a += b
a -= b
a *= b
a /= b
a %= b
a &= b
a |= b
a ^= b
a <<= b
a >>= b
++a
--a
a++
a--
+a
-a
a + b
a - b
a * b
a / b
a % b
~a
a & b
a | b
a ^ b
a << b
a >> b
!a
a && b
a || b
a == b
a != b
a < b
a > b
a <= b
a >= b
a[b]
*a
&a
a->b
a.b
a(...)
a, b
(type) a
a ? b : c
sizeof
_Alignof
(since C11)
for Assignment operators |
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Assignment operating on a structure type copies the structure. The left and right operands must have the same type. Here is an example:
Notionally, assignment on a structure type works by copying each of the fields. Thus, if any of the fields has the const qualifier, that structure type does not allow assignment:
See Assignment Expressions .
When a structure type has a field which is an array, as here,
structure assigment such as r1 = r2 copies array fields’ contents just as it copies all the other fields.
This is the only way in C that you can operate on the whole contents of a array with one operation: when the array is contained in a struct . You can’t copy the contents of the data field as an array, because
would convert the array objects (as always) to pointers to the zeroth elements of the arrays (of type struct record * ), and the assignment would be invalid because the left operand is not an lvalue.
C control structure, branch & jump stmt, character set in c programming language.
The C character set, also known as the ASCII character set, is a set of characters that can be used in the C programming language. The term "ASCII" stands for American Standard Code for Information Interchange. Originally developed in the 1960s, ASCII is a widely used character encoding standard that defines numeric codes for various characters.
In the C character set, the basic set of characters consists of 128 characters, including:
Table of content For Character Set | |
---|---|
The uppercase letters | A to Z (65 to 90) |
The lowercase letters | a to z (97 to 122) |
The decimal digits | 0 to 9 (48 to 57) |
Special characters | punctuation marks, spaces, and mathematical symbols |
Control characters | newline, carriage return, and tab |
The ASCII character set is a subset of the Unicode character set, which is a more comprehensive character encoding standard that supports characters from various languages and scripts worldwide. However, for compatibility and historical reasons, the C programming language still primarily relies on the ASCII character set.
In addition to the basic ASCII characters, the C language also defines escape sequences that represent special characters using backslash () followed by a specific character. For example, '\n' represents a newline character, '\t' represents a tab character, and '\' represents a backslash character.
It's worth noting that the C character set has been extended to include additional characters beyond the original ASCII set. This extension is known as the "extended character set" and includes characters with numeric codes greater than 127. The exact set of extended characters may vary depending on the implementation and locale settings of the C programming environment.
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In C++, the char keyword is used to declare character type variables. A character variable can store only a single character.
In the example above, we have declared a character type variable named ch . We then assigned the character h to it.
Note: In C and C++, a character should be inside single quotation marks. If we use, double quotation marks, it's a string.
In C and C++, an integer (ASCII value) is stored in char variables rather than the character itself. For example, if we assign 'h' to a char variable, 104 is stored in the variable rather than the character itself. It's because the ASCII value of 'h' is 104.
Here is a table showing the ASCII values of characters A , Z , a , z and 5 .
Characters | ASCII Values |
---|---|
65 | |
90 | |
97 | |
122 | |
53 |
To learn more about ASCII code , visit the ASCII Chart .
We can get the corresponding ASCII value of a character by using int() when we print it.
We can assign an ASCII value (from 0 to 127 ) to the char variable rather than the character itself.
Note: If we assign '5' (quotation marks) to a char variable, we are storing 53 (its ASCII value). However, if we assign 5 (without quotation marks) to a char variable, we are storing the ASCII value 5 .
Some characters have special meaning in C++, such as single quote ' , double quote " , backslash \ and so on. We cannot use these characters directly in our program. For example,
Here, we are trying to store a single quote character ' in a variable. But this code shows a compilation error.
So how can we use those special characters?
To solve this issue, C++ provides special codes known as escape sequences. Now with the help of escape sequences, we can write those special characters as they are. For example,
Here, \' is an escape sequence that allows us to store a single quote in the variable.
The table below lists escape sequences of C++.
Escape Sequences | Characters |
---|---|
Backspace | |
Form feed | |
Newline | |
Return | |
Horizontal tab | |
Vertical tab | |
Backslash | |
Single quotation mark | |
Double quotation mark | |
Question mark | |
Null Character |
In the above program, we have used two escape sequences: the horizontal tab \t and the new line \n .
Sorry about that.
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I get no error when I type
But when I change it to the following, I get an error: Array type char is not assignable.
Why is array type char not assignable? Is it because the language is written that way on purpose or am I missing a point?
An array is not a modifiable lvalue
The C++ way of doing this, as I commented above, would be to use std::string instead of char[] . That will give you the assignment behavior you're expecting.
That said, the reason you're only getting an error for the second case is that the = in these two lines mean different things:
The first is an initialization, the second is an assignment.
The first line allocates enough space on the stack to hold 10 characters, and initializes the first three of those characters to be 'H', 'i', and '\0'. From this point on, all a does is refer to the position of the the array on the stack. Because the array is just a place on the stack, a is never allowed to change. If you want a different location on the stack to hold a different value, you need a different variable.
The second (invalid) line, on the other hand, tries to change a to refer to a (technically different) incantation of "Hi" . That's not allowed for the reasons stated above. Once you have an initialized array, the only thing you can do with it is read values from it and write values to it. You can't change its location or size. That's what an assignment would try to do in this case.
The language does not allow assigning string literals to character arrays. You should use strcpy() instead:
a is a pointer to the array, not the array itself. It cannot be reassigned.
You tagged with C++ BTW. For that case better use std::string. It's probably more what you're expecting.
Simple, the
is a little "extra feature", as it cannot be done like that on run-time.
But that's the reason for C/C++ standard libraries.
This comes from the C's standard library. If using C++ you should use std::string, unless you really want to suck all the possible performance from your destination PC.
this is because initialization is not an assignment. the first thing which works is an initialization, and the second one, which does not work, as expected, is assignment. you simply cant assign values to arrays you should use sth like strcpy or memcpy . or you can alternatively use std::copy from <algorithm>
It is so simple,(=) have two different mean assignment and initialization. You can also write your code like that
in this code you have no need to write a difficult code or function and even no need of string.h
COMMENTS
That's why assigning a char gives you a warning, because you cannot do char* = char. But the assignment of "H", works, because it is NOT a char - it is a string ( const char* ), which consists of letter 'H' followed by terminating character '\0'. This is char - 'H', this is string ( char array) - "H". You most likely need to change the ...
In C, string literals such as "123" are stored as arrays of char (const char in C++). These arrays are stored in memory such that they are available over the lifetime of the program. Attempting to modify the contents of a string literal results in undefined behavior; sometimes it will "work", sometimes it won't, depending on the compiler and ...
C Programming Strings. In C programming, a string is a sequence of characters terminated with a null character \0. For example: char c[] = "c string"; When the compiler encounters a sequence of characters enclosed in the double quotation marks, it appends a null character \0 at the end by default. Memory Diagram.
C uses char type to store characters and letters. However, the char type is integer type because underneath C stores integer numbers instead of characters.. To represent characters, the computer has to map each integer with a corresponding character using a numerical code. The most common numerical code is ASCII, which stands for American Standard Code for Information Interchange.
The type of both the variables is a pointer to char or (char*), so you can pass either of them to a function whose formal argument accepts an array of characters or a character pointer. Here are the differences: arr is an array of 12 characters. When compiler sees the statement: char arr[] = "Hello World";
Use String Assignment to Initialize a char Array in C. Another useful method to initialize a char array is to assign a string value in the declaration statement. The string literal should have fewer characters than the length of the array; otherwise, there will be only part of the string stored and no terminating null character at the end of the buffer.
Syntax of Declaring Character Variable in C. char variable_name; Here char is used for declaring Character data type and variable_name is the name of variable (you can use any name of your choice for example: a, b, c, alpha, etc.) and ; is used for line terminator (end of line).
Computer. To declare a Char variable in C, you simply use the char keyword, followed by the name of the variable. You can optionally initialize it at the same time. For example: char myChar; // Declaration without initialization. char anotherChar = 'B'; // Declaration with initialization.
The single characters are surrounded by single quotation marks. The examples below are all chars - even a number surrounded by single quoation marks and a single space is a char in C: 'D', '!', '5', 'l', ' ' Every single letter, symbol, number and space surrounded by single quotation marks is a single piece of character data in C.
Assignment Operators in C - In C language, the assignment operator stores a certain value in an already declared variable. ... f = 5; // definition and initializing d and f. char x = 'x'; // the variable x has the value 'x'. Once a variable of a certain type is declared, it cannot be assigned a value of any other type. In such a case the C ...
A character pointer stores the address of a character type or address of the first character of a character array ( string ). Character pointers are very useful when you are working to manipulate the strings. There is no string data type in C. An array of "char" type is considered as a string. Hence, a pointer of a char type array represents a ...
In C programming String is a 1-D array of characters and is defined as an array of characters. But an array of strings in C is a two-dimensional array of character types. Each String is terminated with a null character (\0). It is an application of a 2d array. Syntax: char variable_name[r][c] = {list of string};Here, var_name is the name of the var
However, the char type is integer type because underneath C stores integer numbers instead of characters.In C, char values are stored in 1 byte in memory,and value range from -128 to 127 or 0 to 255. In order to represent characters, the computer has to map each integer with a corresponding character using a numerical code. The most common ...
It is a nameless, read-only char array. So the correct definition of a would actually be: 1. 2. const char * a = "some text"; // read as: `a` is a pointer to const char. You can take the memory address of the string literal "some text", but you may not change its contents. With that out of the way, you probably wanted to define a char array.
Assignment performs implicit conversion from the value of rhs to the type of lhs and then replaces the value in the object designated by lhs with the converted value of rhs . Assignment also returns the same value as what was stored in lhs (so that expressions such as a = b = c are possible). The value category of the assignment operator is non ...
15.13 Structure Assignment. Assignment operating on a structure type copies the structure. The left and right operands must have the same type. Here is an example: Notionally, assignment on a structure type works by copying each of the fields. Thus, if any of the fields has the const qualifier, that structure type does not allow assignment:
Because in C arrays are not modifiable lvalues. So you can either initialize the array: char k[25] = "Dennis"; or, use strcpy to copy: strcpy(k, "Dennis"); If you actually have no need for an array, you can simply use a pointer that points to the string literal. The following is valid:
The C character set, also known as the ASCII character set, is a set of characters that can be used in the C programming language. The term "ASCII" stands for American Standard Code for Information Interchange. Originally developed in the 1960s, ASCII is a widely used character encoding standard that defines numeric codes for various characters.
const char * const p - The pointer p is constant and so are the characters that p points to - i.e. cannot change both the pointer and the contents to what p points to. const char * p - p points to constant characters. You can change the value of p and get it to point to different constant characters. But whatever p points to, you cannot change ...
ASCII Value. In C and C++, an integer (ASCII value) is stored in char variables rather than the character itself. For example, if we assign 'h' to a char variable, 104 is stored in the variable rather than the character itself. It's because the ASCII value of 'h' is 104.. Here is a table showing the ASCII values of characters A, Z, a, z and 5.
char a[10] = "Hi"; a = "Hi"; The first is an initialization, the second is an assignment. The first line allocates enough space on the stack to hold 10 characters, and initializes the first three of those characters to be 'H', 'i', and '\0'. From this point on, all a does is refer to the position of the the array on the stack.