29643 The answer is 2. A structure assignment will cause a call to memcpy to be made, or equivalent code emitted if the structure is small enough to make this wasteful and the compiler is clever. However if structures contain pointers then the values of the pointers are overwritten. So you have to be extremely careful not to orphan memory or create peculiar bugs with aliases. -- Free games and programming goodies. I think you are confusing arrays and pointers. Since a.s is an array, a.s[0] to a.s[LONG_ENOUGH-1] are actually stored in the structure and are copied by the assignment. If a.s were just a pointer to memory allocated elsewhere the assignment would just copy the pointer. There is an explicit copy since a.s is an array. If a.s were a pointer there would not be an implicit copy, and Bad Things such as dangling pointers could result. -thomas It is not a bitwise copy, it is a copy of all the elements in the struct. Since b.s was not defined as a pointer, what makes you think an assignment could magically transform it from being an array in to being a pointer? You need to read section 6 of the comp.lang.c FAQ at specifically the questions dealing with whether pointers and arrays are the same thing. It is very rare for C to do things behind your back. Had there been pointers in your struct (which there were not) then after the assignment they would point to the same place as they point in the original struct, and when that place is no longer valid (an automatic that goes out of scope, for example) the pointers are no longer valid. -- Flash Gordon It is not a bitwise copy, it is a copy of all the elements in the struct. Since b.s was not defined as a pointer, what makes you think an assignment could magically transform it from being an array in to being a pointer? You need to read section 6 of the comp.lang.c FAQ at specifically the questions dealing with whether pointers and arrays are the same thing. Its easy to see where the confusion comes from. There are situations where pointers degenerate into pointers , the OP probably had that in mind Pointers always degenerate into pointers. -- Richard Heathfield <http://www.cpax.org.uk > Email: -www. +rjh@ Google users: <http://www.cpax.org.uk/prg/writings/googly.php> "Usenet is a strange place" - dmr 29 July 1999 <snip> Since b.s was not defined as a pointer, what makes you think an assignment could magically transform it from being an array in to being a pointer? You need to read section 6 of the comp.lang.c FAQ at specifically the questions dealing with whether pointers and arrays are the same thing. Its easy to see where the confusion comes from. There are situations where pointers degenerate into pointers , the OP probably had that in mind In my opinion it is only easy to confuse arrays and pointers if it is badly taught. If arrays and pointers are taught as fundamentally different concepts and *then* the way array names degenerate to pointers to the first element is explained there will not be anything like the problems. In one-to-one sessions I've been able to explain the basics of arrays pointers to non-computer people in minutes (I needed to so I could explain approximately what was the cause of a problem), although I did not go on to how things are done in C. -- Flash Gordon It is not a bitwise copy, it is a copy of all the elements in the struct. Yes -- and that can be, and commonly is, implemented as a bitwise copy of the struct. Suppose there's a gap between the members "i" and "s". After the assignment "b = a;", the gaps in "a" and "b" may or may not have the same contents. The assignment can be done either as a bitwise copy or by copying the members one-by-one, leaving any gaps alone. 99% of the type, this doesn't matter because you're never going to look at what's in the gaps anyway. -- Keith Thompson (The_Other_Keit h) <http://www.ghoti.net/~kst> San Diego Supercomputer Center <* <http://users.sdsc.edu/~kst> "We must do something. This is something. Therefore, we must do this." -- Antony Jay and Jonathan Lynn, "Yes Minister" Pointers always degenerate into pointers. No they don't, they stay as pointers ;-) Knowing what Serve Lau must have intended I read it as "where arrays degenerate...". -- Flash Gordon Pointers always degenerate into pointers. No they don't, they stay as pointers ;-)
Knowing what Serve Lau must have intended I read it as "where arrays degenerate...". I know. Actually, arrays never actually do that. We often say they do, but we're just being lazy. What we really mean is that the name of an array, when used in an expression, is often (indeed, *usually*) treated as if it were a pointer to the array's first element. The array itself never "degenerate s" (or "decays", as it is usually put) at all. -- Richard Heathfield <http://www.cpax.org.uk > Email: -www. +rjh@ Google users: <http://www.cpax.org.uk/prg/writings/googly.php> "Usenet is a strange place" - dmr 29 July 1999 | | | | | | last post by: | | | last post by: | | last post by: | | last post by: | | last post by: | | last post by: | | last post by: | | | last post by: | | last post by: | | last post by: | By using Bytes.com and it's services, you agree to our Privacy Policy and Terms of Use . To disable or enable advertisements and analytics tracking please visit the manage ads & tracking page. Next: Unions , Previous: Overlaying Different Structures , Up: Structures [ Contents ][ Index ] 15.13 Structure AssignmentAssignment operating on a structure type copies the structure. The left and right operands must have the same type. Here is an example: Notionally, assignment on a structure type works by copying each of the fields. Thus, if any of the fields has the const qualifier, that structure type does not allow assignment: See Assignment Expressions . When a structure type has a field which is an array, as here, structure assigment such as r1 = r2 copies array fields’ contents just as it copies all the other fields. This is the only way in C that you can operate on the whole contents of a array with one operation: when the array is contained in a struct . You can’t copy the contents of the data field as an array, because would convert the array objects (as always) to pointers to the zeroth elements of the arrays (of type struct record * ), and the assignment would be invalid because the left operand is not an lvalue. - Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers
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Collectives™ on Stack OverflowFind centralized, trusted content and collaborate around the technologies you use most. Q&A for work Connect and share knowledge within a single location that is structured and easy to search. Get early access and see previews of new features. Assignment of fields/properties in a struct [duplicate]Possible Duplicate: Modify Struct variable in a Dictionary Why is it that Works great, but Shows a "Cannot modify the expression because it is not a variable" error at compile time? Why is different about the assignment in these two cases? Note: MyDictionary is of type <int, MyStruct> Code for the struct: - @Zabba, edited for more code. – soandos Commented Sep 2, 2011 at 4:19
- Here is the same question stackoverflow.com/questions/6255305/… Jon Skeet already answered. Looks like exact duplicate. – Valentin Kuzub Commented Sep 2, 2011 at 4:30
- Flagged for deletion (I can't do it as there are answers) – soandos Commented Sep 2, 2011 at 4:35
2 Answers 2Because MyDictionary[key] returns a struct, it is really returning a copy of the object in the collection, not the actual object which is what happens when you use a class. This is what the compiler is warning you about. To work around this, you'll have to re-set MyDictionary[key] after the changes to the object, perhaps like this: - But then I would need to call the whole constructor again no? There is no way to change part of a struct in this situation? – soandos Commented Sep 2, 2011 at 4:29
- I modified my example to reuse the same object instead of creating a new one. – Keith Commented Sep 2, 2011 at 4:32
- 3 @soandos struct is always copied when passed between methods, so "whole constructor" is happening all the time (for example when you access your struct by key in that dict), thats why its recommended not to have struct bigger than 16 bytes – Valentin Kuzub Commented Sep 2, 2011 at 4:35
- Pretty sure I am at 11 bytes. – soandos Commented Sep 2, 2011 at 4:47
Change the struct to be a class instead... - I know structs are more efficient when dealing with several objects that basically contain fields like your struct but if you happen to just instantiate a few objects then creating a class will save you some lines of code :) – Tono Nam Commented Sep 2, 2011 at 4:45
- When using an exposed-field struct with built-in collections other than arrays, one must copy the struct, modify it, and then store it back. A nuisance, but the semantics are predictable; dic[1].Isclosed will always be independent of dic[0].Isclosed . Saying dic[0] = dic[1]; will copy the state of dic[0] without attaching the two items together. If one uses a mutable class, one can write dic[1].Isclosed = true; but that doesn't mean doing so will yield the desired behavior. An object which encapsulates its state in the states of mutable objects held in a collection must ... – supercat Commented Sep 17, 2012 at 23:34
- ...generally avoid letting any references to the objects in question reach outside code. This means defensively copying any incoming data to be stored in the collection, and either defensively copying or wrapping any data read from it. Structs automatically perform defensive copying when reading or writing data, but the copy operations on a struct of any size are much cheaper than such operations on a class of the same size. The difference in cost is greatest for small structs, but remains significant until structs get very big. – supercat Commented Sep 17, 2012 at 23:40
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4. Yes, you can assign one instance of a struct to another using a simple assignment statement. In the case of non-pointer or non pointer containing struct members, assignment means copy. In the case of pointer struct members, assignment means pointer will point to the same address of the other pointer.
structure assigment such as r1 = r2 copies array fields' contents just as it copies all the other fields. This is the only way in C that you can operate on the whole contents of a array with one operation: when the array is contained in a struct. You can't copy the contents of the data field as an array, because. would convert the array ...
To access the structure, you must create a variable of it. Use the struct keyword inside the main() method, followed by the name of the structure and then the name of the structure variable: Create a struct variable with the name "s1": struct myStructure {. int myNum; char myLetter; }; int main () {. struct myStructure s1;
In this tutorial, you'll learn about struct types in C Programming. You will learn to define and use structures with the help of examples. In C programming, a struct (or structure) is a collection of variables (can be of different types) under a single name. ... and we cannot use the assignment operator = with it after we have declared the ...
If a struct defines at least one named member, it is allowed to additionally declare its last member with incomplete array type. When an element of the flexible array member is accessed (in an expression that uses operator . or -> with the flexible array member's name as the right-hand-side operand), then the struct behaves as if the array member had the longest size fitting in the memory ...
The assignment operator works with structures. Used with structure operands, the assignment operator copies a block of bits from one memory address (the address of the right-hand object) to another (the address of the left-hand object). C++ code defining a new structure object and copying an existing object to it by assignment.
Structures in C - A structure in C is a derived or user-defined data type. We use the keyword struct to define a custom data type that groups together the elements of different types. ... You can also use the assignment operator (=) to assign the value of the member of one structure to another. Let's have two struct book variables, book1 and book2.
Example of Structure in C. In this example, we have created a structure StudentData with three data members stu_name, stu_id and stu_age. In this program, we are storing the student name, id and age into the structure and accessing structure data members to display these values as an output. #include <stdio.h> /* Created a structure here.
C struct Examples. Store information of a student using structure. Add two distances (in inch-feet) Add two complex numbers by passing structures to a function. Calculate the difference between two time periods. Store information of 10 students using structures. Store information of n students using structures. Share on:
The structure in C is a user-defined data type that can be used to group items of possibly different types into a single type. The struct keyword is used to define the structure in the C programming language. The items in the structure are called its member and they can be of any valid data type. Additionally, the values of a structure are stored in contiguous memory locations.
Assignment performs implicit conversion from the value of rhs to the type of lhs and then replaces the value in the object designated by lhs with the converted value of rhs . Assignment also returns the same value as what was stored in lhs (so that expressions such as a = b = c are possible). The value category of the assignment operator is non ...
Pointers to Structs. Part 1 contains C basics, including functions, static arrays, I/O. Links to other C programming Resources. C Stucts and Pointers. This is the second part of a two part introduction to the C programming language. It is written specifically for CS31 students. The first part covers C programs, compiling and running, variables ...
When initializing a struct, the first initializer in the list initializes the first declared member (unless a designator is specified) (since C99), and all subsequent initializers without designators (since C99) initialize the struct members declared after the one initialized by the previous expression.
printf("weight: %f", personPtr->weight); return 0; } Run Code. In this example, the address of person1 is stored in the personPtr pointer using personPtr = &person1;. Now, you can access the members of person1 using the personPtr pointer. By the way, personPtr->age is equivalent to (*personPtr).age. personPtr->weight is equivalent to ...
The answer is 2. A structure assignment will cause a call to memcpy to be made, or equivalent code emitted if the structure is small enough to make this wasteful and the compiler is clever. However if structures contain pointers then the values of the pointers are overwritten.
9) To Compare the structures in Easy plan as like RAC, login to Easy Plan with MBOM Workspace. 10) Open CC structure in Easy Plan from Favorites. 11) In EBOM MBOM Alignment page, we can see the Engineering BOM and Manufacturing BOM with Assignment status icon i.e partial match shown for child object.
A series of 1-(4′-halophenyl)-4-(4″-methoxyphenyl)buta-1,3-dienes, (H, MeO, Y)-1,4-diphenylbutadienes with halogens Y = F (1), Cl (2), Br (3), and I (4) are described. Crystal structure analysis establishes that 1-4 present a new class of highly dipole parallel-aligned polar organic molecular materials for nonlinear optics (NLO). Building on previous studies of polar crystals of ...
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structure assigment such as r1 = r2 copies array fields' contents just as it copies all the other fields. This is the only way in C that you can operate on the whole contents of a array with one operation: when the array is contained in a struct. You can't copy the contents of the data field as an array, because.
memcpy(test->mem, temporary, sizeof temporary); Regarding the edit to the question: Arrays may not be assigned; x = value is not valid if x is an array. However, structures may be assigned, so another alternative is to create a structure as a temporary object, initialize it, and assign it: // (After the malloc is successful.) static const Test ...
Medicare's new power to negotiate drug prices will lead to an estimated $6 billion in savings for the federal government and a $1.5 billion reduction in out-of-pocket costs for seniors when the ...
1. The struct name for a struct containing a fixed-length array is treated as a contiguous object and therefore assignable, while an array name is interpreted as the address of the first element except in the case where it is the operand of the sizeof operator and unary & operator. edited Mar 3, 2016 at 1:41.
When using an exposed-field struct with built-in collections other than arrays, one must copy the struct, modify it, and then store it back. A nuisance, but the semantics are predictable; dic[1].Isclosed will always be independent of dic[0].Isclosed.Saying dic[0] = dic[1]; will copy the state of dic[0] without attaching the two items together. If one uses a mutable class, one can write dic[1 ...