiply fractions by whole numbers.

Multiplying Two Fractions : Learning the method to multiply two fractions.

Multiplying Mixed Numbers : Converting mixed numbers to improper fractions and then multiplying them.

Exercise 2.2: Division of Fractions

Reciprocal of a Fraction : Introduction to the concept of reciprocals.

Dividing Fractions by Whole Numbers : Method to divide fractions by whole numbers using reciprocals.

Dividing a Fraction by Another Fraction : Understanding the steps to divide one fraction by another fraction.

Word Problems : Applying division of fractions to solve real-life problems.

Exercise 2.3: Multiplication of Decimal Numbers

This section in Maths Class 7 Chapter 2 covers the rules and methods for multiplying decimal numbers. It includes step-by-step instructions for aligning the decimal points and performing multiplication, followed by placing the decimal point in the product correctly. Practical examples and problems help reinforce the concept and provide practice in multiplying decimals in various contexts.

Exercise 2.4: Division of Decimal Numbers

This section focuses on dividing decimal numbers, explaining how to handle the decimal point in both the dividend and the divisor. It includes methods for converting the divisor into a whole number by multiplying both the dividend and the divisor by a power of ten. The section in Class 7 Fractions and Decimals provides numerous examples and exercises to practice the division of decimals, ensuring a clear understanding of the process.

Access NCERT Solutions for Class 7 Maths Chapter 2 – Fractions and Decimals

Exercise - 2.1.

1. Which of the drawings $(a)\,to\,(d)$ show:

(i). $\text{2 }\!\!\times\!\!\text{ }\frac{\text{1}}{\text{5}}$

Ans: corresponds to $\text{(d)}$  

Because,  $2\times \frac{1}{5}=\frac{1}{5}+\frac{1}{5}$                                                                

(ii). $\text{2 }\!\!\times\!\!\text{ }\frac{\text{1}}{\text{2}}$

Ans: corresponds to $\text{(b)}$

Because, $2\times \frac{1}{2}=\frac{1}{2}+\frac{1}{2}$

(iii). $\text{3 }\!\!\times\!\!\text{ }\frac{\text{2}}{\text{3}}$

Ans:   corresponds to $\text{(a)}$   

Because, $3\times \frac{2}{3}=\frac{2}{3}+\frac{2}{3}+\frac{2}{3}$ 

(iv). $\text{3 }\!\!\times\!\!\text{ }\frac{\text{1}}{\text{4}}$

Ans: Corresponds to $\text{(c)}$

Because, $3\times \frac{1}{4}=\frac{1}{4}+\frac{1}{4}+\frac{1}{4}$ 

2. Some pictures $\left( \text{a} \right)\,\text{to}\,\left( \text{c} \right)$ are given below. Tell which of them show: 

(i). $\text{3 }\!\!\times\!\!\text{ }\frac{\text{1}}{\text{5}}\text{=}\frac{\text{3}}{\text{5}}$

Ans: Corresponds to $\text{(c)}$                    

Because, $3\times \frac{1}{5}=\frac{1}{5}+\frac{1}{5}+\frac{1}{5}$  

(ii). $\text{2 }\!\!\times\!\!\text{ }\frac{\text{1}}{\text{3}}\text{=}\frac{\text{2}}{\text{3}}$ 

Ans: Corresponds to $\text{(a)}$                   

Because, $2\times \frac{1}{3}=\frac{1}{3}+\frac{1}{3}$ 

(iii). $\text{3 }\!\!\times\!\!\text{ }\frac{\text{3}}{\text{4}}\text{=2}\frac{\text{1}}{\text{4}}$

Ans: Corresponds to $\text{(b)}$                  

Because, $3\times \frac{3}{4}=\frac{3}{4}+\frac{3}{4}+\frac{3}{4}$      

3. Multiply and reduce to lowest form and convert into a mixed fraction:

(i). $\text{7 }\!\!\times\!\!\text{ }\frac{\text{3}}{\text{5}}$        

Ans: Multiplying and reducing to lowest form and converting into a mixed fraction,   

$7\times \frac{3}{5}=\frac{7\times 3}{5}=\frac{21}{5}=4\frac{1}{5}$

(ii). $\text{4 }\!\!\times\!\!\text{ }\frac{\text{1}}{\text{3}}$ 

Ans: Multiplying and reducing to lowest form and converting into a mixed fraction,

$4\times \frac{1}{3}=\frac{4\times 1}{3}=\frac{4}{3}=1\frac{1}{3}$ 

(iii). $\text{2 }\!\!\times\!\!\text{ }\frac{\text{6}}{\text{7}}$    

$2\times \frac{6}{7}=\frac{2\times 6}{7}=\frac{12}{7}=1\frac{5}{7}$       

(iv). $\text{5 }\!\!\times\!\!\text{ }\frac{\text{2}}{\text{9}}$ 

$5\times \frac{2}{9}=\frac{5\times 2}{9}=\frac{10}{9}=1\frac{1}{9}$

(v). $\frac{\text{2}}{\text{3}}\text{ }\!\!\times\!\!\text{ 4}$     

$\frac{2}{3}\times 4=\frac{2\times 4}{3}=\frac{8}{3}=2\frac{2}{3}$   

(vi)  $\frac{\text{5}}{\text{2}}\text{ }\!\!\times\!\!\text{ 6}$    

$\frac{5}{2}\times 6=5\times 3=15$

(vii)   $\text{11 }\!\!\times\!\!\text{ }\frac{\text{4}}{\text{7}}$    

$11\times \frac{4}{7}=\frac{11\times 4}{7}=\frac{44}{7}=6\frac{2}{7}$ 

(viii)  $\text{20 }\!\!\times\!\!\text{ }\frac{\text{4}}{\text{5}}$ 

$20\times \frac{4}{5}=4\times 4=16$

(ix)  $\text{13 }\!\!\times\!\!\text{ }\frac{\text{1}}{\text{3}}$      

Ans: Multiplying and reducing to lowest form and converting into a mixed fraction,    

$13\times \frac{1}{3}=\frac{13\times 1}{3}=\frac{13}{3}=4\frac{1}{3}$ 

(x)  $\text{15 }\!\!\times\!\!\text{ }\frac{\text{3}}{\text{5}}$ 

Ans: Multiplying and reducing to lowest form and converting into a mixed fraction,   

$15\times \frac{3}{5}=3\times 3=9$                

4. Shade: 

(i). $\frac{\text{1}}{\text{2}}$ of the circles in box

Ans: Half of the circles in the box are,

$\frac{\text{1}}{\text{2}}\,\text{of}\,\text{12}\,\text{circles=}\frac{\text{1}}{\text{2}}\text{ }\!\!\times\!\!\text{ 12=6}\,\text{circles}$

(iii). $\frac{\text{2}}{\text{3}}$ of the triangles in box 

Ans: Two-third of the triangles in the box are, $\frac{\text{2}}{\text{3}}\,\text{of}\,\text{9}\,\text{triangles=}\frac{\text{2}}{\text{3}}\text{ }\!\!\times\!\!\text{ 9=2 }\!\!\times\!\!\text{ 3=6}\,\text{triangles}$

(iv). $\frac{\text{3}}{\text{5}}$ of the squares inbox

Ans: Three-fifth of the squares in the box are,

$\frac{\text{3}}{\text{5}}\,\text{of}\,\text{15}\,\text{squares=}\frac{\text{3}}{\text{5}}\text{ }\!\!\times\!\!\text{ 15=3 }\!\!\times\!\!\text{ 3=9}\,\text{squares}$

(a).$\frac{\text{1}}{\text{2}}\,\text{of}\,\text{(i)}\,\text{24}\,\text{(ii)}\,\text{46}$

(i) Calculating the value,

$\frac{\text{1}}{\text{2}}\,\text{of}\,\text{24=12}$

(ii) Calculating the value,

$\frac{\text{1}}{\text{2}}\,\text{of}\,\text{46=23}$ 

(b). $\frac{\text{2}}{\text{3}}\,\text{of}\,\text{(i)}\,\text{18}\,\text{(ii)}\,\text{27}$ 

(i) Calculating the value, $\frac{\text{2}}{\text{3}}\,\text{of}\,\text{18=}\frac{\text{2}}{\text{3}}\text{ }\!\!\times\!\!\text{ 18=2 }\!\!\times\!\!\text{ 6=12}$

(ii) Calculating the value, $\frac{\text{2}}{\text{3}}\,\text{of}\,\text{27=}\frac{\text{2}}{\text{3}}\text{ }\!\!\times\!\!\text{ 27=2 }\!\!\times\!\!\text{ 9=18}$ 

(c)  $\frac{\text{3}}{\text{4}}\,\text{of}\,\text{(i)}\,\text{16}\,\text{(ii)}\,\text{36}$          

$\frac{\text{3}}{\text{4}}\,\text{of}\,\text{16=}\frac{\text{3}}{\text{4}}\text{ }\!\!\times\!\!\text{ 16=3 }\!\!\times\!\!\text{ 4=12}$

$\frac{\text{3}}{\text{4}}\,\text{of}\,36\text{=}\frac{\text{3}}{\text{4}}\text{ }\!\!\times\!\!\text{ 36=3 }\!\!\times\!\!\text{ 9=27}$  

(d)  $\frac{\text{4}}{\text{5}}\,\text{of}\,\text{(i)}\,\text{20}\,\text{(ii)}\,\text{35}$ 

$\frac{\text{4}}{\text{5}}\,\text{of}\,20\text{=}\frac{\text{4}}{\text{5}}\text{ }\!\!\times\!\!\text{ 20=4 }\!\!\times\!\!\text{ 4=16}$

$\frac{\text{4}}{\text{5}}\,\text{of}\,35\text{=}\frac{\text{4}}{\text{5}}\text{ }\!\!\times\!\!\text{ 35=4 }\!\!\times\!\!\text{ 7=28}$ 

6.   Multiply and express as a mixed fraction:

(a)  $\text{3 }\!\!\times\!\!\text{ 5}\frac{\text{1}}{\text{5}}$       

Ans: Multiplying and expressing the term as mixed fraction,

$3\times 5\frac{1}{5}=3\times \frac{26}{5}=\frac{3\times 26}{5}=\frac{78}{5}=15\frac{3}{5}$

(b) $\text{5 }\!\!\times\!\!\text{ 6}\frac{\text{3}}{\text{4}}$          

$5\times 6\frac{3}{4}=5\times \frac{27}{4}=\frac{5\times 27}{4}=\frac{135}{4}=33\frac{3}{4}$ 

(c) $\text{7 }\!\!\times\!\!\text{ 2}\frac{\text{1}}{\text{4}}$

$7\times 2\frac{1}{4}=7\times \frac{9}{4}=\frac{7\times 9}{4}=\frac{63}{4}=15\frac{3}{4}$        

(d)  $\text{4 }\!\!\times\!\!\text{ 6}\frac{\text{1}}{\text{3}}$ 

$4\times 6\frac{1}{3}=4\times \frac{19}{3}=\frac{4\times 19}{3}=\frac{76}{3}=25\frac{1}{3}$ 

(e)  $\text{3}\frac{\text{1}}{\text{4}}\text{ }\!\!\times\!\!\text{ 6}$ 

$3\frac{1}{4}\times 6=\frac{13}{4}\times 6=\frac{13\times 3}{2}=\frac{39}{2}=19\frac{1}{2}$  

(f)  $\text{3}\frac{\text{2}}{\text{5}}\text{ }\!\!\times\!\!\text{ 8}$ 

$3\frac{2}{5}\times 8=\frac{17}{5}\times 8=\frac{17\times 8}{5}=\frac{136}{5}=27\frac{1}{5}$

(a)  $\frac{\text{1}}{\text{2}}\,\text{of}\,\text{(i)}\,\text{2}\frac{\text{3}}{\text{4}}\,\text{(ii)}\,\text{4}\frac{\text{2}}{\text{9}}$             

(i) Calculating the value, \[\frac{\text{1}}{\text{2}}\,\text{of}\,\text{2}\frac{\text{3}}{\text{4}}\text{=}\frac{\text{1}}{\text{2}}\text{ }\!\!\times\!\!\text{ 2}\frac{\text{3}}{\text{4}}\text{=}\frac{\text{1}}{\text{2}}\text{ }\!\!\times\!\!\text{ }\frac{\text{11}}{\text{4}}\text{=}\frac{\text{11}}{\text{8}}\text{=1}\frac{\text{3}}{\text{8}}\] 

(ii) Calculating the value, \[\frac{\text{1}}{\text{2}}\,\text{of}\,\text{4}\frac{\text{2}}{\text{9}}\text{=}\frac{\text{1}}{\text{2}}\text{ }\!\!\times\!\!\text{ 4}\frac{\text{2}}{\text{9}}\text{=}\frac{\text{1}}{\text{2}}\text{ }\!\!\times\!\!\text{ }\frac{\text{38}}{\text{9}}\text{=}\frac{\text{19}}{\text{9}}\text{=2}\frac{\text{1}}{\text{9}}\] 

(b)  $\frac{\text{5}}{\text{8}}\,\text{of}\,\text{(i)}\,\text{3}\frac{\text{5}}{\text{6}}\,\text{(ii)}\,\text{9}\frac{\text{2}}{\text{3}}$ 

(i) Calculating the value, \[\frac{\text{5}}{\text{8}}\,\text{of}\,\text{3}\frac{\text{5}}{\text{6}}\text{=}\frac{\text{5}}{\text{8}}\text{ }\!\!\times\!\!\text{ 3}\frac{\text{5}}{\text{6}}\text{=}\frac{\text{5}}{\text{8}}\text{ }\!\!\times\!\!\text{ }\frac{\text{23}}{\text{6}}\text{=}\frac{\text{115}}{\text{48}}\text{=2}\frac{\text{19}}{\text{48}}\] 

(ii) Calculating the value, \[\frac{\text{5}}{\text{8}}\,\text{of}\,\text{9}\frac{\text{2}}{\text{3}}\text{=}\frac{\text{5}}{\text{8}}\text{ }\!\!\times\!\!\text{ 9}\frac{\text{2}}{\text{3}}\text{=}\frac{\text{5}}{\text{8}}\text{ }\!\!\times\!\!\text{ }\frac{\text{29}}{\text{3}}\text{=}\frac{\text{145}}{\text{24}}\text{=6}\frac{\text{1}}{\text{24}}\] 

8.  Vidya and Pratap went for a picnic. Their mother gave them a water bottle that contained $\text{5}$ liters of water. Vidya consumed $\frac{\text{2}}{\text{5}}$ of the water. Pratap consumed the remaining water.

(i). How much water did Vidya drink?

Ans:   Water consumed by Vidya is, $\text{=}\frac{\text{2}}{\text{5}}\,\text{of}\,\text{5}\,\text{litres=}\frac{\text{2}}{\text{5}}\text{ }\!\!\times\!\!\text{ 5=2}\,\text{litres}$ 

Hence, Vidya drank $2$ litres of water from the bottle.

(ii). What fraction of the total quantity of water did Pratap drink?

Ans: Water consumed by Pratap \[\text{= }\left( \text{1-}\frac{\text{2}}{\text{5}} \right)\text{  }\]part of bottle

Pratap consumed $\frac{\text{3}}{\text{5}}\,\text{of}\,\text{5}\,\text{litres}\,\text{water=}\frac{\text{3}}{\text{5}}\text{ }\!\!\times\!\!\text{ 5=3}\,\text{lites}$ 

Hence, Pratap drank $\frac{3}{5}$ part of the total quantity of water present in the bottle.

Exercise - 2.2

(i) $\frac{\text{1}}{\text{4}}\,\text{of}$ (a) $\frac{\text{1}}{\text{4}}$ (b) $\frac{\text{3}}{\text{5}}$ (c) $\frac{\text{4}}{\text{3}}$ 

(a) Calculating the value,

$\frac{\text{1}}{\text{4}}\,\text{of}\,\frac{\text{1}}{\text{4}}\text{=}\frac{\text{1}}{\text{4}}\text{ }\!\!\times\!\!\text{ }\frac{\text{1}}{\text{4}}\text{=}\frac{\text{1 }\!\!\times\!\!\text{ 1}}{\text{4 }\!\!\times\!\!\text{ 4}}\text{=}\frac{\text{1}}{\text{16}}$ 

(b) Calculating the value,

$\frac{\text{1}}{\text{4}}\,\text{of}\,\frac{\text{3}}{\text{5}}\text{=}\frac{\text{1}}{\text{4}}\text{ }\!\!\times\!\!\text{ }\frac{\text{3}}{\text{4}}\text{=}\frac{\text{1 }\!\!\times\!\!\text{ 3}}{\text{4 }\!\!\times\!\!\text{ 4}}\text{=}\frac{\text{3}}{\text{16}}$ 

(c) Calculating the value,

$\frac{\text{1}}{\text{4}}\,\text{of}\,\frac{\text{4}}{\text{3}}\text{=}\frac{\text{1}}{\text{4}}\text{ }\!\!\times\!\!\text{ }\frac{\text{4}}{\text{3}}\text{=}\frac{\text{1 }\!\!\times\!\!\text{ 4}}{\text{4 }\!\!\times\!\!\text{ 3}}\text{=}\frac{\text{1}}{\text{3}}$ 

(ii) \[\frac{\text{1}}{\text{7}}\,\text{of}\] (a) \[\frac{\text{2}}{\text{9}}\] (b) \[\frac{\text{6}}{\text{5}}\] (c) $\frac{\text{3}}{\text{10}}$ 

$\frac{\text{1}}{\text{7}}\,\text{of}\,\frac{\text{2}}{\text{9}}\text{=}\frac{\text{1}}{\text{7}}\text{ }\!\!\times\!\!\text{ }\frac{\text{2}}{\text{9}}\text{=}\frac{\text{1 }\!\!\times\!\!\text{ 2}}{\text{7 }\!\!\times\!\!\text{ 9}}\text{=}\frac{\text{2}}{\text{63}}$ 

$\frac{\text{1}}{\text{7}}\,\text{of}\,\frac{\text{2}}{\text{9}}\text{=}\frac{\text{1}}{\text{7}}\text{ }\!\!\times\!\!\text{ }\frac{\text{6}}{\text{5}}\text{=}\frac{\text{1 }\!\!\times\!\!\text{ 6}}{\text{7 }\!\!\times\!\!\text{ 5}}\text{=}\frac{\text{6}}{\text{35}}$ 

$\frac{\text{1}}{\text{7}}\,\text{of}\,\frac{\text{2}}{\text{9}}\text{=}\frac{\text{1}}{\text{7}}\text{ }\!\!\times\!\!\text{ }\frac{\text{3}}{\text{10}}\text{=}\frac{\text{1 }\!\!\times\!\!\text{ 3}}{\text{7 }\!\!\times\!\!\text{ 10}}\text{=}\frac{3}{70}$ 

2. Multiply and reduce to lowest form (if possible):

(i) $\frac{\text{2}}{\text{3}}\text{ }\!\!\times\!\!\text{ 2}\frac{\text{2}}{\text{3}}$ 

Ans: Multiplying and reducing to lowest form,  

$\frac{2}{3}\times 2\frac{2}{3}=\frac{2}{3}\times \frac{8}{3}=\frac{2\times 8}{3\times 3}=\frac{16}{9}=1\frac{7}{9}$ 

(ii) $\frac{\text{2}}{\text{7}}\text{ }\!\!\times\!\!\text{ }\frac{\text{7}}{\text{9}}$

$\frac{2}{7}\times \frac{7}{9}=\frac{2\times 7}{7\times 9}=\frac{2}{9}$

(iii) $\frac{\text{3}}{\text{8}}\text{ }\!\!\times\!\!\text{ }\frac{\text{6}}{\text{4}}$ 

Ans: Multiplying and reducing to lowest form, 

$\frac{3}{8}\times \frac{6}{4}=\frac{3\times 6}{8\times 4}=\frac{3\times 3}{8\times 2}=\frac{9}{16}$

(iv) $\frac{\text{9}}{\text{5}}\text{ }\!\!\times\!\!\text{ }\frac{\text{3}}{\text{5}}$ 

$\frac{9}{5}\times \frac{3}{5}=\frac{9\times 3}{5\times 5}=\frac{27}{25}=1\frac{2}{25}$

(v) $\frac{\text{1}}{\text{3}}\text{ }\!\!\times\!\!\text{ }\frac{\text{15}}{\text{8}}$ 

Ans: Multiplying and reducing to lowest form,

$\frac{1}{3}\times \frac{15}{8}=\frac{1\times 15}{3\times 8}=\frac{1\times 5}{1\times 8}=\frac{5}{8}$

(vi) $\frac{\text{11}}{\text{2}}\text{ }\!\!\times\!\!\text{ }\frac{\text{3}}{\text{10}}$ 

$\frac{11}{2}\times \frac{3}{10}=\frac{11\times 3}{2\times 10}=\frac{33}{20}=1\frac{3}{20}$ 

(vii) $\frac{\text{4}}{\text{5}}\text{ }\!\!\times\!\!\text{ }\frac{\text{12}}{\text{7}}$ 

$\frac{4}{5}\times \frac{12}{7}=\frac{4\times 12}{5\times 7}=\frac{48}{35}=1\frac{13}{35}$

3. Multiply the following fractions:

(i) $\frac{\text{2}}{\text{5}}\text{ }\!\!\times\!\!\text{ 5}\frac{\text{1}}{\text{4}}$

Ans: Performing multiplication,

$\frac{2}{5}\times 5\frac{1}{4}=\frac{2}{5}\times \frac{21}{4}=\frac{2\times 21}{5\times 4}=\frac{1\times 21}{5\times 2}=\frac{21}{10}=2\frac{1}{10}$ 

(ii) $\text{6}\frac{\text{2}}{\text{5}}\text{ }\!\!\times\!\!\text{ }\frac{\text{7}}{\text{9}}$ 

$6\frac{2}{5}\times \frac{7}{9}=\frac{32}{5}\times \frac{7}{9}=\frac{32\times 7}{5\times 9}=\frac{224}{45}=4\frac{44}{45}$

(iii) $\frac{\text{3}}{\text{2}}\text{ }\!\!\times\!\!\text{ 5}\frac{\text{1}}{\text{3}}$ 

$\frac{3}{2}\times 5\frac{1}{3}=\frac{3}{2}\times \frac{16}{3}=\frac{48}{6}=8$ 

(iv) $\frac{\text{5}}{\text{6}}\text{ }\!\!\times\!\!\text{ 2}\frac{\text{3}}{\text{7}}$ 

$\frac{5}{6}\times 2\frac{3}{7}=\frac{5}{6}\times \frac{17}{7}=\frac{85}{42}=2\frac{1}{42}$ 

(v) $\text{3}\frac{\text{2}}{\text{5}}\text{ }\!\!\times\!\!\text{ }\frac{\text{4}}{\text{7}}$

$3\frac{2}{5}\times \frac{4}{7}=\frac{17}{7}\times \frac{4}{7}=\frac{68}{35}=1\frac{33}{35}$

(vi) $\text{2}\frac{\text{3}}{\text{5}}\text{ }\!\!\times\!\!\text{ 3}$ 

$2\frac{3}{5}\times 3=\frac{13}{5}\times \frac{3}{1}=\frac{13\times 3}{5\times 1}=\frac{39}{5}=7\frac{4}{5}$

(vii) $\text{3}\frac{\text{4}}{\text{7}}\text{ }\!\!\times\!\!\text{ }\frac{\text{3}}{\text{5}}$ 

$3\frac{4}{7}\times \frac{3}{5}=\frac{25}{7}\times \frac{3}{5}=\frac{5\times 3}{7\times 1}=\frac{15}{7}=2\frac{1}{7}$

4. Which is greater:

(i) $\frac{\text{2}}{\text{7}}\,\text{of}\,\frac{\text{3}}{\text{4}}\,\text{or}\,\frac{\text{3}}{\text{5}}\,\text{of}\,\frac{\text{5}}{\text{8}}$

Ans: Calculating the greater term,

$\frac{\text{2}}{\text{7}}\,\text{of}\,\frac{\text{3}}{\text{4}}\,\text{or}\,\frac{\text{3}}{\text{5}}\,\text{of}\,\frac{\text{5}}{\text{8}}$                

$\Rightarrow \frac{\text{2}}{\text{7}}\text{ }\!\!\times\!\!\text{ }\frac{\text{3}}{\text{4}}\,\text{or}\,\frac{\text{3}}{\text{5}}\text{ }\!\!\times\!\!\text{ }\frac{\text{5}}{\text{8}}$ 

$\Rightarrow \frac{\text{3}}{\text{14}}\,\text{or}\,\frac{\text{3}}{\text{8}}$

$\Rightarrow \frac{3}{14}<\frac{3}{8}$ 

Hence, $\frac{\text{3}}{\text{5}}\,\text{of}\,\frac{\text{5}}{\text{8}}$ is greater.

(ii) $\frac{\text{1}}{\text{2}}\,\text{of}\,\frac{\text{6}}{\text{7}}\,\text{or}\,\frac{\text{2}}{\text{3}}\,\text{of}\,\frac{\text{3}}{\text{7}}$ 

Calculating the greater term,

$\frac{\text{1}}{\text{2}}\,\text{of}\,\frac{\text{6}}{\text{7}}\,\text{or}\,\frac{\text{2}}{\text{3}}\,\text{of}\,\frac{\text{3}}{\text{7}}$                

$\Rightarrow \frac{\text{1}}{\text{2}}\text{ }\!\!\times\!\!\text{ }\frac{\text{6}}{\text{7}}\,\text{or}\,\frac{\text{2}}{\text{3}}\text{ }\!\!\times\!\!\text{ }\frac{\text{3}}{\text{7}}$ 

$\Rightarrow \frac{\text{6}}{\text{14}}\,\text{or}\,\frac{\text{2}}{\text{7}}$ $\Rightarrow \frac{\text{6}}{\text{14}}>\frac{\text{2}}{\text{7}}$ 

Hence, $\frac{\text{1}}{\text{2}}\,\text{of}\,\frac{\text{6}}{\text{7}}$ is greater.

5. Saili plants \[\text{4}\] saplings in a row in her garden. The distance  between

two adjacent saplings is \[\frac{\text{3}}{\text{4}}\] m. Find the 

distance between the first and the last sapling. 

Ans: Given: Saili plants \[4\] saplings in a row where the distance between two 

adjacent saplings $=\frac{3}{4}$m.

The number of gaps in saplings \[=\text{ }3\] 

Hence, 

The distance between the first and the last saplings$\text{=3 }\!\!\times\!\!\text{ }\frac{\text{3}}{\text{4}}\text{=}\frac{\text{9}}{\text{4}}\text{m=2}\frac{\text{1}}{\text{4}}\text{m}$

Therefore, the distance between the first and the last saplings is $\text{2}\frac{\text{1}}{\text{4}}\,\text{m}$

6. Lipika reads a book for $\text{1}\frac{\text{3}}{\text{4}}$ hours every day. 

She reads the entire book in \[\text{6}\] days. How many hours in all were 

required by her to read the book?

Ans: Given: Time taken for reading a book by Lipika $=1\frac{3}{4}$ hours.

Lipika reads the entire book in $6$ days

Calculating the Total hours taken by Lipika to read the entire book,

$=1\frac{3}{4}\times 6=\frac{7}{4}\times 6=\frac{21}{2}=10\frac{1}{2}$ hours.

Hence, it would take $10$ hours to read the book.

7. A car runs $\text{16}$ km using \[\text{1}\] litre of petrol. How much 

distance will it cover using   $\text{2}\frac{\text{3}}{\text{4}}$ litres of 

Ans: Given: A car covers the distance$\text{=16}\,\text{km}$ in $1$ litre of 

Calculating the distance covered by car in $2\frac{3}{4}$ litres of petrol,

Distance$\text{=2}\frac{\text{3}}{\text{4}}\,\text{of}\,\text{16}\,\text{km=}\frac{\text{11}}{\text{4}}\text{ }\!\!\times\!\!\text{ 16=44}\,\text{km}$

Therefore, car will cover a distance of $44$ km in $2\frac{3}{4}$ litres of petrol.

(i) Provide the number in the box , such that 

$\frac{\text{2}}{\text{3}}\text{ }\!\!\times\!\!\text{ }\text{=}\frac{\text{10}}{\text{30}}$  

Ans: The number inside the box should be $\frac{2}{3}\times =\frac{10}{30}$ 

(ii) The simplest form of the number obtained in $$ is _____.

Ans: The simplest form of the number obtained in 

$\frac{\text{5}}{\text{10}}\,\text{is}\,\frac{\text{1}}{\text{2}}$

(i) Provide the number in the box $$ , such that $\frac{3}{5}\times =\frac{24}{75}$ .

Ans: The number inside the box should be $\frac{3}{5}\times =\frac{24}{75}$ 

(ii) The simplest form of the number obtained in is______.

$\frac{\text{8}}{\text{15}}\,\text{is}\,\frac{\text{8}}{\text{15}}$

Exercise - 2.3

(i) $\text{12 }\!\!\div\!\!\text{ }\frac{\text{3}}{\text{4}}$ 

Ans: Calculating the value,

$12\div \frac{3}{4}=12\times \frac{4}{3}=16$

(ii) $\text{14 }\!\!\div\!\!\text{ }\frac{\text{5}}{\text{6}}$ 

$14\div \frac{5}{6}=14\times \frac{6}{5}=\frac{84}{5}=16\frac{4}{5}$ 

(iii) $\text{8 }\!\!\div\!\!\text{ }\frac{\text{7}}{\text{3}}$ 

Ans:  Calculating the value,

$8\div \frac{7}{3}=8\times \frac{3}{7}=\frac{24}{7}=3\frac{3}{7}$

(iv) $\text{4 }\!\!\div\!\!\text{ }\frac{\text{8}}{\text{3}}$ 

$4\div \frac{8}{3}=4\times \frac{3}{8}=\frac{3}{2}=1\frac{1}{2}$

(v) $\text{3 }\!\!\div\!\!\text{ 2}\frac{\text{1}}{\text{3}}$ 

$3\div 2\frac{1}{3}=3\div \frac{7}{3}=3\times \frac{3}{7}=\frac{9}{7}=1\frac{2}{7}$           

(vi) \[\text{5 }\!\!\div\!\!\text{ 3}\frac{\text{4}}{\text{7}}\] 

$5\div 3\frac{4}{7}=5\div \frac{25}{7}=5\times \frac{7}{25}=\frac{7}{5}=1\frac{2}{5}$

2. Find the reciprocal of each of the following fractions. Classify the 

reciprocals as proper fraction, improper fractions and whole numbers.

(i) $\frac{\text{3}}{\text{7}}$

Ans: Calculating the reciprocal and stating the type of the fraction,

Reciprocal of $\frac{\text{3}}{\text{7}}\text{=}\frac{\text{7}}{\text{3}}\to \text{Improper}\,\text{fraction}$  

(ii) $\frac{\text{5}}{\text{8}}$

Reciprocal of$\frac{\text{5}}{\text{8}}\text{=}\frac{\text{8}}{\text{5}}\to \text{Improper}\,\text{fraction}$

(iii) $\frac{\text{9}}{\text{7}}$

Reciprocal of $\frac{\text{9}}{\text{7}}\text{=}\frac{\text{7}}{\text{9}}\to \text{Proper}\,\text{fraction}$

(iv) $\frac{\text{6}}{\text{5}}$ 

Reciprocal of $\frac{\text{6}}{\text{5}}\text{=}\frac{\text{5}}{\text{6}}\to \text{Proper}\,\text{fraction}$

(v) $\frac{\text{12}}{\text{7}}$ 

Reciprocal of $\frac{\text{12}}{\text{7}}\text{=}\frac{\text{7}}{\text{12}}\to \text{Proper}\,\text{fraction}$  

(vi) $\frac{\text{1}}{\text{8}}$

Reciprocal of $\frac{\text{9}}{\text{7}}\text{=8}\to \text{Whole number}$

(vii) $\frac{\text{1}}{\text{11}}$ 

Reciprocal of $\frac{\text{1}}{\text{11}}\text{=11}\to \text{Whole number}$

(i) $\frac{\text{7}}{\text{3}}\text{ }\!\!\div\!\!\text{ 2}$ 

$\frac{7}{3}\div 2=\frac{7}{3}\times \frac{1}{2}=\frac{7\times 1}{3\times 2}=\frac{7}{6}=1\frac{1}{6}$

(ii) $\frac{\text{4}}{\text{9}}\text{ }\!\!\div\!\!\text{ 5}$

$\frac{4}{9}\div 5=\frac{4}{9}\times \frac{1}{5}=\frac{4\times 1}{9\times 5}=\frac{4}{45}$ 

(iii) $\frac{\text{6}}{\text{13}}\text{ }\!\!\div\!\!\text{ 7}$ 

$\frac{6}{13}\div 7=\frac{6}{13}\times \frac{1}{7}=\frac{6\times 1}{13\times 7}=\frac{6}{91}$ 

(iv) $\text{4}\frac{\text{1}}{\text{3}}\text{ }\!\!\div\!\!\text{ 3}$

Ans:  Calculating the value,

$4\frac{1}{3}\div 3=\frac{13}{3}\div 3=\frac{13}{3}\times \frac{1}{3}=\frac{13}{9}=1\frac{4}{9}$

(v) $\text{3}\frac{\text{1}}{\text{2}}\text{ }\!\!\div\!\!\text{ 4}$ 

$3\frac{1}{2}\div 4=\frac{7}{2}\div 4=\frac{7}{2}\times \frac{1}{4}=\frac{7}{8}$

(vi) $\text{4}\frac{\text{3}}{\text{7}}\text{ }\!\!\div\!\!\text{ 7}$ 

$4\frac{3}{7}\div 7=\frac{31}{7}\div 7=\frac{31}{7}\times \frac{1}{7}=\frac{31}{49}$

(i) $\frac{\text{2}}{\text{5}}\text{ }\!\!\div\!\!\text{ }\frac{\text{1}}{\text{2}}$

$\frac{2}{5}\div \frac{1}{2}=\frac{2}{5}\times \frac{2}{1}=\frac{2\times 2}{5\times 1}=\frac{4}{5}$ 

(ii) $\frac{\text{4}}{\text{9}}\text{ }\!\!\div\!\!\text{ }\frac{\text{2}}{\text{3}}$ 

$\frac{4}{9}\div \frac{2}{3}=\frac{4}{9}\times \frac{3}{2}=\frac{2}{3}$

(iii) $\frac{\text{3}}{\text{7}}\text{ }\!\!\div\!\!\text{ }\frac{\text{8}}{\text{7}}$

$\frac{3}{7}\div \frac{8}{7}=\frac{3}{7}\times \frac{7}{8}=\frac{3}{8}$

(iv) $\text{2}\frac{\text{1}}{\text{3}}\text{ }\!\!\div\!\!\text{ }\frac{\text{3}}{\text{5}}$ 

$2\frac{1}{3}\div \frac{3}{5}=\frac{7}{3}\div \frac{3}{5}=\frac{7}{3}\times \frac{5}{3}=\frac{35}{9}=3\frac{8}{9}$

(v) $\text{3}\frac{\text{1}}{\text{2}}\text{ }\!\!\div\!\!\text{ }\frac{\text{8}}{\text{3}}$ 

$3\frac{1}{2}\div \frac{8}{3}=\frac{7}{2}\div \frac{3}{8}=\frac{7}{2}\times \frac{3}{8}=\frac{7\times 3}{2\times 8}=\frac{21}{16}=1\frac{5}{16}$

(vi) $\frac{\text{2}}{\text{5}}\text{ }\!\!\div\!\!\text{ 1}\frac{\text{1}}{\text{2}}$

$2\frac{1}{3}\div \frac{3}{5}=\frac{2}{5}\div 1\frac{1}{2}=\frac{2}{5}\div \frac{3}{2}=\frac{2}{5}\times \frac{2}{3}=\frac{2\times 2}{5\times 3}=\frac{4}{15}$

(vii) $\text{3}\frac{\text{1}}{\text{5}}\text{ }\!\!\div\!\!\text{ 1}\frac{\text{2}}{\text{3}}$

Ans:   Calculating the value,

$3\frac{1}{5}\div 1\frac{2}{3}=\frac{16}{5}\div \frac{5}{3}=\frac{16}{5}\times \frac{3}{5}=\frac{16\times 3}{5\times 5}=\frac{48}{25}=1\frac{23}{25}$

(viii) $\text{2}\frac{\text{1}}{\text{5}}\text{ }\!\!\div\!\!\text{ 1}\frac{\text{1}}{\text{5}}$ 

$2\frac{1}{5}\div 1\frac{1}{5}=\frac{11}{5}\div \frac{6}{5}=\frac{11}{5}\times \frac{5}{6}=\frac{11}{6}=1\frac{5}{6}$

Exercise 2.4

(i) $\text{0}\text{.2 }\!\!\times\!\!\text{ 6}$ 

\[0.2\times 6=1.2\]

(ii) $\text{8 }\!\!\times\!\!\text{ 4}\text{.6}$

\[8\times 4.6=36.8\]

(iii) $\text{2}\text{.71 }\!\!\times\!\!\text{ 5}$ 

\[2.71\times 5=13.55\]

(iv) $\text{20}\text{.1 }\!\!\times\!\!\text{ 4}$ 

\[20.1\times 4=80.4\]

(v) $\text{0}\text{.05 }\!\!\times\!\!\text{ 7}$ 

\[0.05\times 7=0.35\]

(vi) $\text{211}\text{.02 }\!\!\times\!\!\text{ 4}$ 

\[211.02\times 4=844.08\]

(vii) $\text{2 }\!\!\times\!\!\text{ 0}\text{.86}$ 

\[2\times 0.86=1.72\]

2. Find the area of rectangle whose length is \[\text{5}\text{.7 cm}\] and 

breadth is \[\text{3 cm}\text{.}\]

Ans: Given: The \[\text{Length of rectangle = 5}\text{.7 cm and Breadth of 

rectangle = 3 cm}\] 

Applying the area of rectangle formula,

\[\text{Area of rectangle = Length x Breadth}\] 

\[\text{= 5}\text{.7 x 3 = 17}\text{.1 c}{{\text{m}}^{2}}\]  

Hence, the area of rectangle is $\text{17}\text{.1}\,\text{c}{{\text{m}}^{\text{2}}}$.

(i) \[\text{1}\text{.3 }\!\!\times\!\!\text{ 10}\] 

$1.3\times 10=13.0$

(ii) \[\text{36}\text{.8 }\!\!\times\!\!\text{ 10}\] 

$36.8\times 10=368.0$

(iii) \[\text{153}\text{.7 }\!\!\times\!\!\text{ 10}\] 

$153.7\times 10=1537.0$

(iv) \[\text{168}\text{.07 }\!\!\times\!\!\text{ 10}\]

$168.07\times 10=1680.7$

(v) \[\text{31}\text{.1 }\!\!\times\!\!\text{ 100}\] 

$31.1\times 100=3110.0$

(vi) \[\text{156}\text{.1 }\!\!\times\!\!\text{ 100}\] 

$156.1\times 100=15610.0$

(vii) \[\text{3}\text{.62 }\!\!\times\!\!\text{ 100}\] 

$3.62\times 100=362.0$

(viii) \[\text{43}\text{.07 }\!\!\times\!\!\text{ 100}\] 

$43.07\times 100=4307.0$

(ix) \[\text{0}\text{.5 }\!\!\times\!\!\text{ 10}\] 

$0.5\times 10=5.0$ 

(x) \[\text{0}\text{.08 }\!\!\times\!\!\text{ 10}\] 

$0.08\times 10=0.80$ 

(xi) \[\text{0}\text{.9 }\!\!\times\!\!\text{ 100}\]

$0.9\times 100=90.0$

(xii) \[\text{0}\text{.03 }\!\!\times\!\!\text{ 1000}\] 

$0.03\times 1000=30.0$ 

4. A two-wheeler covers a distance of\[\text{ }\!\!~\!\!\text{ 55}\text{.3 

km}\] 

in one litre of petrol. How much distance will it cover in \[\text{10 litres}\] of 

Ans: Given: In one litre a two-wheeler covers a distance\[\text{ = 55}\text{.3 

Since distance covered in one litre by a two-wheeler\[\text{ = 55}\text{.3 km}\]

\[\therefore \,\,\text{In 10 litrs, a two- wheeler covers a distance = 55}\text{.3 x 10 = 553}\text{.0 km}\] 

Hence, $553$ km distance will be covered by two-wheeler in $10$ litres of petrol.

5.  Find:

(i) $\text{2}\text{.5 }\!\!\times\!\!\text{ 0}\text{.3}$

\[\text{2}\text{.5 x 0}\text{.3 = 0}\text{.75}\] 

(ii) $\text{0}\text{.1 }\!\!\times\!\!\text{ 51}\text{.7}$ 

\[\text{0}\text{.1 x 51}\text{.7 = 5}\text{.17}\]

(iii) $\text{0}\text{.2 }\!\!\times\!\!\text{ 316}\text{.8}$ 

\[\text{0}\text{.2 x 316}\text{.8 = 63}\text{.36}\]

(iv) $\text{1}\text{.3 }\!\!\times\!\!\text{ 1}\text{.3}$ 

\[\text{1}\text{.3 x 3}\text{.1 = 4}\text{.03}\]

(v) $\text{0}\text{.5 }\!\!\times\!\!\text{ 0}\text{.05}$ 

\[\text{0}\text{.5 x 0}\text{.05 = 0}\text{.025}\]

(vi) $\text{11}\text{.2 }\!\!\times\!\!\text{ 0}\text{.15}$ 

\[\text{11}\text{.2 x 0}\text{.15 = 1}\text{.680 }\]

(vii) $\text{1}\text{.07 }\!\!\times\!\!\text{ 0}\text{.02}$ 

\[\text{1}\text{.07 x 0}\text{.02 = 0}\text{.0214}\]

(viii) $\text{10}\text{.05 }\!\!\times\!\!\text{ 1}\text{.05}$

\[\text{10}\text{.05 x 1}\text{.05 = 10}\text{.5525}\]

(ix) $\text{101}\text{.01 }\!\!\times\!\!\text{ 0}\text{.01}$ 

\[\text{101}\text{.01 x 0}\text{.01 = 1}\text{.0101}\]

(x) $\text{100}\text{.01 }\!\!\times\!\!\text{ 1}\text{.1}$

\[\text{100}\text{.01 x 1}\text{.1 = 110}\text{.11 }\]

Exercise 2.5

(i) \[\text{0}\text{.4  }\!\!\div\!\!\text{  2}\] 

\[0.4\div 2=\frac{4}{10}\times \frac{1}{2}=\frac{2}{10}=0.2\]

(ii) \[\text{0}\text{.35  }\!\!\div\!\!\text{  5}\] 

\[0.35\div 5=\frac{35}{100}\times \frac{1}{5}=\frac{7}{100}=0.07\]

(iii) \[\text{2}\text{.48  }\!\!\div\!\!\text{  4}\] 

\[2.48\div 4=\frac{248}{100}\times \frac{1}{4}=\frac{62}{100}=0.62\]

(iv) \[\text{65}\text{.4  }\!\!\div\!\!\text{  6}\] 

\[65.4\div 6=\frac{654}{10}\times \frac{1}{6}=\frac{109}{10}=10.9\]

(v) \[\text{651}\text{.2  }\!\!\div\!\!\text{  4}\] 

\[651.2\div 4=\frac{6512}{10}\times \frac{1}{4}=\frac{1628}{10}=162.8\]

(vi) \[\text{14}\text{.49  }\!\!\div\!\!\text{  7 }\] 

\[14.49\div 7=\frac{1449}{100}\times \frac{1}{7}=\frac{207}{100}=2.07\]

(vii) \[\text{3}\text{.96  }\!\!\div\!\!\text{  4}\]

\[3.96\div 4=\frac{396}{100}\times \frac{1}{4}=\frac{99}{100}=0.99\]

(viii) \[\text{0}\text{.80  }\!\!\div\!\!\text{  5}\] 

\[0.80\div 5=\frac{80}{100}\times \frac{1}{5}=\frac{16}{100}=0.16\]

(i) \[\text{4}\text{.8  }\!\!\div\!\!\text{  10}\] 

Ans: Performing the given calculation,

$4.8\div 10=\frac{4.8}{10}=0.48$

(ii) \[\text{52}\text{.5  }\!\!\div\!\!\text{  10}\] 

$52.5\div 10=\frac{52.5}{10}=5.25$

(iii) \[\text{0}\text{.7  }\!\!\div\!\!\text{  10}\] 

$0.7\div 10=\frac{0.7}{10}=0.07$

(iv) \[\text{33}\text{.1  }\!\!\div\!\!\text{  10}\]

$33.1\div 10=\frac{33.1}{10}=3.31$

(v) \[\text{272}\text{.23  }\!\!\div\!\!\text{  10}\] 

$272.23\div 10=\frac{272.23}{10}=27.223$

(vi) \[\text{0}\text{.56  }\!\!\div\!\!\text{  10 }\] 

$0.56\div 10=\frac{0.56}{10}=0.056$

(vii) \[\text{3}\text{.97  }\!\!\div\!\!\text{  10}\] 

$3.97\div 10=\frac{3.97}{10}=0.397$

(i) \[\text{2}\text{.7  }\!\!\div\!\!\text{  100}\] 

Ans: Converting the terms in fraction form and calculating the value,

$2.7\div 100=\frac{27}{10}\times \frac{1}{100}=\frac{27}{1000}=0.027$ 

(ii) \[\text{0}\text{.3  }\!\!\div\!\!\text{  100 }\]

$0.3\div 100=\frac{3}{10}\times \frac{1}{100}=\frac{3}{1000}=0.003$

(iii) \[\text{0}\text{.78  }\!\!\div\!\!\text{  100}\] 

$0.78\div 100=\frac{78}{10}\times \frac{1}{100}=\frac{78}{1000}=0.0078$

(iv) \[\text{432}\text{.6  }\!\!\div\!\!\text{  100}\] 

$432.6\div 100=\frac{4326}{10}\times \frac{1}{100}=\frac{4326}{1000}=4.326$

(v) \[\text{23}\text{.6  }\!\!\div\!\!\text{  100}\] 

Ans: Converting the terms in fraction form and calculating the value,$23.6\div 100=\frac{236}{10}\times \frac{1}{100}=\frac{236}{1000}=0.236$

(vi) \[\text{98}\text{.53  }\!\!\div\!\!\text{  100}\] 

$98.53\div 100=\frac{9853}{10}\times \frac{1}{100}=\frac{9853}{1000}=0.9853$

(i) \[\text{7}\text{.9  }\!\!\div\!\!\text{  1000}\] 

$7.9\div 1000=\frac{79}{10}\times \frac{1}{1000}=\frac{79}{10000}=0.0079$ 

(ii) \[\text{26}\text{.3  }\!\!\div\!\!\text{  1000}\]

$26.3\div 1000=\frac{263}{10}\times \frac{1}{1000}=\frac{263}{10000}=0.0263$

(iii) \[\text{38}\text{.53  }\!\!\div\!\!\text{  1000}\] 

$38.53\div 1000=\frac{3853}{10}\times \frac{1}{1000}=\frac{3853}{10000}=0.03853$

(iv) \[\text{128}\text{.9  }\!\!\div\!\!\text{  1000}\] 

$128.9\div 1000=\frac{1289}{10}\times \frac{1}{1000}=\frac{1289}{10000}=0.1289$

(v) \[\text{0}\text{.5  }\!\!\div\!\!\text{  1000}\] 

$0.5\div 1000=\frac{5}{10}\times \frac{1}{1000}=\frac{5}{10000}=0.0005$

(i) \[\text{7  }\!\!\div\!\!\text{  3}\text{.5}\] 

$7\div 3.5=7\div \frac{35}{10}=7\times \frac{10}{35}=\frac{10}{5}=2$

(ii) \[\text{36  }\!\!\div\!\!\text{  0}\text{.2 }\]

$36\div 0.2=36\div \frac{2}{10}=36\times \frac{10}{2}=18\times 10=180$

(iii) \[\text{3}\text{.25  }\!\!\div\!\!\text{  0}\text{.5}\]  

Ans: Converting the terms in fraction form and calculating the value,$3.25\div 0.5=\frac{325}{100}\div \frac{5}{10}=\frac{325}{100}\times \frac{10}{5}=\frac{65}{10}=6.5$

(iv) \[\text{30}\text{.94  }\!\!\div\!\!\text{  0}\text{.7}\]

$30.94\div 0.7=\frac{3094}{100}\div \frac{7}{10}=\frac{3094}{100}\times \frac{10}{7}=\frac{442}{10}=44.2$

(v) \[\text{0}\text{.5  }\!\!\div\!\!\text{  0}\text{.25 }\] 

Ans: Converting the terms in fraction form and calculating the value,$0.5\div 0.25=\frac{5}{10}\div \frac{25}{100}=\frac{5}{10}\times \frac{100}{25}=\frac{10}{5}=2$

(vi) \[\text{7}\text{.75  }\!\!\div\!\!\text{  0}\text{.25}\] 

$7.75\div 0.25=\frac{775}{100}\div \frac{25}{100}=\frac{775}{100}\times \frac{100}{25}=31$

(vii) \[\text{76}\text{.5  }\!\!\div\!\!\text{  0}\text{.15}\] 

$76.5\div 0.15=\frac{765}{100}\div \frac{15}{100}=\frac{765}{10}\times \frac{100}{15}=51\times 10=510$

(viii) \[\text{37}\text{.8  }\!\!\div\!\!\text{  1}\text{.4}\]

$37.8\div 1.4=\frac{378}{10}\div \frac{14}{10}=\frac{378}{10}\times \frac{10}{14}=27$

(ix) \[\text{2}\text{.73  }\!\!\div\!\!\text{  1}\text{.3 }\] 

$2.73\div 1.3=\frac{273}{100}\div \frac{13}{10}=\frac{273}{100}\times \frac{10}{13}=\frac{21}{10}=2.1$

6. A vehicle covers a distance of \[\text{43}\text{.2 km}\] in

\[\text{2}\text{.4}\]litres of petrol. How much distance will it cover in one 

litre 

Ans: Given: \[\,\,\,\text{In 2}\text{.4 litres of petrol, distance covered by the vehicle = 43}\text{.2 km}\]

Since,\[\,\,\,\text{In 2}\text{.4 litres of petrol, distance covered by the vehicle = 43}\text{.2 km}\]

\[\therefore \,\,\text{In 1 litre of petrol, distance covered by the vehicle = 43}\text{.2  }\!\!\div\!\!\text{  2}\text{.4}\] 

Performing the required calculations,

$=\frac{432}{10}\div \frac{24}{10}=\frac{432}{10}\times \frac{24}{10}$ 

$\text{=18}\,\text{km}$ 

Hence, the vehicle can cover \[\text{18 km}\] distance in one litre of petrol.

NCERT Solutions for Class 7 Chapter 2 Maths PDF Download

2.1 introduction.

In NCERT Solutions Class 7 Chapter 2 Maths, students will learn about fractions and decimals. In junior classes, students have learned about what is a fraction and its types: proper, improper, mixed fractions, etc. Now, in class 7, we are going to learn about multiplication and division of fractions. The concept of fractions mainly focuses on the ratios and proportions, how to distribute etc. At the same time, decimals are the accurate values obtained after the division.

2.2 Recollect

In NCERT Solutions Class 7 Maths Chapter 2, students need to think again on the topics they have learned so far in the previous classes. These include representation of fractions on the number line, ordering of fractions, addition and subtraction of fractions, decimals and their additions, how to keep a point, etc. These are reminded in the first two exercises.

2.3 Multiplication of Fractions

In this section, students can understand how to multiply two fractions. If students have values like a and b, they can say ab is the product of a and b. If the values are like p/q, a/b then, how can we multiply? To multiply these fractions, it has two different methods. One is by using a  whole number and the other is by using a portion.

2.3.1 Multiplication of Fractions Using the Whole Number

Here, let us see what Fraction tells us? It explains that a down part is a whole number (except zero) and the upper part is the integer. In a fraction, the down part is known as the denominator whereas the upper part is the numerator. We use a whole number to multiply fractions if they are the same. For instance, let's say we have p/q. Then we can multiply with the whole number as 3*p/q. It is also applicable for improper or mixed fractions. But students need to make them into simpler forms before multiplying.

2.3.1 Multiplication of Fractions Using the Fraction

In this section, students can learn how to multiply two fractions when they are dissimilar. Students use a fraction to multiply them. The formula for multiplying two fractions is,(product of numerators)/(product of denominators).

The resultant product is less than the two fractions if we multiply two proper fractions. On the other hand, the result is greater than the two fractions if we multiply two improper fractions.

2.4 Division of Fractions

Let's discuss the division of fractions. Students can divide a fraction by a whole number and a whole number by a fraction. Here is a particular case to keep in mind. If two fractions for which numerator and denominator are in reverse order, then they are called reciprocals to each other.  Their product is always 1.

In the same way, while dividing mixed fractions with a whole number, students need to change the mixed fraction into improper fractions. Then it is easy to divide and solve. Next, we have to learn to divide a fraction with another fraction by changing one of the fractions into its reciprocal form.

The three concepts are explained differently in the NCERT Solutions for Class 7 Maths Chapter 2 PDF book available on Vedantu for students to go through if necessary.

2.5 Recalling Decimals

Decimals are the proper forms to represent the results obtained from multiplication and division. Placing the point in between numbers plays a vital role. One can express the heights, distances, weights,  measuring values, interest rates, shares, and fractions, also using decimals. To change the place value of the point, we can multiply by 10,100,...... Let's have a glance at the addition and subtraction of decimals.

Overview of Deleted Syllabus for CBSE Class 7 Maths Chapter 2 Fractions and Decimals

Class 7 Maths Chapter 2: Exercises Breakdown

NCERT Solutions for Chapter 2 fraction and decimals Class 7 offers practice problems and clear explanations to help master these concepts. Students should focus on fraction addition, subtraction, multiplication, and division for both like and unlike denominators. They should also be able to convert between fractions and decimals easily and understand relative fraction sizes. By carefully working through NCERT Class 7 Maths Chapter 2 Exercises, students can improve their knowledge and prepare for exams.

Other Study Material for CBSE Class 7 Maths Chapter 2

Chapter-Specific NCERT Solutions for Class 7 Maths

Given below are the chapter-wise NCERT Solutions for Class 7 Maths. Go through these chapter-wise solutions to be thoroughly familiar with the concepts.

FAQs on NCERT Solutions Class 7 Maths Chapter 2 Fractions and Decimals

1. What are the main topics and subtopics covered in chapter 2 of Class 7 Maths?

Topics and sub-topics discussed in Chapter 2 Fractions and Decimals of NCERT Solutions Class 7 Maths are: Addition and Subtraction of Fractions, Multiplication of Fraction, Multiplication of a Fraction by a Whole Number, Multiplication of a Fraction by a Fraction, Division of Fraction, Division of Whole Number by a Fraction, Reciprocal of Fraction, Division of a fraction by a Whole Number, Division of Fraction by Another Fraction, Multiplication of Decimal Numbers, Multiplication of Decimal Numbers by 10, 100 and 1000, Division of Decimal Numbers, Division of Decimals by 10, 100 and 1000, Division of a Decimal Number by a Whole Number and Division of a Decimal Number by Another Decimal Number.

2. How many questions are there in exercises of chapter 2 of Class 7 Maths?

There are a total of seven exercises given in the second chapter of Class 7 Maths. Exercise 2.1 has 8 questions, exercise 2.2 has 8 questions, exercise 2.3 has 8 questions, exercise 2.4 has 4 questions, exercise 2.5 has 9 questions, exercise 2.6 has 5 questions, and exercise 2.7 has 6 questions.

3. How do I compare two fractions class 7 maths ch 2?

By examining the numerators, fractions with the same denominator can be compared. It is a larger fraction with a larger numerator. You can convert fractions with different denominators to equivalent fractions with the same denominator so that you can compare them.

4. What are the different types of fractions?

There are three main types of fractions: proper fractions, improper fractions, and mixed numbers.

Proper fractions: These are fractions whose numerator is smaller than the denominator. For example, 1/2 and 3/5 are proper fractions.

Improper fractions: These are fractions whose numerator is larger than or equal to the denominator. For example, 5/3 and 8/2 are improper fractions.

Mixed numbers: These are numbers that are made up of a whole number and a fraction. For example, 2 1/2 is a mixed number.

5. What are the different types of decimals?

There are two main types of decimals: terminating decimals and non-terminating decimals.

Terminating decimals: These are decimals that end after a finite number of digits. For example, 0.5 and 1.23 are terminating decimals.

Non-terminating decimals: These are decimals that do not end after a finite number of digits. For example, 1/3 and 1/2 are non-terminating decimals.

6. What are the uses of fractions and decimals?

Fractions and decimals are used in a variety of ways in mathematics and everyday life.

In mathematics, fractions and decimals are used to represent parts of a whole, to perform arithmetic operations, and to solve equations.

In everyday life, fractions and decimals are used to represent quantities such as money, time, and measurements.

7. What's important in class 7th maths chapter 2 ?

This chapter covers various aspects of fractions and decimals in class 7th maths chapter 2 . Here's what to focus on:

Understanding different types of fractions (proper, improper, mixed)

Converting between fractions and decimals

Comparing and ordering fractions

Adding and subtracting fractions and decimals

Representing fractions on the number line

8. What are like terms in addition and subtraction of fractions in class 7 chapter 2 maths?

Like terms in fractions, they have the same denominator. When adding or subtracting fractions, make sure they have the same denominator before performing the operation.

9. How do I represent fractions on the number line in fraction and decimals class7?

Divide the space between two whole numbers on the number line according to the denominator of the fraction. Each small interval represents 1/denominator. Shade the required number of intervals based on the numerator.

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CBSE Important Questions Class 7 Maths Chapter 2

Home » CBSE » CBSE Important Questions Class 7 Maths Chapter 2

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Important Questions Class 7 Mathematics Chapter 2 – Fractions and Decimals

Mathematics is an important subject that you study in school. We need Mathematics in our daily life too. In this chapter, you will learn about decimals and fractions more elaborately. In Class 6, students have learned about fractions and decimals.

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Chapter 2 of Class 7 Mathematics under the CBSE curriculum deals with the addition or multiplication of decimals and fractions. Students must practice questions from the chapter as much as possible. They may take help from other sources because the textbook exercises have limited questions.

Extramarks is a leading company in the educational sector. Our experts have made the Important Questions Class 7 Mathematics Chapter 2 to help students to solve the questions regularly. They have collated the questions from different sources such as the CBSE sample papers, CBSE past years’ question papers, the textbook exercises, NCERT exemplars and important reference books. They have solved the questions too.

Extramarks provides all the important study materials related to CBSE and NCERT. You can download the study materials after registering on our official website. We provide CBSE syllabus, CBSE sample papers, CBSE past years’ question papers, CBSE extra questions, CBSE revision notes, NCERT books, NCERT exemplars, NCERT solutions, NCERT important questions, vital formulas and many more.

Fraction Questions for Class 7 – With Solutions

The subject matter of Extramarks has made the question series so that students can regularly solve questions from the chapter. They have taken help from the textbook exercises, CBSE sample papers, CBSE past years’ question papers, NCERT exemplars and important reference books. They have solved the questions, and experienced professionals have further checked the answers to ensure the best quality of the content. Thus. The Important Questions Class 7 Mathematics Chapter 2 will help students to score better in exams. The important questions are-

Question 1. Ritu ate at least (3/5) part of an apple, and then the remaining apple was eaten by ritu’s brother Shyam. How many parts of the apple did Shyam eat? Who had the larger share? And By how much?

From the above question, it is given that,

The part of apple eaten by Ritu is equal to (3/5)

And the part of apple eaten by Shyam is = 1 – the part of apple eaten by Ritu is?

= 1 – (3/5)

The LCM of numbers 1 and 5 is = 5

Now, let us change these given fractions into an equivalent fraction by taking ten as the denominator number.

= [(1/1) × (5/5)] – [(3/5) × (1/1)]

= (5/5) – (3/5)

= (5 – 3)/5

Hence the part of apple eaten by Shyam is (2/5)

So, (3/5) is greater than (2/5); hence, Ritu ate the larger apple.

Now, the difference between the shares is = (3/5) – (2/5)

= (3 – 2)/5

Thus, Ritu’s share is greater than the share of Shyam by (1/5)

Question 2. Michae finished colouring a picture on (7/12) hour. On the other hand, Vaibhav finished colouring the same picture in (3/4) hour. Who worked longer colouring the picture? By what fraction was it longer?

Time taken by Michae to colour the picture is = (7/12)

Time taken by Vaibhav to colour the picture is = (3/4)

The LCM of numbers 12, 4 = 12

Now, let us change these given fractions into an equivalent fractions by using 12 as the denominator number.

(7/12) = (7/12) × (1/1) = 7/12

The same method is applied to, 

(3/4) = (3/4) × (3/3) = 9/12

As seen, (7/12) is less than (9/12)

Hence, (7/12) < (3/4)

Thus, Vaibhav worked for a longer time as compared.

Now, Vaibhav worked longer time by = (3/4) – (7/12)

= (9/12) – (7/12)

= (9 – 7)/12

= (1/6) of an hour.

Question 3. Vidya and Pratik went on a picnic. Their mother gave them a mineral water bottle that contained 5 litres of water. Vidya consumed around 2/5 of the water, and Pratik consumed the remaining water.

(i) How many litres of water did Vidya drink?

(ii) And What fraction of the total quantity of water did Pratik drink?

(i) From the above question, it is given that,

The amount of water in the water bottle is = 5 litres.

The amount of water consumed by Vidya is = 2/5 of 5 litres.

= (2/5) × 5

Hence, the total amount of water drank by Vidya is 2 litres.

(ii) From the above question, it is given that,

Amount of water present in the water bottle = 5 litres

The amount of water consumed by Pratik = (1 – water consumed by Vidya)

= (1 – (2/5))

Hence the Total Amount of water consumed by Pratik = is 3/5 of 5 litres.

= (3/5) × 5

So, the total amount of water consumed by Pratik is 3 litres.

Question 4. Which of the following is greater:

(i) (2/7) of (3/4) or the fraction (3/5) of (5/8)

We have seen that,

= (2/7) × (3/4) and the (3/5) × (5/8)

Hence, By the rule of Multiplication of the fraction,

The product of fraction is equal to (product of numerator)/ (product of denominator)

= (2/7) × (3/4)

= (2 × 3)/ (7 × 4)

= (1 × 3)/ (7 × 2)

= (3/14) … [i]

= (3/5) × (5/8)

= (3 × 5)/ (5 × 8)

= (3 × 1)/ (1 × 8)

= (3/8) … [ii]

Now, convert the [i] and [ii] into like fractions,

LCM of 14 and 8 become 56

Now, let us change each of these given fractions into an equivalent fraction that has 56 as its denominator number.

[(3/14) × (4/4)] is equal to (12/56) [(3/8) × (7/7)] = (21/56)

Clearly, it is seen,

(12/56) is less than (21/56)

(3/14) is less than (3/8)

(ii) (1/2) of (6/7) or the (2/3) of (3/7)

= (1/2) × (6/7) and the (2/3) × (3/7)

By the rule of Multiplication of the fraction,

Product of fraction = (product of numerator) divided by (product of denominator)

= (1/2) × (6/7)

= (1 × 6)/ (2 × 7)

= (1 × 3)/ (1 × 7)

= (3/7) … [i]

= (2/3) × (3/7)

= (2 × 3)/ (3 × 7)

= (2 × 1)/ (1 × 7)

= (2/7) … [ii]

By comparing [i] and [ii],

(3/7) > (2/7)

Question 5. Saili plants four saplings successively in a row in her garden. The distance between the two adjacent saplings is ¾ m. Now Find the distance between the first and the last planted sapling.

The distance between the two adjacent saplings is = ¾ m

The number of saplings which are planted by Saili in a row is = 4

Then, the number of the gap in the saplings = ¾ × 4

Hence The total distance between the first and the last saplings becomes = three × ¾

Thus, the distance between the first and the last saplings is two ¼ m.

Question 6. Lipika always reads a book for one ¾ hour every day. She reads an entire book in 6 days. How many hours in total were required by her to finish the book?

From the above question, it is clearly given that,

Lipika reads her book for = one ¾ hours every day, which is equal to 7/4 hours for six days.

The number of days she took to finish the entire book = was six days

Hence, the Total number of hours required by her to fully complete the book = (7/4) × 6

= (7/2) × 3

= 10 ½ hours

Thus, the total number of hours required by her to complete the book is 10 ½ hours.

Question 7. A car runs around 16 km using 1 litre of petrol. How much distance will the car cover use two ¾ litres of petrol?

Answers 7:-

The total distance travelled by car in 1 litre of petrol is = 16 km.

The Total quantity of petrol becomes = two ¾ litre = 11/4 litres

The total distance travelled by car in 11/4 litres of petrol is = (11/4) × 16

Hence, the total distance travelled by car in 11/4 litres of petrol is 44 km.

Question 8. Find the reciprocal of each of these following fractions. Also, Classify these reciprocals as proper fractions, improper fractions and whole numbers.

Reciprocal of (3/7) is (7/3) [which is ((3/7) × (7/3)) = 1]

So, it is an improper fraction.

An improper fraction is defined as a fraction in which the numerator is always greater than its denominator.

Reciprocal of (5/8) is (8/5) [which is ((5/8) × (8/5)) = 1]

So, it is also an improper fraction.

An improper fraction is defined as a fraction in which the numerator is greater than its denominator.

Reciprocal of (9/7) is (7/9) [which is ((9/7) × (7/9)) = 1]

Hence, it is a proper fraction.

A proper fraction is defined as that fraction in which the denominator is greater than the numerator of their fraction.

Reciprocal of (6/5) is (5/6) [which is ((6/5) × (5/6)) = 1]

A proper fraction is defined as a fraction in which the denominator is greater than the numerator of any fraction.

Reciprocal of (12/7) is (7/12) [which is ((12/7) × (7/12)) = 1]

A proper fraction is defined as a fraction in which the denominator is greater than the numerator of the given fraction.

Reciprocal of the fraction (1/8) is (8/1) or 8 as [∵ ((1/8) × (8/1)) = 1]

Hence, it is a whole number.

Whole numbers are the total collection of all positive integers, including the number 0.

Reciprocal of the fraction (1/11) is (11/1) or 11 which is [∵ ((1/11) × (11/1)) = 1]

So, it is a whole number.

Whole numbers are the total collection of all positive integers, including 0.

Question 9. Find:

(i) (7/3) ÷ 2

Answer  9:-

= (7/3) × reciprocal of 2

= (7/3) × (1/2)

= (7 × 1) / (3 × 2)

(ii) (4/9) ÷ 5

= (4/9) × reciprocal of 5

= (4/9) × (1/5)

= (4 × 1) / (9 × 5)

(iii) (6/13) ÷ 7

= (6/13) × reciprocal of 7

= (6/13) × (1/7)

= (6 × 1) / (13 × 7)

Question 10. Which of the following is greater?

(i) 0.5 or 0.05

Answer 10:-

By comparing the whole number, we get 0 = 0

By comparing the tenths place digit, we get 5 > 0

∴ 0.5 > 0.05

(ii) 0.7 or 0.5

By comparing the whole number, 0 = 0

By comparing the tenths place digit we receive, 7 > 5

∴ 0.7 > 0.5

(iii) 7 or 0.7

By comparing these whole numbers, 7 > 0

∴ 7 > 0.7

(iv) 1.37 or 1.49

By comparing these whole numbers, 1 = 1

By comparing the tenths place digit, we get, 3 < 4

∴ 1.37 < 1.49

(v) 2.03 or 2.30

By comparing the whole number, 2 = 2

By comparing the tenths place digit, we get, 0 < 3

∴ 2.03 < 2.30

(vi) 0.8 or 0.88

By comparing these whole numbers, 0 = 0

By comparing the tenths place digit, we get, 8 = 8

Also, by comparing the hundredths place digit, 0 < 8

∴ 0.8 < 0.88

Question 11. Express as rupees as decimals:

(i) 7 paise

Answer 11:-

We know that,

= ₹ 1 = 100 paise

= 1 paise = ₹ (1/100)

∴ 7 paise = ₹ (7/100)

(ii) 7 rupees 7 paise

∴ 7 rupees 7 paise = ₹ 7 + ₹ (7/100)

= ₹ 7 + ₹ 0.07

(iii) 77 rupees 77 paise

∴ 77 rupees 77 paise = ₹ 77 + ₹ (77/100)

= ₹ 77 + ₹ 0.77

(iv) 50 paise

∴ 50 paise = ₹ (50/100)

(v) 235 paise

∴ 235 paise = ₹ (235/100)

Question 12. (i) Express 5 centimeters in meter and kilometre

Answer 12:-

We all know that,

= 1 meter = 100 centimeter

= 1 cm = (1/100) meter

= 5 cm = (5/100)

= 1 km = 1000 meter

= 1 m = (1/1000) kilometer

= 0.05 m = (0.05/1000)

= 0. 00005 kilometer

(i) Express 35 mm in cm, m and km

= 1 cm = 10 mm

= 1 mm = (1/10) cm

= 35 mm = (35/10) cm

= 1 meter = 100 cm

= 1 cm = (1/100) m

= 3.5 cm = (3.5/100) m

= (35/1000) m

= 1 km = 1000 m

= 1 m = (1/1000) km

= 0.035 m = (0.035/1000)

= 0. 000035 km

Question 13. Express in kilogram:

(i) 200 gram

Answer 13:-

= 1 kg = 1000 gram

= 1 g = (1/1000) kg

= 200 g = (200/1000) kilogram

(ii) 3470 gram

= 1 g = (1/1000) kilogram

= 3470 g = (3470/1000) kilogram

= (3470/100)

(ii) 4 kg 8 g

= 4 kg 8 g is equal to 4 kg + (8/1000) kilogram

= 4 kg + 0.008

= 4.008 kilogram

Question 14 . Write the following in decimal numbers in their expanded form:

Answer 14:-

We have that,

20.03 = (2 × 10) + (0 × 1) + (0 × (1/10)) + (3 × (1/100))

2.03 is equal to (2 × 1) + (0 × (1/10)) + (3 × (1/100))

(iii) 200.03

200.03 is (2 × 100) + (0 × 10) + (0 × 1) + (0 × (1/10)) + (3 × (1/100))

2.034 gets equal to (2 × 1) + (0 × (1/10)) + (3 × (1/100)) + (4 × (1/1000)).

Question. Write the place value of 2 in the following decimal numbers:

From the above question, we can observe that,

The place value of 2 in the decimal 2.56 is ones.

The place value of 2 in the decimal 21.37 is tens.

(iii) 10.25

The place value of 2 in the decimal 10.25 is tenths.

The place value of 2 in the decimal 9.42 is the hundredth.

The place value of 2 in the decimal 63.352 is the thousandth.

Question 15. Shyama bought around 5 kg 300 g apples and 3 kg 250 g mangoes. Sarala then bought 4 kg 800 g oranges and 4 kg 150 g bananas. Who bought more fruits?

Answer 15:-

Fruits bought by Shyama is = 5 kg 300 g

= 5 kg + (300/1000) kg

= 5 kg + 0.3 kg

Fruits bought by Sarala is = 4 kg 800 g + 4 kg 150 g

= (4 + (800/1000)) + (4 + (150/1000))

= (4 + 0.8) kg + (4 + .150) kg

= 4.8 kg + 4.150kg

So, Sarala bought more fruits.

Question 16. How much less is 28 km as compared to 42.6 km?

Answer 16:-

Now, we have to find the difference between 42.6 km and 28 km.

Hence, 14.6 km less is 28 km than 42.6 km.

Question 17. Find:

(i) 1.3 × 10

Answer 17:-

On multiplying the decimal by 10, the decimal point is shifted to the right by one place.

= 1.3 × 10 = 13

(ii) 36.8 × 10

n multiplying the decimal by 10, the decimal point is shifted to the right by one place.

= 36.8 × 10 = 368

(iii) 153.7 × 10

= 153.7 × 10 = 1537

(iv) 168.07 × 10

= 168.07 × 10 = 1680.7

(v) 31.1 × 100

On multiplying the decimal by 100, the decimal point is shifted to the right by two places.

= 31.1 × 100 = 3110

(vi) 156.1 × 100

= 156.1 × 100 = 15610

(vii) 3.62 × 100

On multiplying a decimal by the number 100, the decimal point is shifted to the right by two places.

= 3.62 × 100 = 362

(viii) 43.07 × 100

= 43.07 × 100 = 4307

Question 18. A two-wheeler covers a total distance of 55.3 km in one litre of petrol. How much total distance will it cover in 10 litres of petrol?

Answer 18:-

Distance covered by the two-wheeler in 1L of petrol = 55.3 km

Distance covered by the two-wheeler in 10L of petrol is = (10 × 55.3)

Hence the Two-wheeler covers a distance of 10L of petrol 553 km.

Question 19. Find the following:

(a) 2.5 × 0.3

Answer 19:-

= (25/10) × (3/10)

On dividing the decimal by 100, the decimal point is shifted to the left by two places.

(b) 0.1 × 51.7

= (1/10) × (517/10)

= (517/100)

(c) 0.2 × 316.8

= (2/10) × (3168/10)

= (6336/100)

(d) 1.3 × 3.1

= (13/10) × (31/10)

= (403/100)

Question 20. Find:

(i) 7 ÷ 3.5

= 7 ÷ (35/10)

= 7 × (10/35)

= 1 × (10/5)

(ii) 36 ÷ 0.2

= 36 ÷ (2/10)

= 36 × (10/2)

(iii) 3.25 ÷ 0.5

= (325/100) ÷ (5/10)

= (325/100) × (10/5)

= (325 × 10)/ (100 × 5)

= (65 × 1)/ (10 × 1)

Benefits of Solving Important Questions Class 7 Mathematics Chapter 2

Practice is very important for students. It helps them to clear their doubts and strengthen their concepts. Often, students need more than textbook exercises. They may take help from the chapter-wise question series made by our professionals. They have collected the questions from several sources and given the solutions in the Class 7 Mathematics Chapter 2 Important Questions , and there will be multiple benefits to solving these questions. These are-

• Sometimes, students need more than textbook exercises. They would need help to search for questions from different sources. The experts have made the task easier for the students. They collected questions from the CBSE sample papers, NCERT textbook exercises, NCERT exemplars and important reference books. Apart from this, they have included a few questions from CBSE past years’ question papers. Thus, students will find the vital questions in one single pdf. 
• The experts have not only included the questions, but they have solved the questions too. They have given a step-step process to solve the problems. Thus, the students can follow the solutions if they cannot solve the questions. Experienced professionals have further checked the answers to ensure the best quality of the content. Thus, the Mathematics Class 7 Chapter 2 Important Questions will also help the students to solve the questions. It will boost their confidence and generate their interest in the subject matter.
• The habit of practice is very important for students. They must solve questions regularly to strengthen their concepts of the subject matter. The experts have tried to include all the important concepts in this article. Thus, the Important Questions Class 7 Mathematics Chapter 2 will help students in several ways. It will clear their doubts and strengthen their concepts. Thus, it will help them to score better in exams. Some students are scared of this subject. It is because they need help understanding the concepts clearly. This question series will help them greatly because they can follow the solutions and learn how to solve the sums.

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What is the value of the following expression? 0 .1 0 .01 + 0 .01 0 .1

Ans Option1 Explanation

0 .1 0 .01 + 0 .01 0 .1 = 10 + 1 10 = 10 + 0 .1 = 10 .1

Q.2 What is the value of 10.05 × 1.05?

Ans Option2 Explanation

1005 × 105 = 105525

Since 10.05 has 2 digits and 1.05 has 2 digits after the decimal point, therefore, the product must have 4 digits after decimal point.

10.05 × 1.05 = 10.5525

Q.3 Bob has given half of the whole cake to his sister Maria. Maria further divided it into three parts, ate only one part and kept the rest two parts in the fridge for later. What part of the whole cake has she kept in the fridge?

Share= 1 2 The part which Maria ate = 1 2 ÷ 3 Remaining part = 1 2 − 1 6 = 3 − 1 6 = 2 6 = 1 3

4 + 3 5 − 2 7

Marks: 1 Ans

L.C.M of 1, 5, 7 = 35

∴   4 + 3 5 − 2 7 = 140 + 21 − 10 35 = 151 35

Q.5  What is the expanded form of 205.149?

2 × 1000 + 0 × 100 + 5 × 10 + 1 × 1 10 + 4 × 1 100 + 9 × 1 1000 2 × 100 + 0 × 10 + 5 × 1 + 1 × 1 + 4 × 1 10 + 9 × 1 100 1 × 100 + 4 × 10 + 9 × 1 + 2 × 1 10 + 0 × 1 100 + 5 × 1 1000  2 × 100 + 0 × 10 + 5 × 1 + 1 × 1 10 + 4 × 1 100 + 9 × 1 1000

Ans Option4 Explanation

The expanded form of 205 .149 is: 2 × 100 + 0 × 10 + 5 × 1 + 1 × 1 10 + 4 × 1 100 + 9 × 1 1000

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Faqs (frequently asked questions), 1. what is the content of chapter 2 class 7 mathematics.

Chapter 2 of Class 7 Mathematics deals with the addition, subtraction, multiplication and division of fractions and decimals. Students are familiar with decimals and fractions but have yet to study how to perform different mathematical relations between fractions or decimals. The chapter is relatively easy for students; they can easily understand the subject matter if they follow the textbook exercises seriously. They can also take help from the Important Questions Class 7 Mathematics Chapter 2 by the experts of Extramarks. They can also follow the questions if they cannot solve the questions.

2. How can the Important Questions Class 7 Mathematics Chapter 2 help students?

The experts of Extramarks have made this question series to help students. They have collected important questions from different sources such as the textbook exercises, CBSE sample papers, CBSE past years’ question papers, NCERT exemplar and important reference books. They have solved the questions, and experienced professionals have further checked the answers to ensure the best quality of the content. The students can follow the answers if they need help solving the questions. Thus, the Important Questions Class 7 Mathematics Chapter 2 can help students to score better in exams.

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Fractions And Decimals Extra Questions For Practice | Class 7 NCERT Maths Solutions

by Sanjusha · October 18, 2019

CLASS 7 MATHEMATICS | FRACTIONS AND DECIMALS – Extra Questions for practice

Answer the following:

1. Write first five equivalent fractions of 2/3.

2. Arrange the following in descending order: 2/7, 4/3, 5/21

3. A rectangular sheet of paper is 5/2 m long and 3/5 m wide. Find its perimeter.

4. Find ½ of 36.

5. Find ¼ of 5/8.

6. Anu purchased 2 ¼ kg apples and 4 ¾ kg oranges. What is the total weight of fruits purchased by her?

7. Multiply the following:

a) 2/5 x 4/7 b) ½ x ¾

8. If there are 5 pieces of cake and each person gets 5/3 of a piece of cake, how many people get cake?

9. Which is greatest?

2/3 of 4/5 or 3/5 of 4/3.

10. Find a) ¼ of 3/5 b) 1/7 of 3/10.

1. Equivalent fractions of 2/3 are 2/3, 4/6, 6/9, 8/12, 10/15.

2. First convert to like fractions.

2/7 = 6/21 ( Multiply both numerator and denominator by 3) 4/3 = 28/21 (Multiply both numerator and denominator by 7) Descending order is 28/21, 6/21, 5/21. So 4/3, 2/7, 5/2 is the descending order.

3. Given length= 5/2 m and Breadth = 3/5 m

Perimeter = 2 x (length + breadth) = 2 x (5/2 + 3/5) = 2 x (25 +6)/10 = 2 x 31/10 = 31/5 m

4. ½ of 36 = ½ x 36 = 18

5. ¼ of 5/8 = ¼ x 5/8 = 5/32.

6. Weight of apples = 2 ¼ kg

Weight of oranges = 4 ¾ kg Total weight of fruits = 2 ¼ + 4 ¾ Convert to improper fractions, 2 ¼ = 9/4 4 ¾ = 19/4 2 ¼ + 4 ¾ = 9/4 + 19/4 = 28/4 = 7 kg

7. a) 2/5 x 4/7 = 8/35

b) ½ x ¾ = 3/8.

8. Total number of pieces of cake = 5

Piece of cake each one get = 5/3 Number of persons = 5 divided by 5/3 = 5 x 3/5 = 15/5 =3

9. 2/3 x 4/5 = 8/15

3/5 x 4/3 = 12/15. Since 12 is greater than 8, 12/15 is greater than 8/15.

10. a) ¼ x 3/5 = 3/20. b) 1/7 x 3/10 = 3/70.

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Fractions and Decimals Class 7 MCQ Test (Online Available)

Free mcq test, table of content, fractions and decimals test - 35.

Duration: 10 Mins

Maximum Marks: 10

Read the following instructions carefully.

1. The test contains 10 total questions.

2. Each question has 4 options out of which only one is correct .

3. You have to finish the test in 10 minutes.

4. You will be awarded 1 mark for each correct answer.

5. You can view your Score & Rank after submitting the test.

6. Check detailed Solution with explanation after submitting the test.

7. Rank is calculated on the basis of Marks Scored & Time

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Duration:  15 Mins

Maximum Marks:  15

1. The test contains 15 total questions.

3. You have to finish the test in 15 minutes.

4. There is No Negative marking .

5. You will be awarded 1 mark for each correct answer.

6. You can view your Score & Rank after submitting the test.

7. Check detailed Solution with explanation after submitting the test.

8. Rank is calculated on the basis of Marks Scored & Time.

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Objective questions have become the norm now, those students who are studying in class 7 must be well versed with all kinds of MCQ Questions; therefore, the link to access Fractions and Decimals MCQ Class 7 is mentioned here on this page.

Fractions and Decimals Class 7 MCQ questions are curated by subject experts referring to the prescribed NCERT Class 7 Maths Book. Those students who have studied the lesson Fractions and Decimals must practise the CBSE Class 7 MCQ Questions as it helps in deepening the understanding of the topics.

Class 7 Fractions and Decimals MCQ with Answers Online

For the ease of students, the subject experts have simplified the practice process of the class 7 Fractions and Decimals MCQ as they have solved each and every question given. The answers are detailed and easy to grasp. Students who want to practise the questions of Class 7 Fractions and Decimals MCQ with Answers online can use the Selfstudys website.

The MCQ Questions of Fractions and Decimals with answers are also given so that students can understand the methods of solving the concepts based questions. As well as, the solutions are helpful to understand where the students are making mistakes and need to improve.

How to Practise MCQ from NCERT Chapter Fractions and Decimals?

There are several ways to practise the MCQ from NCERT Chapter Fractions and Decimals; one is by solving questions from the chapter’s end and another is by using online medium. In this section, we have mentioned the steps to Practise MCQ from NCERT Chapter Fractions and Decimals online.

• First of all open Selfstudys.com on your Smartphone, PC/Laptop

• Navigate to the CBSE by Tapping/clicking on the navigation bar or button 
• It will open a new lists where you can find MCQ Test - Click on that  

• Then, a new page will load containing the lists of classes; just Tap or click on Class 7. *In Smartphone, you may require to scroll the given classes name towards left.

• Now, after selecting the Class 7, the same page will reload, make sure you select the Maths to access the MCQ Questions of Class 7 Fractions and Decimals.

Note: The online MCQ Questions of Fractions and Decimals can’t be downloaded, those who want to access the PDF of Fractions and Decimals MCQ can refer to the CBSE Class 7 MCQ PDF  section within the CBSE menu.

What is Fractions and Decimals MCQ and How to Use it?

Since class 7 students are in their early stage of academics they may have questions regarding What is Fractions and Decimals MCQ and How to Use it. So, the answer is MCQ Questions are objective questions which contain questions followed by 4 options where only one is considered the correct answer and remaining as a distraction. Why is it so, because MCQ questions are ideal to assess a student’s conceptual knowledge.

Those who want to use the Fractions and Decimals MCQ can use this website to access the online MCQ questions to practise.

Top 5 Benefits of Fractions and Decimals MCQ Class 7

Fractions and Decimals MCQ Class 7 questions benefit students in several ways; however, here we have mentioned a total of 5 benefits that a student will get if they are using the MCQ from NCERT Chapter Fractions and Decimals.

• Helps in Practising Questions: Sometimes, it's hard to get the questions to practise; therefore, the Selfstudys team has curated various sets of MCQ Questions of Class 7 Fractions and Decimals. Having access to the objective questions of Class 7 Fractions and Decimals helps students practising various questions for free of cost.
• Boosts the Critical Thinking Capability: The MCQs or objective questions must be answered in lesser time; therefore, those who will regularly solve Fractions and Decimals MCQ Class 7 will benefit by having a great boost in the critical thinking capability as the questions are in the objective format which can be answered if one has a good command over the concepts of Fractions and Decimals.
• Assists in Covering the Class 7 Maths Syllabus: Fractions and Decimals is a chapter of Class 7 Maths and those who are going to solve the MCQs of Class 7 Fractions and Decimals will be able to practise all the questions as per their Maths Syllabus.
• Helps in Exam Preparation: If a student solves the objective questions from class 7 Fractions and Decimals, they will be able to be prepared for the annual examination too. It is because the questions that are asked in the online MCQ of Fractions and Decimals are asked in the final exam question papers too.
• A Deeper Understanding of Fractions and Decimals: All the important points that are discussed in Fractions and Decimals must be memorised by students as it helps in deepening the understanding of the Delhi Sultans. One of the great benefits of solving Fractions and Decimals MCQ Class 7 is that one can be thorough with the topics and can develop a deeper understanding of Fractions and Decimals chapter of class 7.

Apply These Techniques To Better Answer the MCQ Questions of Fractions and Decimals

Although, there is no wrong or right method to answer the MCQ Questions, those who are interested in knowing the techniques to better answer the MCQ Questions of Fractions and Decimals can follow the below given methods.

Read the Question Carefully:  Questions in Fractions and Decimals MCQ Class 7 can be asked from tricky to hard to understand. In this case, you must read the questions of Fractions and Decimals MCQ carefully. By paying attention to the questions, it will help you connect the dots and assist you recall the studied concepts to answer the MCQs easily.

Eliminate Obviously Wrong Answers:  Many questions of Fractions and Decimals MCQ Class 7 will be so familiar that you can be certain for the wrong answer but uncertain for the right answer, in that situation obviously eliminate wrong answers first. By eliminating irrelevant or incorrect answers, it will help you find the one correct answer from all the given four options.

Look for Clues in the Question:  As we have discussed the first technique is to read the questions carefully, it is vital for looking for the clues in the questions of Fractions and Decimals MCQ Class 7. Every single question contains some kind of clues that help you answer them easily, but due to running out of time many don’t pay attention to it. In order to solve Fractions and Decimals MCQ Class 7 by using this technique you may have to do a thorough practice of Class 7 MCQ Questions.

Use the Process of Elimination:  There is not much difference in the elimination method and eliminating the wrong answer (discussed in point number 2) first, but one difference that makes the elimination process different is you can eliminate the right or wrong answer first. 

This means that when you are confused between two options, you can separate them and then you try to focus on only those 2 options to find out the correct answer of Fractions and Decimals MCQ Class 7. This elimination process works best in most of the scenarios.

Don't Spend too Much Time on One Question:  It is never a good idea to be rigid on one question and spend most of your time answering them. When you are practising Fractions and Decimals MCQ Class 7 questions, you have limited time and you have to make sure that you use your time smartly to attempt all the questions as asked in the Fractions and Decimals Class 7 MCQ.

Double-check your Answer:  Before submitting the Online test of Class 7 Fractions and Decimals MCQ, you should double check your answer if the test time hasn't completed. When you do a double check of your answers, you may find some silly mistakes that you have made due to which you could have lost some marks. Therefore, be conscious and double check your answers before submitting Fractions and Decimals MCQ Class 7.

*As per the Selfstudys Online MCQ Test instructions the time plays a crucial role in calculating your test rank so, be conscious when you use any single minute during your test.

Manage your Time:  Having great time management skills doesn’t only help you quickly answer the questions, but gives you the ability to save time to review the questions or in doing a last minute cross-checking. Thus, when you start solving Fractions and Decimals MCQ Class 7 questions, try to manage time and some of your test time to review the answers you have ticked throughout the test. 

Apart from this, time management skills give you peace of mind and keep you calm.

Stay Calm to Recall Previously Studied Topics:  When you struggle to come up with the correct answer of Fractions and Decimals MCQ Class 7 Questions try to stay calm as it will help you recall previously studied topics. Research says, being calm and relaxed helps in saving energy. Thus, staying calm while solving the MCQ from NCERT Chapter Fractions and Decimals helps you be more focused and answer the questions efficiently. The saved energy can be channelized to increase the focus and concentration to better recall the topics and subtopics of Fractions and Decimals.

There is a high possibility of having more techniques of Fractions and Decimals MCQ Class 7 as mentioned, but these given methods work well in most of the cases.

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NCERT Exemplar Solutions for Class 7 Maths Chapter 2 Fractions and Decimals

NCERT Exemplar Solutions for Class 7 Maths Chapter 2 Fractions and Decimals is the best study material for those students who have difficulties in solving problems. These solutions can help students clear their doubts quickly and also understand the topic effectively. Our expert faculty formulated these solutions to assist them with their exam preparation to attain good marks in the annual exam. Students who wish to score good marks in Maths subject should practise NCERT Exemplar Solutions for Class 7 Maths.

A fraction simply tells us how many parts of a whole we have. You can represent a fraction by the slash that is written in between two numbers. The top number is called the numerator, and the bottom number is called the denominator. A decimal is defined as a fraction whose denominator is a power of ten and whose numerator is expressed by figures placed to the right of a decimal point. NCERT Exemplar Solutions for Class 7 Maths Chapter 2 – Fractions and Decimals PDF are available here. Now, let us have a look at the topics discussed in this chapter.

• Addition, Subtraction, Division and Multiplication of Fractions
• Multiplication of a Fraction by a Whole Number
• Division of Whole Number by a Fraction
• Reciprocal of Fraction
• Division of a Fraction by a Whole Number
• Multiplication and Division of Decimal Numbers

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Access Answers to Maths NCERT Exemplar Solutions for Class 7 Chapter 2 Fractions and Decimals

Exercise Page: 38

In questions 1 to 20, out of four options, only one is correct. Write the correct answer.

(a) 26/25 (b) 52/25 (c) 2/5 (d) 6

First, we have to convert the mixed fraction into an improper fraction

Then, (2/5) × (26/5)

2. 3¾ ÷ ¾ is equal to:

(a) 3 (b) 4 c) 5 (d) 45/16

First, we have to convert the mixed fraction into improper fraction 3¾ = 15/4

Then, 15/4 ÷ ¾

= (15/4)/ (¾)

= (15/4) × (4/3)

= (15 × 4)/ (4 ×3)

= (5 × 1)/ (1 ×1)

3. A ribbon of length 5¼ m is cut into small pieces, each of length ¾m. The number of pieces will be:

(a) 5 (b) 6 (c) 7 (d) 8

First, we have to convert the mixed fraction into improper fraction 5¼ = 21/4

Then, 21/4 ÷ ¾

= (21/4)/ (¾)

= (21/4) × (4/3)

= (21 × 4)/ (4 × 3)

= (7 × 1)/ (1 × 1)

4. The ascending arrangement of (2/3), (6/7), (13/21) is:

(a) 6/7, 2/3, 13/21 (b) 13/21, 2/3, 6/7

(c) 6/7, 13/21, 2/3 (d) 2/3, 6/7, 13/21

(b) 13/21, 2/3, 6/7

LCM of 21, 3, 7 = 21

Now, let us change each of the given fractions into an equivalent fraction having 21 as the denominator.

(13/21) < (14/21) < (18/21)

(13/21) < (2/3) < (6/7)

Hence, the given fractions in ascending order are (13/21), (2/3), (6/7)

5. Reciprocal of the fraction 2/3 is:

(a) 2 (b) 3 (c) 2/3 (d) 3/2

The reciprocal of a non-zero fraction is obtained by interchanging its numerator and denominator.

6. The product of 11/13 and 4 is:

8. Pictorial representation of 3 × 2/3 is:

In the above figure, three circles are divided into 3 equal parts.

Out of 3 equal parts 2 equal parts are hatched.

9. 1/5 ÷ 4/5 equal to:

(a) 4/5 (b) 1/5 (c) 5/4 (d) ¼

= 1/5 ÷ 4/5

= (1/5)/ (4/5)

= (1/5) × (5/4)

10. The product of 0.03 × 0.9 is:

(a) 2.7 (b) 0.27 (c) 0.027 (d) 0.0027

0.03 × 0.9 can be written as = (3/100) × (9/10)

On dividing a decimal by 1000, the decimal point is shifted to the left by three places.

11. (5/7) ÷ 6 is equal to:

(a) 30/7 (b) 5/42 (c) 30/42 (d) 6/7

= 5/7 ÷ 6/1

= (5/7)/ (6/1)

= (5/7) × (1/6)

= 31/6 ÷ 9/2

= (31/6)/ (9/2)

= (31/6) × (2/9)

= (31/3) × (1/9)

13. Which of the following represents 1/3 of 1/6?

(a) (1/3) + (1/6) (b) (1/3) – (1/6)

(c) (1/3) × (1/6) (d) (1/3) ÷ (1/6)

(c) (1/3) × (1/6)

14. 3/7 of 2/5 is equal to

(a) 5/12 (b) 5/35 (c) 1/35 (d) 6/35

3/7 of 2/5 is equal to = (3/7) × (2/5)

(a) less than 30 cups

(b) between 30 cups and 40 cups

(c) between 40 cups and 50 cups

(d) above 50 cups

From the question, it is given that,

One packet of biscuits requires 2½ cups of flour = 5/2

Total ingredients for one packet of biscuits = (5/2) + (5/3)

= (15 + 10)/6

Then, the total quantity of both ingredients used in 10 such packets of biscuits = 10 × (25/6)

= 5 × (25/3)

16. The product of 7 and 6¾ is

(a) 42¼ (b) 47¼ (c) 42¾ (d) 47¾

First, we have to convert the mixed fraction into improper fraction 6¾ = 27/4

= 7 × (27/4)

17. On dividing 7 by 2/5, the result is

(a) 14/2 (b) 35/4 (c) 14/5 (d) 35/2

= 7 × (5/2)

(a) 8/15 (b) 40/3 (c) 40/5 (d) 8/3

= (8/3) ÷ 5

= (8/3)/(5/1)

= (8/3) × (1/5)

19. 4/5 of 5 kg apples were used on Monday. The next day 1/3 of what was left was used. Weight (in kg) of apples left now is

(a) 2/7 (b) 1/14 (c) 2/3 (d) 4/21

4/5 of 5 kg apples were used on Monday = (4/5) × 5

The next day 1/3 of what was left was used = (1/3) × 1

So, the Weight (in kg) of apples left now is = 1 – (1/3)

= (3 – 1)/3

= 2/3 kg of apples

20. The picture

(a) ¼ ÷ 3 (b) 3 × ¼ (c) ¾ × 3 (d) 3 ÷ ¼

From the given picture, ¼ + ¼ + ¼ = ¾

In Questions 21 to 44, fill in the blanks to make the statements true.

21. Rani ate 2/7 part of a cake while her brother Ravi ate 4/5 of the remaining. Part of the cake left is

Rani ate 2/7 part of a cake while her brother Ravi ate 4/5 of the remaining. Part of the cake left is 1/7.

Now, let us assume total part of cake be 1.

Then, from the question, given that Rani ate 2/7 part of a cake = 1 – (2/7)

= (7 – 2)/7

So, Ravi ate 4/5 of the remaining cake = (4/5) × (5/7)

Therefore, the part of the cake left = (5/7) – (4/7)

22. The reciprocal of 3/7 is

The reciprocal of 3/7 is 7/3

23. 2/3 of 27 is

2/3 of 27 is 18.

24. 4/5 of 45 is

4/5 of 45 is 36.

Then, 4 × 19/3

Then, ½ × (30/7)

27. 1/9 of 6/5 is

1/9 of 6/5 is 2/15.

= (1/9) × (6/5)

= (1/3) × (2/5)

Then, (17/7) × (7/9)

29. (4/5) ÷ 4 is equal to

(4/5) ÷ 4 is equal to 1/5.

= (4/5) ÷ 4

= (4/5) × (¼)

= (1/5) × (1/1)

30. 2/5 of 25 is

2/5 of 25 is 10

31. (1/5) ÷ (5/6) = (1/5) (6/5)

(1/5) ÷ (5/6) = (1/5) × (6/5)

While dividing one fraction by another fraction, we multiply the first fraction by the reciprocal of the other.

32. 3.2 × 10 = _______

3.2 × 10 = 32

To multiply a decimal number by 10, we move the decimal point in the number to the right by as many places as many zeros (0) are at the right of one.

33. 25.4 × 1000 = _______

25.4 × 1000 = 25400

To multiply a decimal number by 1000, we move the decimal point in the number to the right by as many places as many zeros (0) are at the right of one.

34. 93.5 × 100 = _______

93.5 × 100 = 9350

To multiply a decimal number by 100, we move the decimal point in the number to the right by as many places as many zeros (0) are at the right of one.

35. 4.7 ÷ 10 = ______

4.7 ÷ 10 = 0.47

To divide a decimal number by 10, shift the decimal point in the decimal number to the left by as many places as there are zeros over 1, to get the quotient.

36. 4.7 ÷ 100 = _____

4.7 ÷ 100 = 0.047

To divide a decimal number by 100, shift the decimal point in the decimal number to the left by as many places as there are zeros over 1, to get the quotient.

37. 4.7 ÷ 1000 = ______

4.7 ÷ 1000 = 0.0047

To divide a decimal number by 1000, shift the decimal point in the decimal number to the left by as many places as there are zeros over 1, to get the quotient.

38. The product of two proper fractions is _______ than each of the fractions that are multiplied.

The product of two proper fractions is less than each of the fractions that are multiplied.

Consider the two proper fractions, 4/5 and 2/4

= (4/5) × (2/4)

Then, 0.4 is multiplied to the proper fraction less than each of the fractions that are multiplied = (4/5) × 0.4

39. While dividing a fraction by another fraction, we _________ the first fraction by the _______ of the other fraction.

While dividing a fraction by another fraction, we multiply the first fraction by the reciprocal of the other fraction.

= (1/5) ÷ (5/6)

= (1/5) × (6/5)

40. 8.4 ÷ = 2.1

8.4 ÷ 4 = 2.1

Let us assume the missing fraction be x,

8.4 ÷ x = 2.1

8.4/x = 2.1

By cross multiplication, we get,

x = 8.4/2.1

41. 52.7 ÷ _______ = 0.527

52.7 ÷ 100 = 0.527

52.7 ÷ x = 0.527

52.7/x = 0.527

x = 52.7/0.527

42. 0.5 _____ 0.7 = 0.35

0.5 × 0.7 = 0.35

While multiplying two decimal numbers, first multiply them as whole numbers. Count the number of digits to the right of the decimal point in both the decimal numbers. Add the number of digits counted. Put the decimal point in the product by counting the number of digits equal to the sum obtained from its rightmost place.

= 0.5 × 0.7

43. 2 (5/3) = 10/3

2 × (5/3) = 10/3

44. 2.001 ÷ 0.003 = __________

2.001 ÷ 0.003 = 667

= 2.001/0.003

In each of the Questions 45 to 54, state whether the statement is True or False.

45. The reciprocal of a proper fraction is a proper fraction.

Consider the proper fraction 5/8.

Then, reciprocal of 5/8 = 8/5.

Therefore the obtained fraction is improper fraction.

46. The reciprocal of an improper fraction is an improper fraction.

Consider the improper fraction 5/3.

Then, the reciprocal of 5/3 = 3/5.

Therefore the obtained fraction is a proper fraction.

47. Product of two fractions = (Product of their denominators)/ (Product of their numerators)

Product of two fractions = (Product of their numerators)/ (Product of their denominators)

48. The product of two improper fractions is less than both the fractions.

The product of two improper fractions is more than each of the fractions that are multiplied.

Consider the two improper fractions, 5/4 and 4/2

= (5/4) × (4/2)

Then, 2.5 is multiplied to the improper fraction more than each of the fractions that are multiplied = (5/4) × 2.5

And (4/2) × 2.5 = 5

49. A reciprocal of a fraction is obtained by inverting it upside down.

Reciprocal of 8/9 = 9/8

50. To multiply a decimal number by 1000, we move the decimal point in the number to the right by three places.

2.5 × 1000 = 2500

51. To divide a decimal number by 100, we move the decimal point in the number to the left by two places.

Example: 3.4/100 = 0.034

52. 1 is the only number which is its own reciprocal.

We know that, if the denominator is not given, then we have to assume 1 always.

So, the reciprocal of 1/1 = 1/1

53. 2/3 of 8 is same as (2/3) ÷ 8

2/3 of 8 = (2/3) × 8

54. The reciprocal of 4/7 is 4/7

The reciprocal of 4/7 is 7/4.

55. If 5 is added to both the numerator and the denominator of the fraction 5/9, will the value of the fraction be changed? If so, will the value increase or decrease?

If 5 is added to both the numerator and denominator of the fraction 5/9 = 10/14

But, 5/9 ≠ 10/14

Yes, the value of the fraction is changed, and also, the value is increased.

56. What happens to the value of a fraction if the denominator of the fraction is decreased while the numerator is kept unchanged?

The value of a fraction is increased when the denominator of the fraction is decreased while the numerator is kept unchanged.

Example: ¼ = 0.25

57. Which letter comes 2/5 of the way among A and J?

There are 10 letters from A to J

So, 2/5 of 10 = 2/5 × 10

The 4 th letter from A to J is D.

Therefore, D comes 2/5 of the way among A and J.

58. If 2/3 of a number is 10, then what is 1.75 times of that number?

2/3 of a number is 10.

Let us assume the number be ‘P’.

2/3 of P = 10

2/3 × P = 10

P = 10 × 3/2

So, the number is 15

Again it is given in the question that, 1.75 times of that number = ?

= 1.75 of 15

= 1.75 × 15

59. In a class of 40 students, 1/5 of the total number of students like to eat rice only, 2/5 of the total number of students like to eat chapati only, and the remaining students like to eat both. What fraction of the total number of students like to eat both?

Number of students in a class = 40 students

1/5 of the total number of students like to eat rice only = 1/5 × 40

= 8 students

2/5 of the total number of students like to eat chapati only = 2/5 × 40

= 16 students

Number of students like to eat both = 40 – (8 + 16)

Fraction of the total number of students like to eat both = 16/40 = 2/5

60. Renu completed 2/3 part of her homework in 2 hours. How much part of her homework had she completed in 1¼ hours?

Renu completed 2/3 part of her homework in 2 hours.

Let us assume the total part of the homework be ‘P’.

2/3 of P = 2

2/3 × P = 2

P = 2 × 3/2

P = 3 homework

So, part of her homework she had completed in 1¼ hours i.e. 5/4 hours

Let us assume part of the homework she had completed in 5/4 hours be = Q

Q of 3 = 5/4

Q × 3 = 5/4

Q = (5/4) × (1/3)

Therefore, Renu completed 5/12 part of her homework in 5/4 hours.

61. Reemu read (1/5) th pages of a book. If she reads further 40 pages, she would have read (7/10) th pages of the book. How many pages are left to be read?

From the question it is given that,

Reemu read (1/5) th pages of a book.

Let us assume the total number of pages in the book be ‘P’.

Then, number of pages read by Reemu = (1/5) of P

= (1/5) × P

And also, it is given in the question, If she reads further 40 pages, she would have read (7/10) th pages of the book. = (7/10) × P

((1/5) × P) + 40 = (7/10) × P

(P + 200)/5 = (7P/10)

By cross mutliplication we get,

2P + 400 = 7P

Then, pages read by Reemu = Total pages – Pages read

P – (7P/10) = (3P/10)

(3/10) × 80

Therefore, 24 pages are left to be read.

Let us assume the missing number be P.

(3/7) × P = 15/98

By cross multiplication we get,

P = (15/98) × (7/3)

P = (5/14) × (1/1)

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Unit 2: Fractions and decimals

Fractions (recap).

• Adding fractions with like denominators (Opens a modal)
• Subtracting fractions with like denominators (Opens a modal)
• Add fractions with common denominators Get 5 of 7 questions to level up!
• Subtract fractions with common denominators Get 5 of 7 questions to level up!

Multiplying fractions

• Intro to multiplying 2 fractions (Opens a modal)
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Fractions word problems

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• Multiply fractions word problems Get 3 of 4 questions to level up!
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Decimals (Recap)

• Visual understanding of regrouping decimals (Opens a modal)
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• Write decimals and fractions shown on number lines Get 3 of 4 questions to level up!
• Adding & subtracting decimals word problems Get 3 of 4 questions to level up!

Multiplying decimals

• Intro to multiplying decimals (Opens a modal)
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• Decimal multiplication place value Get 3 of 4 questions to level up!
• Multiplying decimals like 0.847x3.54 (standard algorithm) Get 3 of 4 questions to level up!

Dividing decimals

• Dividing decimals with hundredths (Opens a modal)
• Dividing by a multi-digit decimal (Opens a modal)
• Dividing decimals: hundredths Get 3 of 4 questions to level up!
• Dividing decimals: thousandths Get 3 of 4 questions to level up!

Decimals word problems

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• Word problems on multiplication and division of decimals Get 3 of 4 questions to level up!

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Home » Fractions and Decimals Class 7 MCQS With Answers – Mathematics Chapter 2 – Free PDF

Fractions and Decimals Class 7 MCQS With Answers – Mathematics Chapter 2 – Free PDF

Update on: 03 Feb 2024, 10:41 AM

NCERT class 7 mathematics chapter 2 – “Fractions and Decimals” teaches us two fractions are multiplied by multiplying their numerators and denominators separately. For the CBSE exams, practice multiple-choice questions (MCQs) to prepare for the objective questions. We have provided Class 7 MCQ Questions on “Fractions and Decimals” paired with comprehensive explanations. CBSE is emphasizing the role of MCQs as they assist in understanding the concepts completely.

As compared to subjective questions, MCQs are very different so practicing and understanding how to get appropriate answers in MCQs is very essential. To revise the main concepts, students should practice all the MCQs with the answers given. This will also help them familiarize themselves with the kinds of questions that might appear in the board exams.

Previous – Integers Class 7 MCQS With Answers

Important – CBSE Class 7 Syllabus For 2024-25 Session

You will also like – Class 7 Math MCQ Question with Answers 

Topics covered in “Fractions and Decimals”

• Multiplication of Fractions
• Multiplication of a Fraction by a Whole Number
• Multiplication of a Fraction by a Fraction
• Division of Fractions
• Division of Whole Number by a Fraction
• Division of a Fraction by a Whole Number
• Division of a Fraction by Another Fraction
• Multiplication of Decimal Numbers
• Multiplication of Decimal Numbers by 10, 100 and 1000
• Division of Decimal Numbers
• Division by 10, 100 and 1000
• Division of a Decimal Number by a Whole Number
• Division of a Decimal Number by another Decimal Number

CBSE Class 7 Mathematics Fractions and Decimals MCQs – PDF Download

Answers – 

Summary for NCERT class 7 mathematics chapter 2 – “Fractions and Decimals”

• Two fractions are multiplied by multiplying their numerators and denominators separately and writing the product as (product of numerators)/ (product of denominators).
• A fraction acts as an operator ‘of.
• The product of two proper fractions is less than each of the fractions that are multiplied.
• The product of a proper and an improper fraction is less than the improper fraction and greater than the proper fraction.
• The product of two improper fractions is greater than the two fractions.
• A reciprocal of a fraction is obtained by inverting it upside down.
• While dividing a whole number by a fraction, we multiply the whole number with the reciprocal of that fraction.
• While dividing a fraction by a whole number we multiply the fraction by the reciprocal of the whole number.
• While dividing one fraction by another fraction, we multiply the first fraction by the reciprocal of the other.
• While multiplying two decimal numbers, first multiply them as whole numbers. Count the number of digits to the right of the decimal point in both the decimal numbers. Add the number of digits counted. Put the decimal point in the product by counting the digits from its rightmost place. The count should be the sum obtained earlier.
• To multiply a decimal number by 10, 100 or 1000, we move the decimal point in the number to the right by as many places as there are zeros over 1.
• To divide a decimal number by a whole number, we first divide them as whole numbers. Then place the decimal point in the quotient as in the decimal number.
• To divide a decimal number by 10, 100 or 1000, shift the digits in the decimal number to the left by as many places as there are zeros over 1, to get the quotient.
• While dividing two decimal numbers, first shift the decimal point to the right by equal number of places in both, to convert the divisor to a whole number. Then divide.

Best Reference Books for Class 7 Mathematics

• NCERT Textbook + Exemplar Problems Solutions Mathematics
• NCERT at your Fingertips Mathematics
• Foundation Course Mathematics
• Practice-cum-Workbook Mathematics
• Integrated Learning Mathematics

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7th Class Mathematics Decimals and Fractions Question Bank

Done fractions and decimals total questions - 40.

question_answer 1) Among 240 students, it was found that three - fourth of the students preferred to play hockey and one-eighth of the students preferred to play cricket. The number of students whole prefer to play hockey and cricket respectively are

A)  180 and 30       done clear

B)  40 and 180      done clear

C)  180 and 40                   done clear

D)  None of these done clear

question_answer 2) In the above example, how many students prefer neither hockey nor cricket?

A)  60                                done clear

B)  50 done clear

C)  40                                done clear

D)  30 done clear

question_answer 3) Which of the following is true with respect to \[\frac{7}{16}\]and\[\frac{12}{7}\]?

A)  \[\frac{7}{16}>\frac{12}{7}\]               done clear

B)  \[\frac{7}{16}=\frac{12}{7}\] done clear

C)  \[\frac{7}{16}<\frac{12}{7}\]      done clear

D)  \[\frac{12}{7}<\frac{7}{16}\] done clear

question_answer 4) Which of the following is the improper fraction form of\[6\frac{1}{6}\] ?

A)  \[\frac{72}{6}\]                         done clear

B)  \[\frac{37}{6}\] done clear

C)  \[\frac{105}{6}\]                       done clear

D)  \[\frac{35}{6}\] done clear

question_answer 5) What is the sum of \[\frac{3}{4},\,\,\frac{7}{6}\]and\[1\frac{3}{5}\] ?

A)  \[3\frac{2}{3}\]                         done clear

B)  \[\frac{422}{120}\] done clear

C)  \[3\frac{23}{60}\]                     done clear

D)  \[\frac{412}{120}\] done clear

question_answer 6) The distance between two cities X and Y is 50 km. Ramesh travels from city X to city Y by scooter with an average speed of 30 km/h. How long will it take him to reach city Y?

A)  \[1\frac{2}{3}h\]       done clear

B)  \[2\frac{1}{3}h\] done clear

C)  \[10h\]                                      done clear

D)  \[20h\] done clear

question_answer 7) The value of the expression\[\left( 2\frac{3}{6}+\frac{4}{9} \right)\]is

A)  \[\frac{19}{2}\]                         done clear

B)  \[\frac{53}{18}\] done clear

C)  \[\frac{17}{2}\]                         done clear

D)  \[\frac{13}{2}\] done clear

question_answer 8) Given that the value of the expression \[\left[ \left( \frac{7}{8}-\frac{2}{5} \right)-\left( \frac{1}{6}+\frac{1}{5} \right) \right]=m\], the value of expression   \[\left[ \left( \frac{7}{8}-\frac{1}{5} \right)-\left( \frac{1}{6}+\frac{2}{5} \right) \right]\]  will be:

A)  Same as m       done clear

B) \[\frac{13}{120}\] done clear

C)  Both A & B                  done clear

D)  Neither A nor B done clear

question_answer 9) Manav took 4 minutes to complete a race comprising three rounds. The time taken to complete the first and the second round is \[\frac{3}{4}\] min and \[1\frac{1}{2}\] min respectively. How much time was taken by Manav to complete the last round?

A) \[2\frac{1}{2}\] min                   done clear

B)  \[3\frac{1}{3}\] min done clear

C)  \[1\frac{3}{4}\]min       done clear

A)  Tea Cup                       done clear

B)  Cereal Bowl    done clear

C)  Drinking Glass   done clear

D)  Lemonade Pitcher done clear

question_answer 11) What is the value of the expression \[\left[ \frac{14}{3}\left( 2\frac{3}{7}-3\frac{1}{6}+1\frac{2}{3} \right) \right]\]?

A)  \[1\frac{1}{2}\]                         done clear

B)  \[2\frac{1}{3}\] done clear

C)  \[3\frac{1}{3}\]                                     done clear

D)  \[4\frac{1}{3}\] done clear

question_answer 12) Rakesh had some amla candies. He gave two third of the total candies to Rajan. One fifth to Sumitra and the remaining candies were given to Prasad. If Rakesh had 90 candies, then how many candies were given to Prasad?

A)  9                                 done clear

B)  13            done clear

C)  14                                done clear

D)  12 done clear

question_answer 13) The decimals 0.919, 9.19, 0.0919, 91.96 and 0.9919 can be arranged in descending order as

A)  \[91.96>0.9919>0.0919>9.19>0.919\] done clear

B)  \[91.96>9.19>0.9919>0919>0.0919\] done clear

C)  \[91.96>0.9919>9.19>0.0919>0.919\] done clear

D)  \[9196>9.19>0.919>0.0919>0.9919\] done clear

question_answer 14) Don Bradman Scored 7996 runs from 80 innings. Sehwag scored 10000 runs from 160 innings. Rahul Dravid scored 13000 runs from 200 innings. Who scored maximum runs per innings?

A)  Don Bradman done clear

B)  Sehwag        done clear

C)  Rahul Dravid                 done clear

D)  Cannot Say done clear

question_answer 15) The missing fraction in the series given below is \[\frac{4}{9},\frac{13}{9},\frac{22}{9},.......,\frac{40}{9}\]

A)  \[\frac{49}{9}\]                         done clear

B)  \[\frac{29}{9}\]           done clear

C)  \[\frac{31}{9}\]                         done clear

question_answer 16) In which of the following does the shaded part represent one fourth of its whole?

A)  3                                 done clear

B)  10             done clear

C)  8                                 done clear

D)  12    done clear

question_answer 18) Devi eats one full bar of chocolate. Then she divided another one into 5 equal parts and eats 3 of them. What is the total number of chocolates that she has eaten?

A)  \[\frac{4}{5}\]                          done clear

B) \[\frac{3}{5}\]             done clear

C)  \[\frac{8}{5}\]              done clear

D) \[\frac{8}{10}\] done clear

question_answer 19) How many one - fourths need to be added to \[1\frac{1}{4}\] to make 5?

B)  4 done clear

C)  11        done clear

D)  15 done clear

question_answer 20) Which of the following is an improper fraction?

question_answer 21) \[0.5\times 0.5\times 0.5\]is equal to

A)  1.25                             done clear

B)  0.0125          done clear

C)  12.5                 done clear

D)  0.125 done clear

A)  \[\frac{0}{2},\frac{2}{2},\frac{7}{5}\]                           done clear

B) \[\frac{0}{1},\frac{2}{1},\frac{7}{5}\]      done clear

C)  \[\frac{0}{0},\frac{2}{2},\frac{7}{5}\]               done clear

question_answer 23) If Ravichandran Ashwin takes 250 wickets for 1321 runs, then his average runs per wicket is (strike rate) is

A)  19                                done clear

B)  13.21           done clear

C)  5.284        done clear

D)  10.6 done clear

question_answer 24) \[2\times 0.2\times 2\times 0.2\times 2\times 0.2\]

A)  0.064       done clear

B)  0.64           done clear

C)  0.0064            done clear

D)  64 done clear

question_answer 25) If the length and breadth of a rectangular field are 120.6 m and 66.26 m respectively, then what is the difference between the length and breadth of the field?

A)  40.34 m           done clear

B)  25.50 m        done clear

C)  54.34 m           done clear

D)  37.16 m done clear

question_answer 26) What is the area of a square whose perimeter is 4.04 cm?                     

A) \[1\text{ }c{{m}^{2}}~\]                     done clear

B)  \[1.021\text{ }c{{m}^{2}}\] done clear

C) \[1.0201\text{ }c{{m}^{2}}\]    done clear

D)  \[1.01\text{ }c{{m}^{2}}~\] done clear

question_answer 27) What is the value of the expression \[\left( 52.3\times 0.13\times 0.001 \right)?\]

A)  0.00305                        done clear

B)  0.006799      done clear

C)  0.016785                      done clear

D)  0.01256 done clear

question_answer 28) Which of the following statements is true? (i) Fractions with the same numerator are called like fractions (ii) Fractions with the same denominator are called like fractions. (iii) Difference of two like fractions\[\text{=}\frac{\text{difference of numerator}}{\text{common denominator}}\] (iv) A fraction with the numerator greater than or equal to the denominator is called a proper fraction.

A)  (i)                                done clear

B)  (i) & (ii)        done clear

C)  (ii) & (iii)      done clear

D)  (iv) & (i) done clear

question_answer 29) Sandeep reads \[\frac{3}{5}\] of a book. He finds that there are still 80 pages left to be read. What is the total number of page in the book?

A)  100                              done clear

B)  200          done clear

C)  300                              done clear

D)  400 done clear

question_answer 30) What should be added to \[\frac{21}{37}\]to make it 1?

A)  \[\frac{26}{37}\]                       done clear

B)  \[\frac{6}{37}\]        done clear

C)  \[\frac{16}{37}\]            done clear

D)  \[\frac{7}{37}\] done clear

question_answer 31) How is the decimal number 10.13 read?

A)  Ten point one three         done clear

B)  One thousand thirteen done clear

C)  Ten point thirteen                  done clear

D)  Ten and thirteen done clear

question_answer 32) What is the decimal equivalent of \[\frac{7}{10}+0+\frac{17}{1000}?\]

A)  0.0717                         done clear

B)  717/1000       done clear

C)  0.717              done clear

D)  0.7017 done clear

question_answer 33) What is the place value of 5 in 10.051?

A)  5                                 done clear

B)  500 done clear

C)  \[\frac{5}{100}\]       done clear

D)  \[\frac{5}{10}\] done clear

question_answer 34) How will you write 7 thousandth?

A)  0.007                           done clear

B)  0.07          done clear

C)  7000                            done clear

D)  700         done clear

question_answer 35) A badminton player won 3 games and lost 2, what fraction of the games did he win?

A)  \[\frac{6}{4}\]                          done clear

B)  \[\frac{4}{6}\] done clear

C)  \[\frac{6}{10}\]             done clear

question_answer 36) Shyamlal had \[\frac{5}{6}\] of a cake. He ate \[\frac{2}{3}\]of it. What part of the total cake did not he not eat?

A)  \[\frac{4}{9}\]              done clear

B)  \[\frac{10}{12}\] done clear

C)  \[\frac{10}{6}\]                         done clear

D)  \[\frac{10}{3}\] done clear

question_answer 37) If \[100-\frac{1}{5}\times R=0,\]then what is the value of R?

B)  \[\frac{1}{5}\]           done clear

C)  \[\frac{199}{5}\]                                   done clear

D)  500 done clear

question_answer 38) Govind travelled a distance of 196.5 km by a train in 3 hours. If the train was moving at uniform speed, what is the speed of the train?

A)  61.5 km/h                     done clear

B)  62.5 km/h       done clear

C)  63.5 km/h                     done clear

D)  65.5 km/h done clear

question_answer 39) By which number should the decimal 8.9 be multiplied with so that the product is 31.15?

A)  2.3                               done clear

B)  1.3            done clear

C)  3.5       done clear

D)  2.5 done clear

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Fractions and Decimals worksheet for class 7

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CBSE worksheets for Fractions and Decimals worksheet for class 7 in PDF for free download. Mathematics worksheets for class 7 CBSE includes worksheets on Fractions and Decimals as per NCERT syllabus. CBSE class 7 worksheets as PDF for free download Fractions and Decimals worksheets. Users can download and print the worksheets on class 7 Mathematics Fractions and Decimals for free.

Download Fractions and Decimals worksheet for class 7

Fractions and decimals   worksheet for class 7 important topics.

• Let’s recal fractions
• Multiplication of Fractions (fraction x whole number & fractionx fraction)
• Division of fractions (whole number/fraction; reciprocal of a fraction; fraction/whole number; fraction/fraction)
• How Well have you learnt about decimal numbers
• Multiplication & Division of Decimal Numbers (decimal x decimal; decimal x whole number; decimal x 10, 100, 1000)
• Word Problems on Fractions and Decimal Numbers

Some important Facts about  Fractions and Decimals   worksheet for class 7

• We have learnt about fractions and decimals alongwith the operations of addition and subtraction on them, in the earlier class.
• We now study the operations of multiplication and division on fractions as well as on decimals.
• We have learnt how to multiply fractions. Two fractions are multiplied by multiplying their numerators and denominators seperately and writing the product as product of numerators product of denominators . For example, 2 5 2 × 5 10 × 3 7 3× 7 21 .
• While dividing a whole number by a fraction, we multiply the whole number with the reciprocal of that fraction.

NCERT class 7   Mathematics Solved Worksheets

• Chapter 1 – Integers
• Chapter 2 – Fractions and Decimals
• Chapter 3 – Data Handling
• Chapter 4 – Simple Equations
• Chapter 5 – Lines and Angles
• Chapter 6 – Practical Geometry
• Chapter 7 – The Triangle and its Properties
• Chapter 8 – Congruence of triangles
• Chapter 9 – Comparing Quantities
• Chapter 10 – Rational numbers
• Chapter 11 – Perimeter and Area
• Chapter 12 – Algebraic Expressions
• Chapter 13 – Exponents and Powers
• Chapter 14 – Symmetry
• Chapter 15 – Visualizing Solid Shapes

CBSE Worksheets for class 7 Mathematics   in PDF

• CBSE 7 Mathematics Integers
• CBSE 7 Mathematics Fractions and Decimals
• CBSE 7 Mathematics Data Handling
• CBSE 7 Mathematics Simple Equations
• CBSE 7 Mathematics Lines and Angles
• CBSE 7 Mathematics The triangle and its properties
• CBSE 7 Mathematics Congruence of triangles
• CBSE 7 Mathematics Comparing Quantities
• CBSE 7 Mathematics Rational Numbers
• CBSE 7 Mathematics Geometry
• CBSE 7 Mathematics Perimeter and Area
• CBSE 7 Mathematics Algebraic Expressions
• CBSE 7 Mathematics Exponents and Powers
• CBSE 7 Mathematics Symmetry
• CBSE 7 Mathematics Visualising solid shapes

MULTIPLICATION OF DECIMAL NUMBERS

Reshma purchased 1.5kg vegetable at the rate of ` 8.50 per kg. How much money should she pay? Certainly it would be ` (8.50 × 1.50). Both 8.5 and 1.5 are decimal numbers. So, we have come across a situation where we need to know how to multiply two decimals. Let us now learn the multiplication of two decimal numbers.

To download Printable worksheets for class 7 Mathematics and Science; do check myCBSEguide app or website. myCBSEguide provides sample papers with solution, test papers for chapter-wise practice, NCERT solutions, NCERT Exemplar solutions, quick revision notes for ready reference, CBSE guess papers and CBSE important question papers. Sample Paper all are made available through  the best app for CBSE students  and myCBSEguide website.

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• Visualising Solid Shapes worksheet for class 7
• Symmetry worksheet for class 7
• Exponents and Powers worksheet for class 7
• Algebraic Expressions worksheet for class 7
• Perimeter and Area worksheet for class 7
• Practical Geometry worksheet for class 7
• Rational numbers worksheet for class 7
• Comparing Quantities worksheet for class 7

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