A commonly used experiment to show the effect of concentration on rate is between dilute hydrochloric acid and sodium thiosulfate solution.
Na S O (aq) + 2HCl(aq) (g) + S(s) + H O(l)
At this stage, the only place you are likely to come across sodium thiosulfate is in this reaction.
The interesting thing about the reaction is the formation of a precipitate of sulfur. This is formed slowly and appears first as a very pale cream solid which turns yellow as more of it is formed.
In the video you are going to watch, the time taken to form a very small fixed amount of sulfur is measured at various concentrations of sodium thiosulfate, keeping everything else the same.
As you will see, the more dilute the sodium thiosulfate, the longer the time it takes for that amount of sulfur to form.
The is the one that changes as a result of something you are doing. In this case, the dependent variable is the time taken for the cross to disappear, because that is changing as a result of you changing the concentration.
The is the one that you are changing - in this case, the concentration.
The independent variable is always plotted on the x-axis, and the dependent one on the y-axis. The video showed a graph of the results of time taken against concentration and looked like this.
As it stands, this isn't actually very helpful. All it shows is that as you increase the concentration, the time taken for the cross to disappear gets less. But you can see that just by looking at it.
It would be much better if we could find a more precise relationship between the rate of the reaction and the concentration.
If you have read the page about the effect of on rates of reaction, you will have read about "initial rate" experiments. This is another initial rate experiment.
You are finding the time taken for a very small amount of sulfur to be produced at the very beginning of the reaction as you vary concentration.
If you could do a complete plot of the mass of sulfur being formed against time, you would get a curve starting steeply, slowing down, and then stopping - exactly like the one you saw on the previous page.
But at the very beginning of the reaction, the curve is almost a straight line. So if you consider plots of the very early parts of three reactions to produce a fixed mass of sulfur in this experiment, the graphs would look like this.
The initial rates would be m/t , m/t and m/t grams of sulfur per second.
You don't know what m is of course - that would depend, amongst other things, on how thick your cross was, and how good your eyesight is. But it is always going to be the same in every experiment.
What you can say is that the initial rate is proportional to 1/t - or inversely proportional to t, if you prefer.
If it takes half as long for the cross to disappear, the rate is twice as fast; if it takes 4 times as long for the cross to disappear, the rate is only a quarter as fast.
On a graph, we can use this by plotting 1/t as a measure of rate. It isn't an actual rate, but it allows you to compare rates.
Doing this shows that in this reaction, you have a straight line relationship between concentration and rate - rate is proportional to concentration.
Required practical 5, core practicals.
How does the concentration of an acid affect the rate of reaction?
In this experiment you will:
How does the concentration of sodium thiosulphate affect the rate of reaction?
As a general rule, eye protection (goggles) must be worn for all practicals.
hazard | possible harm | precaution |
---|---|---|
hydrochloric acid | skin and eye irritation | avoid contact with the skin |
gases escaping from reaction | may damage skin and eyes | place cotton wool at opening of conical flask to minimse gas escape |
hot sodium thiosulfate solution | burns to the skin | do not heat above 60°C |
sulfur dioxide | irritation to the eyes and lungs, particularly to people with asthma | lab needs to be well ventilated |
This risk assessment is provided as an example only, and you must perform your own risk assessment before doing this experiment.
magnesium strips hydrochloric acid (3 concentrations) 250 ml conical flask 100 ml gas syringe
water bath sodium thiosulfate 50 ml measuring cylinder stop clock or stopwatch 10 ml measuring cylinder
time (s) | volume of gas produced (ml) | ||
---|---|---|---|
0.5 mol/dm | 1.0 mol/dm | 1.5 mol/dm | |
0 | 0 | 0 | 0 |
20 | |||
... |
For each concentration plot a graph on the same set of axes to show:
Use your graph to compare the rates of reaction with different concentrations of hydrochloric acid with magnesium. Use collision theory to explain your findings.
concentration (g/dm ) | time for cross to disappear (s) | ||
---|---|---|---|
trial 1 | trial 2 | mean | |
8 | |||
16 | |||
... |
Plot a graph to show:
Describe the relationship between the independent variable and the dependent variable? What were your control variables? Evaluate the two methods that you have used to investigate the effect of concentration on rate of reaction.
A chemical company makes calcium chloride by reacting calcium carbonate and hydrochloric acid. They think they can increase the rate of reaction by increasing the concentration of the acid. Describe an experiment they could do in a laboratory to be able to test this idea.
Add calcium carbonate powder to a conical flask. Pour hydrochloric acid into the flask, mix, and immediately attach a gas syringe. Measure how much gas has been produced every 20 seconds, and record in a table. Compare the results to find out which reaction has a faster rate.
Add calcium carbonate powder to a conical flask. Pour hydrochloric acid into the flask, mix, and immediately attach a gas syringe. Measure how much gas has been produced every 20 seconds, and record in a table. Repeat these steps with other concentrations of hydrochloric acid as well (keep the volume the same). Compare the results to find out which reaction has a faster rate.
Add 5 g of calcium carbonate powder to a conical flask. Using a measuring cylinder, pour and mix 20 ml of 0.5 mol/dm 3 hydrochloric acid into the flask, and immediately attach a gas syringe. Measure how much gas has been produced every 20 seconds, and record in a table. Repeat these steps with 1.0 mol/dm 3 and 1.5 mol/dm 3 hydrochloric acid as well (keeping the temperature, volume of acid the same, and the mass of the calcium carbonate the same). Calculate the rate of each reaction (volume ÷ time), and compare the results to find out which reaction has a faster rate.
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Publication 91860
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The purpose of this demonstration is to investigate the effect of sodium thiosulfate concentration on the rate of reaction of sodium thiosulfate with hydrochloric acid. The reaction, which produces solid sulfur, will be followed by measuring the time needed for the reaction mixture to become opaque. The results will be analyzed graphically to determine the order of reaction—the mathematical relationship between the reactant concentration and the rate.
Whether you are introducing collision theory or something more demanding like reaction order, the reaction between sodium thiosulfate—Na 2 S 2 O 3 and hydrochloric acid can provide a consistent, accurate, and engaging opportunity for investigating these topics.
A few weeks ago, I was looking for a new reaction that could be used to investigate how concentration affects reaction time. In the past, I had always used traditional reactions such as magnesium and hydrochloric acid or Alka-Seltzer and hydrochloric acid. Though both served their purpose, there would always be groups that didn’t quite get data that was consistent with what I knew the relationship to be. In most cases, this was due to ambiguous and inconsistent timing methods or simply a matter of experimental error like not ensuring the magnesium stayed in the acid without floating to the top. I wanted a reaction that would be more likely to produce consistent results from group to group, easy to execute, and was a bit more exciting than waiting for magnesium or Alka-Seltzer to disappear.
Eventually, I came across a Flinn 1 experiment which focused on the reaction between sodium thiosulfate and hydrochloric acid.
Na 2 S 2 O 3 (aq) + HCl (aq) → 2NaCl (aq) + S (s) + H 2 O (l) + SO 2 (g)
What I liked most about this reaction was the easy and consistent timing mechanism it provided my students with, which could eliminate the ambiguity and differences in timing approaches that lab groups had used in the past.
Here’s how: As the reaction proceeds, one of the products is sulfur. As more sulfur gets produced, the solution becomes more and more cloudy until eventually the solution is opaque. Because of this, the moment that you can no longer see through the solution can be used as a consistent way to stop time. When I asked my students how we would all consistently decide on when the solution is opaque, many of them suggested to place some sort of object on the other side of the beaker so that we would all stop the timer when the object was no longer visible. This naturally progressed to the idea of drawing something on the beaker itself (an X on the bottom in this case) and applying the same reasoning.
This reaction and the implementation of this natural clock can be seen below in a Flinn video 2 .
Even though it is just a matter of changing from visible to opaque, I noticed that the anticipation of waiting for that X to disappear had nearly all my students hovering over their beakers anxiously waiting to stop their timer. It even got to a point where different groups started to use their phones to make time lapse videos of their reaction beakers. You can see one below. As a teacher, it was fun to watch their level of excitement over something so seemingly simple.
Though I used this experiment to primarily investigate collision theory and different factors that affect the time it takes for a reaction to complete, it could easily be used to determine something more complex like reaction order ( see the entire Flinn video from which the above clip is taken ).
I also found this lab to serve as a great opportunity for my students to play a larger role in the creation of the experimental setup since there wasn’t much complexity to it. I facilitated the design of the experiment by asking my students a series of questions that were meant to feel like it was a genuine conversation happening between scientists interested in answering a question. The PowerPoint that I used to help facilitate this discussion can be found as Supporting Information at the bottom of this post if you are logged in to ChemEd X, but the general theme followed these questions:
I don’t include students in things like this often enough and it’s important that I continue to remind myself the beneficial experience this can provide for students to get a more accurate understanding of how science operates.
However you decide to do it, the general approach to this experiment goes something like this:
1) Using a Sharpie, draw a black X on the bottom (outside) of each beaker. 2) A stock solution of 0.15 M Na 2 S 2 O 3 is used to make 5 different concentrations using different amounts of distilled water, though our tap water worked just fine too. The total volume of each solution should be the same in each beaker. 3) Add 5 mL of 2 M HCl to your first beaker to start the reaction. You can give it an initial stir to uniformly distribute the HCl. The timer starts after this initial swirl. 4) While looking down at the beaker, stop the timer the moment you see the X completely disappear from sight. 5) Do this for all your samples and start analyzing your data
After everyone had finished the experiment and analyzed their results, I was thrilled to see that the data from each group produced a graph that displayed the relationship I was looking for. Not a single group had one weird outlier or a graph with seemingly random points all over the place! Some of the groups even paid close enough attention to the fact that each beaker had different levels of “opaqueness” to them. This provided a great opportunity to talk about the benefits of qualitative evidence as well. I attribute these consistent results to two primary things:
1) Consistent timing mechanism that each group can easily reproduce 2) It is almost impossible to mess up this reaction—you’re just pouring HCl into your Na 2 S 2 O 3 solution. Minimizing chances for experimental error was huge.
Though I don’t always shoot for consistent data between groups when we do a lab, I knew that the arguments would vary between groups when trying to explain why their experiment displayed the relationship it did. It is the arguments I am most interested in developing after students complete their data analysis.
Students were tasked with developing their initial argument using a Claim, Evidence, Reasoning (CER) framework. Though most boards had similar claims, they often differed in what evidence they chose to present. They all had access to the same evidence and yet different groups intentionally left out certain pieces of evidence—why? Where their boards differed the most was in their reasoning, which is meant to have them justify why their evidence makes sense based on known scientific principles. I should mention that the students had not been presented anything about collision theory before this lab and yet many of them were able to come up with a valid particle-based explanation while others either circled around ambiguity, lacked detail, or simply displayed some form of misconception. The important part of this was that they tried their best, based on the models they had running around in their heads, to explain the phenomenon and knew that it was up to the scientific community (our class) to act as a filter for sorting out valid explanations from ones that either lacked detail or could not quite account for the evidence. This is the process I love doing the most.
The lab itself took about 30 mins to do but because I involved them in the experimental setup and dedicated time to construct arguments that were presented, debated, and refined, the entire process took 3 periods (1 hr each).
I want to thank Flinn for inspiring the idea for the experiment in the first place and NSTA’s book Argument-Driven Inquiry in Chemistry 3 for providing the framework we used to set up and make sense of the investigation.
Resources 1 Rate of Reaction of Sodium Thiosulfate and Hydrochloric Acid . N.p.: Flinn Scientific, n.d. Pdf . https://www.flinnsci.com/globalassets/flinn-scientific/all-free-pdfs/dc91860.pdf 2 "Rate of Reaction of Sodium Thiosulfate and Hydrochloric Acid..."20 Dec. 2012, & https://www.youtube.com/watch?v=r4IZDPpN-bk . Accessed 17 Jan. 2017. 3 "NSTA Science Store: Argument-Driven Inquiry in Chemistry: Lab ...." 1 Oct. 2014, https://www.nsta.org/store/product_detail.aspx?id=10.2505/9781938946226 . Accessed 17 Jan. 2017.
For Laboratory Work: Please refer to the ACS Guidelines for Chemical Laboratory Safety in Secondary Schools (2016) .
For Demonstrations: Please refer to the ACS Division of Chemical Education Safety Guidelines for Chemical Demonstrations .
RAMP : Recognize hazards; Assess the risks of hazards; Minimize the risks of hazards; Prepare for emergencies
Analyzing data in 9–12 builds on K–8 and progresses to introducing more detailed statistical analysis, the comparison of data sets for consistency, and the use of models to generate and analyze data.
Analyzing data in 9–12 builds on K–8 and progresses to introducing more detailed statistical analysis, the comparison of data sets for consistency, and the use of models to generate and analyze data. Analyze data using tools, technologies, and/or models (e.g., computational, mathematical) in order to make valid and reliable scientific claims or determine an optimal design solution.
Asking questions and defining problems in grades 9–12 builds from grades K–8 experiences and progresses to formulating, refining, and evaluating empirically testable questions and design problems using models and simulations.
questions that challenge the premise(s) of an argument, the interpretation of a data set, or the suitability of a design.
Scientific questions arise in a variety of ways. They can be driven by curiosity about the world (e.g., Why is the sky blue?). They can be inspired by a model’s or theory’s predictions or by attempts to extend or refine a model or theory (e.g., How does the particle model of matter explain the incompressibility of liquids?). Or they can result from the need to provide better solutions to a problem. For example, the question of why it is impossible to siphon water above a height of 32 feet led Evangelista Torricelli (17th-century inventor of the barometer) to his discoveries about the atmosphere and the identification of a vacuum.
Questions are also important in engineering. Engineers must be able to ask probing questions in order to define an engineering problem. For example, they may ask: What is the need or desire that underlies the problem? What are the criteria (specifications) for a successful solution? What are the constraints? Other questions arise when generating possible solutions: Will this solution meet the design criteria? Can two or more ideas be combined to produce a better solution?
Constructing explanations and designing solutions in 9–12 builds on K–8 experiences and progresses to explanations and designs that are supported by multiple and independent student-generated sources of evidence consistent with scientific ideas, principles, and theories.
Constructing explanations and designing solutions in 9–12 builds on K–8 experiences and progresses to explanations and designs that are supported by multiple and independent student-generated sources of evidence consistent with scientific ideas, principles, and theories. Construct and revise an explanation based on valid and reliable evidence obtained from a variety of sources (including students’ own investigations, models, theories, simulations, peer review) and the assumption that theories and laws that describe the natural world operate today as they did in the past and will continue to do so in the future.
Modeling in 9–12 builds on K–8 and progresses to using, synthesizing, and developing models to predict and show relationships among variables between systems and their components in the natural and designed worlds.
Modeling in 9–12 builds on K–8 and progresses to using, synthesizing, and developing models to predict and show relationships among variables between systems and their components in the natural and designed worlds. Use a model to predict the relationships between systems or between components of a system.
Science practice: obtaining, evaluating, and communicating information.
Engaging in argument from evidence in 9–12 builds on K–8 experiences and progresses to using appropriate and sufficient evidence and scientific reasoning to defend and critique claims and explanations about natural and designed worlds. Arguments may also come from current scientific or historical episodes in science.
Engaging in argument from evidence in 9–12 builds on K–8 experiences and progresses to using appropriate and sufficient evidence and scientific reasoning to defend and critique claims and explanations about natural and designed worlds. Arguments may also come from current scientific or historical episodes in science. Evaluate the claims, evidence, and reasoning behind currently accepted explanations or solutions to determine the merits of arguments.
Planning and carrying out investigations in 9-12 builds on K-8 experiences and progresses to include investigations that provide evidence for and test conceptual, mathematical, physical, and empirical models.
Planning and carrying out investigations in 9-12 builds on K-8 experiences and progresses to include investigations that provide evidence for and test conceptual, mathematical, physical, and empirical models. Plan and conduct an investigation individually and collaboratively to produce data to serve as the basis for evidence, and in the design: decide on types, how much, and accuracy of data needed to produce reliable measurements and consider limitations on the precision of the data (e.g., number of trials, cost, risk, time), and refine the design accordingly.
Students who demonstrate understanding can apply scientific principles and evidence to provide an explanation about the effects of changing the temperature or concentration of the reacting particles on the rate at which a reaction occurs.
*More information about all DCI for HS-PS1 can be found at https://www.nextgenscience.org/dci-arrangement/hs-ps1-matter-and-its-interactions and further resources at https://www.nextgenscience.org .
Assessment is limited to simple reactions in which there are only two reactants; evidence from temperature, concentration, and rate data; and qualitative relationships between rate and temperature.
Emphasis is on student reasoning that focuses on the number and energy of collisions between molecules.
Comments 11.
This is awesome. I found this lab to be very useful too, and appreciate how you've shared how it's run in your classroom.
Thanks! Glad I came across it and was able to reflect/share.
I thoroughly enjoyed reading your reflections on this activity. I use a microscale version of this reaction in my AP Chemistry class and have students calculate the order of reaction with respect to thiosulfate and hydrochloric acid. It is a very reliable procedure and the students enjoy the lab for the reasons you've discussed.
I usually don't touch on kinetics in my first year course, but this year while I was teaching it I realized that the theory of kinetics (collision theory, activation energy, catalysts, decrease of rate with time) is very accessible to first year students who have a firm grasp of the particulate nature of matter. Thank you for posting how you went through this with them, I plan on giving it a shot in my chemical reactions unit that will now include basic kinetic theory.
Thank you for sharing this lab! I am a new teacher and really appreciate such good resources.
One question: In my textbook (Chemistry by Whitten, Davis, Peck, Stanley), the integrated rate laws use ln [A]0- ln [A]= a kt. So when working textbook problems, I've had the students use the coefficient in calculations. However, I noticed in the AP FRQ a is not included (such as 2004B #3) and a is not included in the given equations. I am confused on what is the correct method and how I should be teaching this. I would appreciate any clarification.
Hi Beverly,
I have a coppy of the 10th edition of Whitten (though I do not use it) and it does indeed use " a " for the coefficient from the balanced equation. This is new to me and I have not seen it before. However it makes sense if you look at how they set up the integration compared to other sources.
Method 1: The rate of reaction of a first order reaction A --> Products is defined as Rate = -d[A]/dt = k [A]. This assumes A has a coefficient of 1.
Method 2: The Whitten text defines the same thing, but uses the reaction a A --> Products as the model. This leads to Rate = (1/ a )(-d[A]/dt). This affects the value of k in Rate = k [A] and the inclusion of a in the integrated rate law.
k (the "rate constant") is simply a proportionality constant, it's value just depends on how you define it. If we say that k = ak' then if you're asked to calculate "the rate constant of the reaction" and use Method 1 exclusively then you are solving for k . If you take in to account the stoichiometry, you are solving for k' .
Given the prevelance of not including a I would assume that "the rate constant" is widely considered by chemists to be the value obtained via Method 1.
Now for your concerns about practice in AP Chemistry.
This area of possible confusion have only come up twice to my knowledge. Once in 2008 #3 and once in 2016 #5. In both situations the graders accepted either value for k . The scoring guidelines for both exams are here:
2008 Scoring Guidelines
2016 Scoring Guidelines
The forumula included on the formula chart, combined with the precedent of these two equations leads me to belive that either method will be accepted unless a more specific question were asked.
I hope this helps.
As defined by the International Union on Pure and Applied Chemistry, reaction rate depends on stoichiometry. You can find the defnition here: https://goldbook.iupac.org/html/R/R05156.html . So, if the reaction is aA --> products, the rate is defined as -(1/a)(d[A]/dt). This affects the integration, and therefore the integrated rate law, just as Kaleb says.. If the stoichiometry is A --> products, then a does not appear in the integrated rate law but only because a = 1. It appears that the AP folks allowed for both of these possibilities, which seems reasonable to me.
The version with a included is more general and gives the other version when a = 1. The distinction is important when rate constants are reported in a published paper because if the stoichiometric coefficient a is not included the rate constant value will be off by a factor of a. However, the distinction seems a lot less important when students are learning this for the first time.
I did want to clarify that the version with a included is the version that most chemists who do kinetics studies would say is correct.
Thank you for your response and link to the Gold Book! I am glad to know that the chemistry community does have a a published, accepted standard for this (and that I was incorrect in my assertion). I agree that the distinction seems less imporant for first-time students, I am curious if this is the reasoning of the AP Test Development Committee as well and am going to reach out to see.
Hey Beverly,
I don't teach AP so I don't want to suggest a "correct method" but here's what I'm thinking based on my own limited knowledge of integrated rate laws.
The short answer: I don't think the coefficient ( a ) is necessary.
Why I think a isn't necessary: I think your answer can be found in the difference between differential rate laws and integrated rate laws--at least it helped me understand it better. Resource here
Differential rate laws express the rate of reaction as a function of a change in the concentration of one or more reactants over a particular period of time, they are used to describe what is happening at the molecular level during a reaction (mechanism-focused).
On the other hand, integrated rate laws express the reaction rate as a function of the intial concentration and a measured (actual) concentration of one or more reactants after a sepcific amount of time has passed--they are used to determine the rate constant and the reaction order from experimental data.
To me, that means that because the order of a reaction is determined experimentally, they do not represent the coefficients from a balanced equation like they would for an equilibrium expression. In other words, the expression used for a rate law generally bears no relation to the reaction equation, and must be determined experimentally (Resource here )
I hope that helped somewhat. There are several people on this site that would be most likely provide a much easier answer so I can reach out to others if this didn't help. If nothing else, I got to brush up on topics I haven't dealt with for some time!
I checked my chemical inventory and found that I only have the hydrate. Do you think it would work?
It will work. Just make sure you account for the added mass from water when making your solutions of desired concentration.
Great minds think alike. I posted a video post about 1.5 weeks before on this same topic.
https://www.chemedx.org/blog/disappearing-x-lab
I plan on reading your post more in depth tonight during conferences if time allows. I don't do much modeling or CER although more of this may show up as we revamp our chemistry 1 curriculum to comply with our updated state science standards.
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Find a solution
Observe how the concentration of sodium thiosulfate solution affects its rate of reaction with hydrochloric acid
The value of experiencing live practical work cannot be overstated. Numerous studies provide evidence of its value in terms of learner engagement, understanding, results and the likelihood of continuing to study chemistry or work in a related field.
Use this video to complement live practical work, or to help learners understand the methods, equipment and skills when they cannot access the lab.
Source: © Royal Society of Chemistry
Investigate rates of reaction (observing a colour change) using this video, including a step-by-step method, calculation support for learners and evaluation
Chapter titles: 00:09 Introduction to rates of reaction; 01:34 Carrying out the experiment; 05:45 Calculations; 07:40 Evaluating the method.
Full teacher notes are available in the supporting resources booklet (also available in MS Word ), including ideas for how to use this video and the accompanying activites and answers to use as part of your teaching.
Detailed teacher notes, learner activities and answers
Integrated instructions, Frayer model and Johnstone's triangle
Equipment, chemicals, hazards and disposal information
Ask learners to work in pairs. Demonstrate how to set up the equipment first (either in-person or via the video) to emphasise health and safety issues. Remind learners that they must wear eye protection and direct them to the relevant student safety sheets (SSS).
It is important that all learners have access to a stop bath to dispose of their waste products as sodium thiosulfate solution ( SSS034 ) reacts with hydrochloric acid ( SSS020 ) to toxic produce sulfur dioxide gas. Explain that the stop bath is a solution of sodium carbonate/hydrogen carbonate ( SSS033 ) with an acid–base indicator such as phenolphthalein ( SSS070 ). It neutralises any remaining acid and the sulfur dioxide reacts with the water to produce sulfuric acid. If the indicator is showing the acidic colour, refresh the stop bath by adding more sodium carbonate solution. Ensure the room is well ventilated. A microscale version of the experiment is available from CLEAPSS.
Teaching rates of reaction at 16–18 too? Watch the practical video to show learners how to monitor the rate of reaction and identify the effects of changing temperature and concentration, using both initial rate and continuous monitoring methods. Plus, download the resources for teacher and technician notes, follow-up worksheets and more.
Read our standard health and safety guidance and carry out a risk assessment before running any live practical. Refer to SSERC/CLEAPSS Hazcards, recipe books and student safety sheets. Hazard classification may vary depending on supplier. Download the technician notes for the full equipment list, safety notes and disposal information.
Measure 10 cm 3 of sodium thiosulfate and pour it into the conical flask.
Measure 40 cm 3 of distilled water and add it to the conical flask.
Place the flask on the black cross.
Using a clean measuring cylinder, measure 10 cm 3 of hydrochloric acid.
Add the acid to the flask, start the stop clock and swirl.
Place the watch glass on top of the flask to limit breathing in sulfur dioxide gas.
Time how long it takes until you can no longer see the black cross. Look at the cross from a distance of at least 20 cm above the top of the flask.
Repeat the method using 20, 30, 40 and 50 cm 3 of sodium thiosulfate solution with 30, 20, 10 and 0 cm 3 of distilled water.
Find the integrated instructions for this experiment in the PowerPoint slides .
Learners will need to have a clear understanding of the following scientific terminology:
You will find a template, example Frayer model and suggested answers for the term ‘collision theory’ in the PowerPoint slides . Find more examples and tips on how to use Frayer models in your teaching.
Difficulties related to chemical change.
Learners can struggle to form a full answer including:
There is a lot going on here, so it is important to provide a clear scaffold for learners. Initially, the use of a structure strip (see the example and suggested answer in the supporting resources ) will help, followed by plenty of practice providing learners with similar but slightly different questions.
There are several misconceptions around the understanding of catalysts including:
Be careful with your language. The definition in some pre-16 specifications eg ‘catalysts change the rate of reaction but are not used up during the reaction’ can lead to misconceptions if the definition is not carefully unpacked and linked to the reaction profile, showing an alternative reaction pathway with a lower activating energy. This 5-minute demonstration clearly shows the catalyst is involved in the reactions as the colour changes from pink to green and back to pink.
This practical activity provides the opportunity to develop several ‘working scientifically’ skills and mathematical skills including:
If asked to draw another line on a graph (eg, volume of gas produced (y-axis) versus time (x-axis)) learners can struggle to know how to draw it. Should the start go up more steeply? Where does it plateau? Encourage learners to tell the story of their graph. Linking what is happening in the reaction vessel and their observations to what the graph is showing. Using a Johnstone’s triangle approach can also help here. Download the PowerPoint slides for an example and suggested answers.
Many learners find this challenging and depending on when you teach rates, they may be meeting the concept for the first time. Talk to your maths colleagues to find out when they teach tangents.
Rates of reaction technician notes, rates of reaction slides, additional information.
The original video script, supporting resources and slides were written by Dorothy Warren. The technician notes were adapted by Sandrine Bouchelkia.
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Revision note.
The disappearing cross experiment.
Na 2 S 2 O 3 (aq) + 2HCl (aq) → 2NaCl (aq) + H 2 O (l) + SO 2 (g) + S (s)
Dilution of sodium thiosulfate solution table
) | ) | |
10 | 40 | 0.2 |
20 | 30 | 0.4 |
30 | 20 | 0.6 |
40 | 10 | 0.8 |
50 | 0 | 1.0 |
Diagram showing the apparatus needed to investigate reaction rate in the disappearing cross experiment
Specimen Results
0.2 | 115.2 |
0.4 | 57.6 |
0.6 | 30.0 |
0.8 | 15.6 |
1.0 | 7.2 |
) | |
0.05 | 115.2 |
0.10 | 57.6 |
0.15 | 30.0 |
0.20 | 15.6 |
0.25 | 7.2 |
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When hydrochloric acid (HCl) and sodium thiosulphate (Na 2 S 2 O 3 ) are combined, an interesting reaction takes place and the colourless solution turns opaque. But why does this happen, and how can we use this opacity to determine the rate of reaction?
In this post:
The chemicals used in this experiment are both extremely important in their own areas. In case you missed our previous posts, hydrochloric acid is a strong acid that plays an important role in a range of industries. From regenerating cation exchange resins to neutralising the pH of swimming pools, it is a workhorse chemical that is used in nearly every industry.
Sodium thiosulphate is a chemical that has been classified by the World Health Organisation as one of the most effective and safe medicines needed in the health system. An efflorescent compound that appears as a colourless pentahydrate, sodium thiosulphate is used as a medication for things like cyanide poisoning and pityriasis versicolour.
While these compounds have crucial impacts in their separate applications, when they come together they provide a perfect example of how the rate of a reaction increases, decreases and how it can be measured.
A reaction happens when particles collide, resulting in the reactants getting consumed and new products getting formed. Therefore, in order for a reaction to be successful, the collisions have to have sufficient energy. The greater the number of particles, the more energy these collisions will create. This means that the concentration of the reactants directly affects the energy of a reaction.
With this in mind, the rate of a reaction can be defined as an increase or decrease of concentration in any one of the reactants or final product.
As the concentration of a reactant increases, for example, the number of reacting molecules increases. This means that there is a greater number of collisions which leads to a quicker reaction time and a larger rate of reaction.
Therefore, although there is an inverse relationship between concentration and the rate of a reaction, it is a relationship that is directly proportional. This concept is best demonstrated by the reaction between hydrochloric acid and sodium thiosulphate.
When sodium thiosulphate is added to a solution of hydrochloric acid, an insoluble precipitate of sulphur (S) is formed. Sulphur dioxide (SO 2 ) and water (H 2 O) are also formed, but it is the solid sulphur that has the biggest impact here.
The sulphur is a colloid in this reaction, staying in suspension and eventually blocking the light from reaching the solution. This transforms the solution from being colourless to being milky and entirely opaque. This happens because of the precipitates of elemental sulphur that are being formed, which are insoluble and eventually cloud the water. You can see this by drawing an X on a piece of paper, placing it under your beaker and watching as it begins to disappear.
If the concentration of sodium thiosulphate is high, the solution will cloud fairly quickly (generally between 15-30 seconds). If the concentration of sodium thiosulphate is low, then it will take longer for the reaction to occur. This is how you can measure the rate of the reaction.
The rate of the reaction can be studied by measuring the opaqueness of the solution against the time taken for it to change. Changing the concentration of sodium thiosulphate will change the time it takes for a certain amount of sulphur to form and, therefore, how long it takes for the solution to turn cloudy.
You can lower the concentration of sodium thiosulphate by diluting it with distilled water. This will reduce the number of Na s S 2 O 3 particles which ultimately means fewer collisions. The sulphur precipitates will then appear at a lower rate. This means a longer reaction time and smaller reaction rate.
Comparatively, a reaction that uses a very low concentration of sodium thiosulphate may take up to 5 minutes for the solution to become fully opaque.
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Jasmine Grover
Senior Content Specialist
Rate of reaction plays a significant role in the chemical reaction because it tells us the speed of the reaction. Rate of reaction is referred to as the speed with which reactants are converted into products at a given time. In other words, rate of reaction is defined as the change in concentration of reactants or products per unit time. There are many factors which affect the rate of reaction such as the nature of the reactant, presence of catalyst, presence of radiation, surface area of the reactants, temperature etc. One such factor is the concentration which is directly proportional to the rate of reaction.
Read More : Concepts in Chemistry
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Key Terms: Rate of Reaction, Reactants, Products, Catalyst, Concentration, Sodium Thiosulphate, Hydrochloric Acid
[Click Here for Sample Questions]
To study the effect of concentration on the rate of reaction between sodium thiosulphate and hydrochloric acid.
The materials/ apparatus used in the given experiment are as follows:
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The effect of concentration on the reaction rate is governed by the law of mass action . As per this law, the rate of reaction is directly proportional to the product of molar concentration of the reactants. Moreover, with the increase or decrease in the concentration of the reactants the rate of reaction increases or decreases. When sodium thiosulphate reacts with hydrochloric acid then it forms the elemental sulphur accompanied by the evolution of sulphur dioxide gas. The reaction that takes place is written as follows:
Na 2 S 2 O 3 (aq) + 2HCL (aq) \(\rightarrow\) 2NaCl (aq) + SO 2 (g) + H 2 O (l) + S (s)
Furthermore, the rate of disappearance or consumption of sodium thiosulphate (Na 2 S 2 O 3 ) or the rate of precipitation of elemental sulphur tells us the rate of reaction. It is more convenient to determine the reaction by the rate of precipitation of sulphur which imparts the turbidity to the reaction mixture. Also, the rate of reaction can be studied by measuring the time taken to form enough sulphur to make some mark invisible on the paper, kept under the conical flask in which the reaction is carried out. Therefore, with the increase in the concentration of the reacting species, the rate of precipitation of sulphur also rises. As a result, the molecular collisions per unit time of reactants increase which increases the chances of product formation. If the product formation increases then the rate of reaction will also increase.
To determine the effect of concentration on rate of reaction follow the given steps:
The readings of the given experiment is recorded in the tabular form so that calculations can be done easily.
Volume of 1M HCl solution added to each conical flask = 10 ml
50 ml | - | t1 |
40 ml | 10 ml | t2 |
30 ml | 20 ml | t3 |
20 ml | 30 ml | t4 |
10 ml | 40 ml | t5 |
From the observation table, it is concluded that the time taken for disappearance of the mark ‘X’ should increase with the decrease in the concentration of sodium thiosulphate solution ( from 50 ml to 10 ml in flask no.1 to no.5 in the same order). The trend is shown below:
t 5 > t 4 > t 3 > t 2 > t 1
The graph between the concentration of the sodium thiosulphate and time taken for the disappearance of the mark 'X’ is plotted as:
From the observation table and trend observed in the time taken for the disappearance of the mark ’X’ , it is clear that the rate of reaction between sodium thiosulphate and hydrochloric acid decreases with the decrease in the concentration of the sodium thiosulphate.
There are some basic precautions that should be followed while performing the experiment:
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Ques. What are the units of the rate of a reaction? (2 marks)
Ans. There are two main units of expressing the rate of reaction. These are:
However, Mol L -1 s -1 is widely used in chemistry.
Ques. Is it possible to determine the rate of reaction for all the reactions? (1 mark)
Ans. No, it is not possible for all the reactions. The rate of reaction for very slow and fast reactions cannot be determined.
Ques. What do you mean by hypo solution? (1 mark)
Ans . An aqueous solution of sodium thiosulphate (Na 2 S 2 O 3 .5H 2 O) is known as hypo solution.
Ques. What is the order of reaction involving reaction between sodium thiosulphate and hydrochloric acid? (3 marks)
Ans. The first order reaction is involved between the sodium thiosulphate and hydrochloric acid. It is because of the lower concentrations of the chemicals.
Na 2 S 2 O 3 (aq) + 2HCl (aq) \(\rightarrow\) 2NaCl (aq) + SO 2 (g) + H 2 O (l) + S (s)
Here, the rate of a reaction is first order with respect to sodium thiosulphate (Na 2 S 2 O 3 (aq)) as well as hydrochloric acid(HCl).
Ques. What is the nature of the rate of a reaction with time? (2 marks)
Ans. The rate of a reaction decreases with the passage of time because concentrations of the reactants are high in the beginning. As the time increases, the concentration of the reactants becomes low which slows down the reaction. As a result, the rate of a reaction goes down with time.
Ques. Why should air-free water be used for preparation of sodium sulphite solution? (2 marks)
Ans. Air free water should be used for preparation of sodium sulphite solution because sodium sulphite is easily oxidised to sulphate by dissolving air in the water. Therefore, air free water should be used to prepare aqueous solution of sodium sulphite.
Ques. Write down the principle involved in the study of the rate of a reaction between sodium thiosulphate and hydrochloric acid? (2 marks)
Ans. In the reaction between sodium thiosulphate and hydrochloric acid, the elemental sulphur i.e. colloidal sulphur is produced which results in the appearance of the turbidity in the solution. Also, it appears as when the cross marked on the paper disappears.
Ques. What do you understand from the rate of a reaction? (3 marks)
Ans. The rate of speed at which the reactants convert into products at a given time is known as the rate of a reaction. It can be represented as;
A \(\rightarrow\) B
where, A refers to the reactant and B refers to the product
Rate of a reaction = Decrease in concentration of A / Time taken
Rate of a reaction = - \(\Delta \) [A] / \(\Delta\) t
Rate of a reaction = Increase in concentration of B / Time taken
Rate of a reaction = + \(\Delta \) B / \(\Delta\) t
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1. write the nernst equation and emf of the following cells at 298 k : (i) mg(s) | mg 2+ (0.001m) || cu 2+ (0.0001 m) | cu(s) (ii) fe(s) | fe 2+ (0.001m) || h + (1m)|h 2 (g)(1bar) | pt(s) (iii) sn(s) | sn 2+ (0.050 m) || h + (0.020 m) | h 2 (g) (1 bar) | pt(s) (iv) pt(s) | br 2 (l) | br - (0.010 m) || h + (0.030 m) | h 2 (g) (1 bar) | pt(s)., 2. discuss briefly giving an example in each case the role of coordination compounds in: biological systems medicinal chemistry analytical chemistry extraction/ metallurgy of metals, 3. how would you account for the following: of the d 4 species, cr 2+ is strongly reducing while manganese(iii) is strongly oxidising. cobalt(ii) is stable in aqueous solution but in the presence of complexing reagents it is easily oxidised. the d 1 configuration is very unstable in ions., 4. name the oxometal anions of the first series of the transition metals in which the metal exhibits the oxidation state equal to its group number., 5. write the mechanism of the following reaction : nbubr+kcn→etoh-h 2 o nbucn , 6. accomplish the following conversions: (i) nitrobenzene to benzoic acid (ii) benzene to m-bromophenol (iii) benzoic acid to aniline (iv) aniline to 2,4,6-tribromofluorobenzene (v) benzyl chloride to 2-phenylethanamine (vi) chlorobenzene to p-chloroaniline (vii) aniline to p-bromoaniline (viii) benzamide to toluene (ix) aniline to benzyl alcohol., subscribe to our news letter.
COMMENTS
2. action of Sodium Thiosulfate and Hydrochloric Acid continuedDiscussionSodium thiosulfate react. ion 1).Na2S2O3(aq) + 2HCl(aq) → S(s) + SO2(g) + 2NaCl(aq) Equation 1The kinetics of the reaction can be analyzed by graphing the. oncentration of Na2S2O3 as a function of both reaction time and 1/time. A plot of concentration versus time gives a ...
Procedure. Put 50 cm 3 of sodium thiosulfate solution in a flask. Measure 5 cm 3 of dilute hydrochloric acid in a small measuring cylinder. Add the acid to the flask and immediately start the clock. Swirl the flask to mix the solutions and place it on a piece of paper marked with a cross. Look down at the cross from above.
The aim of this experiment - Understanding the effect of concentration on the rate of reaction between hydrochloric acid and sodium thiosulphate. Theory: The reaction between Sodium thiosulphate (Na 2 S 2 O 3) and hydrochloric acid (HCl) To produce a colloidal solution of sulphur, where the solution obtained is translucent. The reaction ...
Put 10 cm 3 of sodium thiosulfate solution and 40 cm 3 of water into a conical flask. Measure 5 cm 3 of dilute hydrochloric acid in a small measuring cylinder. Warm the thiosulfate solution in the flask if necessary to bring it to the required temperature. The object is to repeat the experiment five times with temperatures in the range 15-55 °C.
A close up view of the classic experiment between Hydrochloric Acid and Sodium Thiosulfate (producing a sulfur precipitate), with varying concentrations of s...
sodium thiosulfate + hydrochloric acid → sodium chloride + water + sulfur dioxide + sulfur. Na 2 S 2 O 3 (s) + 2HCl ... add 50 cm 3 of dilute sodium thiosulfate solution to a conical flask.
In this video, a series of experiments are used to show the effect of concentration on the rate of reaction between sodium thiosulfate and hydrochloric acid....
Na2S2O3 (aq) + 2HCL (aq) → H2O (l) + SO2 (g)+ 2 NaCl (aq) + S (s) It was observed that in a reaction, with an increase in the concentration of sodium thiosulphate gradually while keeping the concentration of hydrochloric acid constant, the rate of reaction has increased slowly. If "t" is the amount of time taken for the products to form ...
A more detailed experiment. A commonly used experiment to show the effect of concentration on rate is between dilute hydrochloric acid and sodium thiosulfate solution. Na 2 S 2 O 3 (aq) + 2HCl (aq) 2NaCl (aq) + SO 2 (g) + S (s) + H 2 O (l) At this stage, the only place you are likely to come across sodium thiosulfate is in this reaction.
Procedure. Put 50 cm3 of sodium thiosulfate solution in a flask. Measure 5 cm3 of dilute hydrochloric acid in a small measuring cylinder. Add the acid to the flask and immediately start the clock. Swirl the flask to mix the solutions and place it on a piece of paper marked with a cross. Look down at the cross from above.
Vary the concentrations of reactants and measure the time it takes for product to appear.This video is part of the Flinn Scientific Best Practices for Teachi...
avoid contact with the skin. gases escaping from reaction. may damage skin and eyes. place cotton wool at opening of conical flask to minimse gas escape. hot sodium thiosulfate solution. burns to the skin. do not heat above 60°C. sulfur dioxide. irritation to the eyes and lungs, particularly to people with asthma.
The aim for this investigation is to investigate what is the effect of the concentration of sodium thiosulphate (Na2S2O3) on the rate of reaction with Hydrochloric Acid (HCl). In my hypothesis statement, I stated "when the concentration of sodium thiosulphate increasing, the rate of reaction will increase, the less time taken for the „O ...
Transfer the hot sodium thiosulfate into the conical flask. Record the temperature of the hot sodium thiosulfate solution. Measure out 5cm 3 of the hydrochloric acid into the 10 cm 3 measuring cylinder. Place the conical flask onto the cross. Add the hydrochloric acid to the conical flask. Swirl the conical flask to mix the contents, at the ...
The Disappearing 'X' Experiment investigates how a change in concentration of sodium thiosulfate affects the rate at which it reacts with hydrochloric acid. By measuring the time it takes for the ...
The purpose of this demonstration is to investigate the effect of sodium thiosulfate concentration on the rate of reaction of sodium thiosulfate with hydrochloric acid. The reaction, which produces solid sulfur, will be followed by measuring the time needed for the reaction mixture to become opaque. The results will be analyzed graphically to ...
Whether you are introducing collision theory or something more demanding like reaction order, the reaction between sodium thiosulfate—Na 2 S 2 O 3 and hydrochloric acid can provide a consistent, accurate, and engaging opportunity for investigating these topics.. A few weeks ago, I was looking for a new reaction that could be used to investigate how concentration affects reaction time.
In this video, a series of experiments are used to show the effect of temperature on the rate of reaction between sodium thiosulfate and hydrochloric acid.On...
Measure 10 cm 3 of sodium thiosulfate and pour it into the conical flask. Measure 40 cm 3 of distilled water and add it to the conical flask. Place the flask on the black cross. Using a clean measuring cylinder, measure 10 cm 3 of hydrochloric acid. Add the acid to the flask, start the stop clock and swirl.
This experiment can be done for a number of different reactions, but the following reaction is commonly used: Na2S2O3 (aq) + 2HCl (aq) → 2NaCl (aq) + H2O (l) + SO2 (g) + S (s) In this reaction, sodium thiosulphate reacts with hydrochloric acid. The key product in this experiment is the solid sulfur which causes the solution to become opaque.
4. Add 5 cm 3 of the hydrochloric acid and at the same time start the stopclock. 5. Viewing from directly above the flask, note the time taken for the cross marked on the paper to 'disappear' i.e. be obscured by the sulfur precipitating. 6. Repeat the experiment using different concentrations of sodium thiosulfate. 7. Record your results in a ...
When hydrochloric acid and sodium thiosulphate react, the solution turns cloudy. You can measure the rate of the reaction by altering the concentration of sodium thiosulphate and measuring the time it takes for the solution to turn fully opaque. The Reaction. When sodium thiosulphate is added to a solution of hydrochloric acid, an insoluble ...
When sodium thiosulphate reacts with hydrochloric acid then it forms the elemental sulphur accompanied by the evolution of sulphur dioxide gas. The reaction that takes place is written as follows: Na2S2O3 (aq) + 2HCL (aq) → → 2NaCl (aq) + SO2 (g) + H2O (l) + S (s) Furthermore, the rate of disappearance or consumption of sodium thiosulphate ...